PL/SQL - XML Clob 错误
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【中文标题】PL/SQL - XML Clob 错误【英文标题】:PL/SQL - XML clob error 【发布时间】:2017-11-17 21:22:27 【问题描述】:我正在尝试测试一个以 xml CLOB 作为参数的 PL/SQL 过程
PROCEDURE example_proc(ex_xml CLOB) IS
BEGIN
/* Find the second < (skip over declaration) */
ln_position := instr(pc_shipment_xml, '<', 1, 2);
/* Find the space after the first tag */
ln_position := instr(pc_shipment_xml, ' ', ln_position, 1);
/* Set the first part of the XML clob */
lc_shipment_xml := substr(pc_shipment_xml, 1, ln_position - 1);
/* Skip the namespace */
ln_position := instr(pc_shipment_xml, '>', ln_position, 1);
lc_shipment_xml := lc_shipment_xml || substr(pc_shipment_xml, ln_position);
/* Set the XML type */
lx_shipment_xml := xmltype(lc_shipment_xml); --RIGHT HERE IS WHERE IT ERRORS OUT
这是我传入的 xml(作为 ex_xml clob 参数):
xml :=
'<Shipment>
<OrderNumber>00000</OrderNumber>
<ShipmentLines>
<ShipmentLine>
<OrderDetailId>000000</OrderDetailId>
<LineNumber>0</LineNumber>
<ItemId>00000</ItemId>
<UnitId>0000000</UnitId>
<BaseUom>X</BaseUom>
<Quantity1>000</Quantity1>
</ShipmentLine>
</ShipmentLines>
</Shipment>';
它在最后一行出错:
ORA-19202: Error occurred in XML processing
LPX-002255: end-element tag "ShipmentLines" does not match start-element tag "Shipment"
请原谅我的无知,但这是我第一次在 PL/SQ 中使用 XML,我是否遗漏了格式?据我所见,我正在正确打开和关闭我的标签。任何意见都表示赞赏。
【问题讨论】:
您真的尝试使用instr
、substr
等修改XML 文档吗?看看XML Functions
【参考方案1】:
运行你的代码
declare
pc_shipment_xml CLOB := '<Shipment>
<OrderNumber>00000</OrderNumber>
<ShipmentLines>
<ShipmentLine>
<OrderDetailId>000000</OrderDetailId>
<LineNumber>0</LineNumber>
<ItemId>00000</ItemId>
<UnitId>0000000</UnitId>
<BaseUom>X</BaseUom>
<Quantity1>000</Quantity1>
</ShipmentLine>
</ShipmentLines>
</Shipment>';
lc_shipment_xml varchar2(2000);
ln_position integer;
BEGIN
/* Find the second < (skip over declaration) */
ln_position := instr(pc_shipment_xml, '<', 1, 2);
/* Find the space after the first tag */
ln_position := instr(pc_shipment_xml, ' ', ln_position, 1);
/* Set the first part of the XML clob */
lc_shipment_xml := substr(pc_shipment_xml, 1, ln_position - 1);
/* Skip the namespace */
ln_position := instr(pc_shipment_xml, '>', ln_position, 1) + 1;
lc_shipment_xml := lc_shipment_xml || substr(pc_shipment_xml, ln_position);
dbms_output.put_line(lc_shipment_xml);
end;
/
给出以下输出:
<Shipment>
<OrderNumber>00000</OrderNumber>
<ShipmentLine>
<OrderDetailId>000000</OrderDetailId>
<LineNumber>0</LineNumber>
<ItemId>00000</ItemId>
<UnitId>0000000</UnitId>
<BaseUom>X</BaseUom>
<Quantity1>000</Quantity1>
</ShipmentLine>
</ShipmentLines>
</Shipment>
所以看起来您正在剥离开始 ShipmentLines 标记,而不是结束标记
如果您知道要删除的标签的名称,则可以更简单地使用
lc_shipment_xml := regexp_replace(pc_shipment_xml, '</?ShipmentLines>');
或按位置获取标签:
l_tag := regexp_substr(pc_shipment_xml, '<(\w+)>',1,3,'i',1);
lc_shipment_xml := regexp_replace(pc_shipment_xml, '</?' || l_tag || '>');
更好的方法是使用 xml 函数,如下所示:
declare
pc_shipment_xml CLOB := '<Shipment>
<OrderNumber>00000</OrderNumber>
<ShipmentLines>
<ShipmentLine>
<OrderDetailId>000000</OrderDetailId>
<LineNumber>0</LineNumber>
<ItemId>00000</ItemId>
<UnitId>0000000</UnitId>
<BaseUom>X</BaseUom>
<Quantity1>000</Quantity1>
</ShipmentLine>
</ShipmentLines>
</Shipment>';
lx_shipment_xml xmltype := xmltype(pc_shipment_xml);
lx_shipline_xml xmltype := xmltype(pc_shipment_xml);
lc_shipment_xml varchar2(2000);
BEGIN
/* Set the XML type */
select extract(lx_shipment_xml, '/Shipment/ShipmentLines/ShipmentLine') into lx_shipline_xml from dual;
select deletexml(lx_shipment_xml, '/Shipment/ShipmentLines') into lx_shipment_xml from dual;
select insertxmlafter(lx_shipment_xml, '/Shipment/OrderNumber', lx_shipline_xml) into lx_shipment_xml from dual;
select xmlserialize(content lx_shipment_xml) into lc_shipment_xml from dual;
dbms_output.put_line(lc_shipment_xml);
end;
/
【讨论】:
【参考方案2】:我解析 xml 的方式需要将 <?xml version="1.0"?>
放在 clob 的开头。解析方法不是我自己的代码,所以改变我做的方式不是一个选择。谢谢
【讨论】:
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