在Android中解析嵌套的JSONObject [重复]
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【中文标题】在Android中解析嵌套的JSONObject [重复]【英文标题】：Parsing nested JSONObject in Android [duplicate] 【发布时间】：2015-07-05 12:24:38 【问题描述】：在我的项目中，我从 HTTP 响应中获取了以下 JSON。
"base":"USD","date":"2015-04-24","rates":"AUD":1.2827,"BGN":1.8069,"BRL":2.9733,"CAD":1.2119,"CHF":0.9551,"CNY":6.1948,"CZK":25.364,"DKK":6.8927,"GBP":0.6614,"HKD":7.75,"HRK":7.0284,"HUF":278.53,"IDR":12954.0,"ILS":3.9244,"INR":63.563,"JPY":119.51,"KRW":1078.25,"MXN":15.358,"MYR":3.5741,"NOK":7.8298,"NZD":1.3216,"php":44.281,"PLN":3.7076,"RON":4.08,"RUB":51.215,"SEK":8.6674,"SGD":1.3375,"THB":32.55,"TRY":2.7314,"ZAR":12.182,"EUR":0.9239
我想从上面的 json 中获取“BGN”。如何获得。
【问题讨论】：
试试这个：***.com/questions/9605913/… 【参考方案1】：这涉及多个步骤
首先：创建一个jsonObject
JSONObject jObject = new JSONObject(yourJSON_String);
第二：获取你想要的对象或数组，在你的情况下
obj = getJSONObject("rates")
第三：获取所需的字符串
obj.getString("BGN");
这里是JSON CLASS REFERENCE
【讨论】：
【参考方案2】：假设您使用的是 JSONObject，并且您的根文档称为“doc”，
JSONObject rates = doc.getJSONObject("rates") 将为您提供费率部分：
"AUD":1.2827,"BGN":1.8069,"BRL":2.9733,"CAD":1.2119,"CHF":0.9551,"CNY":6.1948,"CZK":25.364,"DKK":6.8927,"GBP":0.6614,"HKD":7.75,"HRK":7.0284,"HUF":278.53,"IDR":12954.0,"ILS":3.9244,"INR":63.563,"JPY":119.51,"KRW":1078.25,"MXN":15.358,"MYR":3.5741,"NOK":7.8298,"NZD":1.3216,"PHP":44.281,"PLN":3.7076,"RON":4.08,"RUB":51.215,"SEK":8.6674,"SGD":1.3375,"THB":32.55,"TRY":2.7314,"ZAR":12.182,"EUR":0.9239
从此对象中，您可以使用
简单地获取 BGN 值String bgn = rates.getString("BGN")
【讨论】：
【参考方案3】：JSONObject responseJson = new JSONObject("<your-string">);
JSONObject ratesJson = responseJson.getJSONObject("rates");
double rate = ratesJson.getDouble("BGN");
要清楚地看到JSON 对象，请使用PrettyJson。在此处复制粘贴 JSON 字符串，它将显示嵌套对象（如果有），以便清楚地理解响应。
【讨论】：
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