使用 XSLT 从 XML 中删除 xmlns

Posted 2023-04-12

【中文标题】使用 XSLT 从 XML 中删除 xmlns

【英文标题】：Remove xmlns from XML using XSLT

【发布时间】：2015-11-16 10:32:12

【问题描述】：

我有一个如下所示的 XML，并希望从请求中删除 SOAP 信封和正文并生成如下。

当前 XML

<?xml version="1.0" encoding="utf-8"?>
 <soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
<soap:Body>
<AsnPODetailsRequest>
<AsnPODetails>
    <RequestSourcedFrom>EDI</RequestSourcedFrom>
    <ValidationLevelInd></ValidationLevelInd>
    <AdvanceShipmentNotificationId></AdvanceShipmentNotificationId>
    <PoAttributeList>
        <PoAttribute>
            <Department></Department>
            <FreightTerms></FreightTerms>
            <Location></Location>
            <LocationType></LocationType>
            <MFOrderNo>MOMILQ</MFOrderNo>
            <NotBeforeDate>2014-06-24 01:21:36</NotBeforeDate>
            <PurchaseOrderType></PurchaseOrderType>
            <RetekPurchaseOrderNo></RetekPurchaseOrderNo>
            <sku></sku>
            <Status></Status>
            <Supplier></Supplier>
            <SupplierDesc></SupplierDesc>
            <upc></upc>
            <VendorOrderNo></VendorOrderNo>
        </PoAttribute>
        <PoAttribute>
        <Department></Department>
        <FreightTerms></FreightTerms>
        <Location></Location>
        <LocationType></LocationType>
        <MFOrderNo>MOMILN</MFOrderNo>
        <NotBeforeDate>2014-06-24 01:21:36</NotBeforeDate>
        <PurchaseOrderType></PurchaseOrderType>
        <RetekPurchaseOrderNo></RetekPurchaseOrderNo>
        <sku></sku>
        <Status></Status>
        <Supplier></Supplier>
        <SupplierDesc></SupplierDesc>
        <upc></upc>
        <VendorOrderNo></VendorOrderNo>
        </PoAttribute>
    </PoAttributeList>
    </AsnPODetails>
   </AsnPODetailsRequest>
  </soap:Body>
 </soap:Envelope>

所需的 XML：

<?xml version="1.0" encoding="utf-8"?>
<AsnPODetailsRequest>
<AsnPODetails>
    <RequestSourcedFrom>EDI</RequestSourcedFrom>
    <ValidationLevelInd></ValidationLevelInd>
    <AdvanceShipmentNotificationId></AdvanceShipmentNotificationId>
    <PoAttributeList>
        <PoAttribute>
            <Department></Department>
            <FreightTerms></FreightTerms>
            <Location></Location>
            <LocationType></LocationType>
            <MFOrderNo>MOMILQ</MFOrderNo>
            <NotBeforeDate>2014-06-24 01:21:36</NotBeforeDate>
            <PurchaseOrderType></PurchaseOrderType>
            <RetekPurchaseOrderNo></RetekPurchaseOrderNo>
            <sku></sku>
            <Status></Status>
            <Supplier></Supplier>
            <SupplierDesc></SupplierDesc>
            <upc></upc>
            <VendorOrderNo></VendorOrderNo>
        </PoAttribute>
        <PoAttribute>
        <Department></Department>
        <FreightTerms></FreightTerms>
        <Location></Location>
        <LocationType></LocationType>
        <MFOrderNo>MOMILN</MFOrderNo>
        <NotBeforeDate>2014-06-24 01:21:36</NotBeforeDate>
        <PurchaseOrderType></PurchaseOrderType>
        <RetekPurchaseOrderNo></RetekPurchaseOrderNo>
        <sku></sku>
        <Status></Status>
        <Supplier></Supplier>
        <SupplierDesc></SupplierDesc>
        <upc></upc>
        <VendorOrderNo></VendorOrderNo>
        </PoAttribute>
    </PoAttributeList>
    </AsnPODetails>
  </AsnPODetailsRequest>

我正在使用下面的 XSLT

<xsl:stylesheet version="1.0" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:output encoding="UTF-8" indent="yes" method="xml" version="1.0"/>
  <xsl:strip-space elements="*"/>

 <!-- identity transform -->
 <xsl:template match="@*|node()">
<xsl:copy>
    <xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>

<xsl:template match="soap:Envelope | soap:Body">
  <xsl:apply-templates select="@*|node()"/>
</xsl:template>
</xsl:stylesheet>

但它没有删除行 xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"。它只去除肥皂：信封和肥皂：身体。有谁能帮我写一个 XSLT 来按我的要求删除标签吗？

【参考方案1】：

使用 XSLT 2.0，您可以将身份转换编写为

<xsl:template match="@*|node()">
  <xsl:copy copy-namespaces="no">
    <xsl:apply-templates select="@*|node()"/>
  </xsl:copy>
</xsl:template>

见http://xsltransform.net/jyH9rNm。

或者，对于 XSLT 1.0，您需要使用

<xsl:template match="*">
  <xsl:element name="name()" namespace="namespace-uri()">
    <xsl:apply-templates select="@*|node()"/>
  </xsl:element>
</xsl:template>

以确保在范围内的名称空间（如肥皂名称空间）不会被复制。在样式表中，我会将xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" 移动到

<xsl:template xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" match="soap:Envelope | soap:Body">
  <xsl:apply-templates select="@*|node()"/>
</xsl:template>

或在xsl:stylesheet 上添加exclude-result-prefixes="soap"。见http://xsltransform.net/nc4NzRo。

【讨论】：

请注意：如果要复制的节点是名称空间中的元素节点，@copy-namespaces 仍将复制名称空间。它只是删除未使用的命名空间，当然，强制命名空间作为the namespace fixup process 的一部分保留。