Oracle SQL - 来自/来自带有日期的表的日期
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【中文标题】Oracle SQL - 来自/来自带有日期的表的日期【英文标题】:Oracle SQL - Dates from/to from a table with dates 【发布时间】:2021-02-11 14:45:23 【问题描述】:我有一个问题,我不知道最好的解决方法是什么:
我有以下信息:
PRODUCT | IS_BUY | DATE |
---|---|---|
A | 1 | 01/01/2021 |
A | 1 | 02/01/2021 |
A | 1 | 03/01/2021 |
A | 0 | 04/01/2021 |
A | 1 | 05/01/2021 |
A | 1 | 06/01/2021 |
B | 1 | 01/01/2021 |
C | 1 | 01/01/2021 |
C | 0 | 02/01/2021 |
C | 0 | 03/01/2021 |
C | 1 | 04/01/2021 |
我需要将以下结果留在每个产品存在或不购买的日期之间的位置:
PRODUCT | IS_BUY | FROM_DATE | TO_DATE |
---|---|---|---|
A | 1 | 01/01/2021 | 04/01/2021 |
A | 0 | 04/01/2021 | 05/01/2021 |
A | 1 | 05/01/2021 | null |
B | 1 | 01/01/2021 | null |
C | 1 | 01/01/2021 | 02/01/2021 |
C | 0 | 02/01/2021 | 04/01/2021 |
C | 1 | 04/01/2021 | null |
感谢您的帮助!
【问题讨论】:
请注意:Oracle SQL 不称为“PL/SQL”。 PL/SQL 是完全不同的东西。我不会告诉你它是什么——我相信你可以使用谷歌搜索来找出答案。我相应地更改了您的标签(以及您的问题的标题)。 【参考方案1】:您没有告诉我们您的 Oracle 版本。下面我将展示两个解决方案:第一个是更高级的,使用 Oracle 12.1 中添加的 match_recognize
子句,然后是旧的方法,使用 Tabibitosan 方法解决间隙和岛屿问题(您的问题所属的类到)。
数据设置:
create table my_data (product, is_buy, eff_date) as
select 'A', 1, to_date('01/01/2021', 'mm/dd/yyyy') from dual union all
select 'A', 1, to_date('02/01/2021', 'mm/dd/yyyy') from dual union all
select 'A', 1, to_date('03/01/2021', 'mm/dd/yyyy') from dual union all
select 'A', 0, to_date('04/01/2021', 'mm/dd/yyyy') from dual union all
select 'A', 1, to_date('05/01/2021', 'mm/dd/yyyy') from dual union all
select 'A', 1, to_date('06/01/2021', 'mm/dd/yyyy') from dual union all
select 'B', 1, to_date('01/01/2021', 'mm/dd/yyyy') from dual union all
select 'C', 1, to_date('01/01/2021', 'mm/dd/yyyy') from dual union all
select 'C', 0, to_date('02/01/2021', 'mm/dd/yyyy') from dual union all
select 'C', 0, to_date('03/01/2021', 'mm/dd/yyyy') from dual union all
select 'C', 1, to_date('04/01/2021', 'mm/dd/yyyy') from dual
;
(顺便说一下,这是在您的帖子中包含示例数据的首选方式!)
注意date
是保留关键字;我将列名更改为eff_date
。
第一个解决方案,使用match_recognize
匹配数据中的模式:
select product, is_buy, eff_date, end_date
from my_data
match_recognize(
partition by product
order by eff_date
measures a.is_buy as is_buy,
a.eff_date as eff_date,
next(eff_date) as end_date
pattern ( a b* )
define b as is_buy = a.is_buy
);
PRODUCT IS_BUY EFF_DATE END_DATE
------- ------ ---------- ----------
A 1 01/01/2021 04/01/2021
A 0 04/01/2021 05/01/2021
A 1 05/01/2021
B 1 01/01/2021
C 1 01/01/2021 02/01/2021
C 0 02/01/2021 04/01/2021
C 1 04/01/2021
第二种解决方案,仅使用解析函数和聚合(Tabibitosan 方法):
with prep as (
select product, is_buy, eff_date,
lead(eff_date) over (partition by product
order by eff_date) as next_date,
row_number() over (partition by product order by eff_date) -
row_number() over (partition by product, is_buy order by eff_date)
as grp
from my_data
)
select product, is_buy, min(eff_date) as eff_date,
max(next_date) keep (dense_rank last order by eff_date) as end_date
from prep
group by product, is_buy, grp
order by product, eff_date
;
【讨论】:
【参考方案2】:试试这个
Select
Product,
Is_Buy,
(select min(x.DATE) from products x where x.product=a.product and x.is_buy=a.is_buy) from_date,
(select max(x.DATE) from products x where x.product=a.product and x.is_buy=a.is_buy) to_date,
from products a
group by a.Product, a.Is_Buy
【讨论】:
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