为啥我不能从 FragmentPagerAdapter 分离片段？

Posted 2023-02-16

【中文标题】为啥我不能从 FragmentPagerAdapter 分离片段？

【英文标题】：Why cannot I detach fragment from FragmentPagerAdapter?为什么我不能从 FragmentPagerAdapter 分离片段？

【发布时间】：2013-03-02 22:33:10

【问题描述】：

我想从我的 FragmentPagerAdapter 中分离一个片段，但它似乎不起作用。这是我从原始代码中复制的 pageradapter 类：

public class PagerAdapter1 extends FragmentPagerAdapter 

    private List<String> fragments;
       private static final String TAG = "FragmentPagerAdapter";
        private static final boolean DEBUG = true;
        private Fragment mCurrentPrimaryItem = null;
        private final FragmentManager mFragmentManager;
        private FragmentTransaction mCurTransaction = null;

    /**
     * @param fm
     * @param fragments2
     */
    public PagerAdapter1(FragmentManager fm, List<String> fragments2) 
        super(fm);
        mFragmentManager=fm;
        this.fragments = fragments2;
    
    /* (non-Javadoc)
     * @see android.support.v4.app.FragmentPagerAdapter#getItem(int)
     */
    @Override
    public Fragment getItem(int position) 
        //return this.fragments.get(position);
        return Fragment.instantiate(ViewPagerActivity.context, fragments.get(position));

    

    /* (non-Javadoc)
     * @see android.support.v4.view.PagerAdapter#getCount()
     */
    @Override
    public int getCount() 
        return this.fragments.size();
    



      /**
     * Return the Fragment associated with a specified position.
     */


    @Override
    public void startUpdate(ViewGroup container) 
    

    @Override
    public Object instantiateItem(ViewGroup container, int position) 
       Log.i("asasd", "asdasdasdasdasd");

        if (mCurTransaction == null) 
            mCurTransaction = mFragmentManager.beginTransaction();
        

        final long itemId = getItemId(position);

        // Do we already have this fragment?
        String name = makeFragmentName(container.getId(), itemId);

        Fragment fragment = mFragmentManager.findFragmentByTag(name);
        if (fragment != null) 
            if (DEBUG) Log.v(TAG, "Attaching item #" + itemId + ": f=" + fragment);
                mCurTransaction.attach(fragment);

         else 

            fragment = getItem(position);
            if (DEBUG) Log.v(TAG, "Adding item #" + itemId + ": f=" + fragment);
            mCurTransaction.add(container.getId(), fragment,
                    makeFragmentName(container.getId(), itemId));
          //  Log.i("asdJANIANI", " " + getFragmentTag(container.getId(),0));
            //Log.i("JANI", " " + getItem(0));
        

        if (fragment != mCurrentPrimaryItem) 
            fragment.setMenuVisibility(false);
            fragment.setUserVisibleHint(false);
        
        **destroyItem(container,0,getItem(0));**

        return fragment;
    

    @Override
    public void destroyItem(ViewGroup container, int position, Object object) 
        if (mCurTransaction == null) 
            mCurTransaction = mFragmentManager.beginTransaction();
        
        if (DEBUG) Log.v(TAG, "Detaching item #" + getItemId(position) + ": f=" + object
                + " v=" + ((Fragment)object).getView());
        mCurTransaction.detach((Fragment)object);
    

    @Override
    public void setPrimaryItem(ViewGroup container, int position, Object object) 
        Fragment fragment = (Fragment)object;
        if (fragment != mCurrentPrimaryItem) 
            if (mCurrentPrimaryItem != null) 
                mCurrentPrimaryItem.setMenuVisibility(false);
                mCurrentPrimaryItem.setUserVisibleHint(false);
            
            if (fragment != null) 
                fragment.setMenuVisibility(true);
                fragment.setUserVisibleHint(true);
            
            mCurrentPrimaryItem = fragment;
        

        if (position == 0)
            this.notifyDataSetChanged();
        

    

    @Override
    public void finishUpdate(ViewGroup container) 
        if (mCurTransaction != null) 
            mCurTransaction.commitAllowingStateLoss();
            mCurTransaction = null;
            mFragmentManager.executePendingTransactions();
        
    

    @Override
    public boolean isViewFromObject(View view, Object object) 
        return ((Fragment)object).getView() == view;
    

    @Override
    public Parcelable saveState() 
        return null;
    

    @Override
    public void restoreState(Parcelable state, ClassLoader loader) 
    

    /**
     * Return a unique identifier for the item at the given position.
     *
     * <p>The default implementation returns the given position.
     * Subclasses should override this method if the positions of items can change.</p>
     *
     * @param position Position within this adapter
     * @return Unique identifier for the item at position
     */
    public long getItemId(int position) 
        return position;
    

    private static String makeFragmentName(int viewId, long id) 
        return "android:switcher:" + viewId + ":" + id;
    

我只改变了一件事，我在 instantiateItem() 方法中实现了一个destroyItem() 方法，因为我想在每次实例化片段时分离片段（位置 0）。我没有收到任何错误，它只是没有分离。为什么？

提前感谢您！

【问题讨论】：

您是否要完全删除该片段？

以后会用到，所以不想完全删除。

【参考方案1】：

这让我连续忙了两天。我终于在这里找到了答案：

Update ViewPager dynamically?

基本上，不要使用 FragmentPagerAdapter，而是使用 FragmentStatePagerAdapter 并覆盖 getItemPosition() 方法。事实证明，前者不允许对其数据源进行适当的更改，也不会反映它们。

这个该死的错误花费了我大量的时间 :( 但是上面的链接帮助我在几分钟内修复了它。

【参考方案2】：

在FragmentPagerAdapter.java的源码中，

82 @Override83 public Object instantiateItem(ViewGroup container, int 位置) @987654326 @ if (mCurTransaction == null) 85 mCurTransaction = mFragmentManager.beginTransaction();86 @ 987654330@ // 我们已经有这个片段了吗？89 String name = makeFragmentName(container.getId(), position);90 Fragment fragment = mFragmentManager. findFragmentByTag(name);91 if (fragment != null) 92 if ( DEBUG) Log.v(TAG, "Attaching item #" + position + ": f=" + fragment);93 mCurTransaction.attach(fragment);94  else 95 fragment = getItem(position);96 if (DEBUG) Log.v(TAG, "正在添加item #" + position + ": f=" + fragment);97 mCurTransaction .add(container.getId(), 片段,98makeFragmentName(container.getId(), position));99 100 if (fragment != mCurrentPrimaryItem) 101fragment.setMenuVisibility(false);102fragment.setUserVisibleHint(false);103 105 返回片段；106 108@Override109 public void destroyItem(ViewGroup container, int position, Object object) 110 如果 (mCurTransaction == null) 111 mCurTransaction = mFragmentManager.beginTransaction();112 @987654372 @if (DEBUG) Log.v(TAG, "Detaching item #" + position + ": f=" + object114 + " v=" + ((@ 987654375@)object).getView());115 mCurTransaction.detach((Fragment)object);116 

您可以看到它使用附加/分离来显示/隐藏片段。这就是它们不起作用的原因。