R数据存储在一个数据框列的两个列表中，想要创建单独的列
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【中文标题】R数据存储在一个数据框列的两个列表中，想要创建单独的列【英文标题】：R data stored in two lists on one dataframe column, want to create individual columns 【发布时间】：2020-11-09 01:59:34 【问题描述】：来自 json 文件的 R 数据以列表形式存储在 'rounds' 列中。
> head(leaderboard[,20:22])
round rounds strokes
1 -5 r1, r2, r3, r4, 67, 68, 67, 65 267
2 -7 r1, r2, r3, r4, 70, 70, 66, 63 269
3 -5 r1, r2, r3, r4, 72, 66, 66, 65 269
4 -7 r1, r2, r3, r4, 68, 69, 71, 63 271
5 -5 r1, r2, r3, r4, 72, 70, 65, 65 272
6 -1 r1, r2, r3, r4, 68, 69, 66, 69 272
> leaderboard$rounds[[1]]
title strokes
1 r1 67
2 r2 68
3 r3 67
4 r4 65
我想把上面的数据做成这样：
round r1 r2 r3 r4 strokes
-5 67 68 67 65 267
-7 70 70 66 63 269
dput 函数的输出：
> dput(head(leaderboard[,20:22]))
structure(list(round = c("-5", "-7", "-5", "-7", "-5", "-1"),
rounds = list(structure(list(title = c("r1", "r2", "r3",
"r4"), strokes = c("67", "68", "67", "65")), class = "data.frame", row.names = c(NA,
4L)), structure(list(title = c("r1", "r2", "r3", "r4"), strokes = c("70",
"70", "66", "63")), class = "data.frame", row.names = c(NA,
4L)), structure(list(title = c("r1", "r2", "r3", "r4"), strokes = c("72",
"66", "66", "65")), class = "data.frame", row.names = c(NA,
4L)), structure(list(title = c("r1", "r2", "r3", "r4"), strokes = c("68",
"69", "71", "63")), class = "data.frame", row.names = c(NA,
4L)), structure(list(title = c("r1", "r2", "r3", "r4"), strokes = c("72",
"70", "65", "65")), class = "data.frame", row.names = c(NA,
4L)), structure(list(title = c("r1", "r2", "r3", "r4"), strokes = c("68",
"69", "66", "69")), class = "data.frame", row.names = c(NA,
4L))), strokes = c("267", "269", "269", "271", "272", "272"
)), row.names = c(NA, 6L), class = "data.frame")
【问题讨论】：
如果我们可以重新创建数据结构会更容易提供帮助：请您复制/粘贴来自dput(head(leaderboard[, 20:22])) 的输出。
是的，我已经编辑过原文
【参考方案1】：
你可以使用：
library(dplyr)
library(tidyr)
leaderboard %>%
rename(new_strokes = strokes) %>%
unnest(rounds) %>%
pivot_wider(names_from = title, values_from = strokes)
# round new_strokes r1 r2 r3 r4
# <chr> <chr> <chr> <chr> <chr> <chr>
#1 -5 267 67 68 67 65
#2 -7 269 70 70 66 63
#3 -5 269 72 66 66 65
#4 -7 271 68 69 71 63
#5 -5 272 72 70 65 65
#6 -1 272 68 69 66 69
【讨论】：
【参考方案2】：这是tidyverse 方法
library(dplyr)
library(tidyr)
leaderboard %>% mutate(rounds = lapply(rounds, pivot_wider, names_from = "title", values_from = "strokes")) %>% unnest(rounds)
输出
# A tibble: 6 x 6
round r1 r2 r3 r4 strokes
<chr> <chr> <chr> <chr> <chr> <chr>
1 -5 67 68 67 65 267
2 -7 70 70 66 63 269
3 -5 72 66 66 65 269
4 -7 68 69 71 63 271
5 -5 72 70 65 65 272
6 -1 68 69 66 69 272
【讨论】：
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