如果作者写了多篇文章,为啥这个 SQL 查询将一篇文章的作者姓名返回为 NULL?
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【中文标题】如果作者写了多篇文章,为啥这个 SQL 查询将一篇文章的作者姓名返回为 NULL?【英文标题】:Why is this SQL query returning the author name for an article as NULL, if the author has written more than one article?如果作者写了多篇文章,为什么这个 SQL 查询将一篇文章的作者姓名返回为 NULL? 【发布时间】:2016-12-07 23:21:16 【问题描述】:这是我的创作声明:
String createFeedTable = "CREATE TABLE rss_feed ("
+ "channel_ID INTEGER NOT NULL GENERATED ALWAYS AS IDENTITY (START WITH 1, INCREMENT BY 1), "
+ "channelTitle VARCHAR(255), "
+ "channelLink VARCHAR(255), "
+ "channelDescription VARCHAR(255), "
+ "channelPubDate TIMESTAMP, "
+ "channelLastBuildDate TIMESTAMP,"
+ "channelIcon BLOB(1M),"
+ "PRIMARY KEY (channel_ID))";
String createFeedItemTable = "CREATE TABLE feed_item ("
+ " item_ID INTEGER NOT NULL GENERATED ALWAYS AS IDENTITY (START WITH 1, INCREMENT BY 1),"
+ " itemTitle VARCHAR(255),"
+ " itemLink VARCHAR(255),"
+ " itemDescription VARCHAR(255),"
+ " itemGuid VARCHAR(255),"
+ " itemPubDate TIMESTAMP,"
+ " channel_ID INTEGER REFERENCES rss_feed(channel_ID),"
+ " haveRead BOOLEAN DEFAULT FALSE,"
+ " PRIMARY KEY (item_ID))";
String createCategoryTable = "CREATE TABLE category ("
+ "category_ID INTEGER NOT NULL GENERATED ALWAYS AS IDENTITY (START WITH 1, INCREMENT BY 1),"
+ "categoryName VARCHAR(255), "
+ "CONSTRAINT category_constraint UNIQUE (categoryName),"
+ "PRIMARY KEY (category_ID))";
String createFeedItemCategoryTable = "CREATE TABLE feed_item_category ("
+ " item_ID INTEGER REFERENCES feed_item(item_ID),"
+ " category_ID INTEGER REFERENCES category(category_ID))";
String createFeedCategoryTable = "CREATE TABLE rss_feed_category ("
+ "feed_ID INTEGER REFERENCES rss_feed(channel_ID),"
+ "category_ID INTEGER REFERENCES category(category_ID))";
String createAuthorTable = "CREATE TABLE author ("
+ "author_ID INTEGER NOT NULL GENERATED ALWAYS AS IDENTITY (START WITH 1, INCREMENT BY 1),"
+ "authorName VARCHAR(255),"
+ "CONSTRAINT author_constraint UNIQUE (authorName),"
+ "PRIMARY KEY (author_ID))";
String createFeedItemAuthorTable = "CREATE TABLE feed_item_author ("
+ "item_ID INTEGER REFERENCES feed_item(item_ID),"
+ "author_ID INTEGER REFERENCES author(author_ID))";
我的查询:
SELECT i.ITEMTITLE, i.ITEMLINK, i.ITEMDESCRIPTION, i.ITEMPUBDATE, i.CHANNEL_ID,
i.ITEM_ID, a.AUTHOR_ID, a.AUTHORNAME
FROM FEED_ITEM i
LEFT JOIN FEED_ITEM_AUTHOR fia
ON i.ITEM_ID = fia.ITEM_ID
LEFT JOIN AUTHOR a
ON fia.ITEM_ID = a.AUTHOR_ID;
结果:
<table border =1>
<tr>
<th>ITEMTITLE</th>
<th>ITEM_ID</th>
<th>AUTHOR_ID</th>
<th>AUTHORNAME</th>
</tr>
<tr>
<td align="center">Lawyers...</td>
<td align="center">1</td>
<td align="center">1</td>
<td align="center">Joe Mullin</td>
</tr>
<tr>
<td align="center">AT&T/Time Warner...</td>
<td align="center">2</td>
<td align="center">2</td>
<td align="center">Jon Brodkin</td>
</tr>
<tr>
<td align="center">The “technosphere” ...</td>
<td align="center">19</td>
<td align="center">19</td>
<td align="center">Annalee Newitz</td>
</tr>
<tr>
<td align="center">Decrypted: ...</td>
<td align="center">20</td>
<td align="center"><null></td>
<td align="center"><null></td>
</tr>
</table>
feed_item_author 表具有正确的作者和项目数 - 15 个作者和 20 个项目,并且逐行正确匹配数据。
author 和 feed_items 表也有正确的行数 - 15 个作者和 20 个 feed_items。
我的代码中也有验证所有内容是否输入正确:
try
feedItem_AuthorStatement = conn.prepareStatement(feed_item_author_SQL, PreparedStatement.RETURN_GENERATED_KEYS);
feedItem_AuthorStatement.setInt(1, item_ID);
feedItem_AuthorStatement.setInt(2, author_ID);
int entrySuccess = feedItem_AuthorStatement.executeUpdate();
System.out.println("SUCCESS? :" + entrySuccess);
catch (SQLException ex)
Logger.getLogger(FeedItemCategoryHelper.class.getName()).log(Level.SEVERE, null, ex);
我在这里缺少什么?如果作者写了不止一篇文章,为什么我的查询返回的作者姓名和 ID 为 null?
【问题讨论】:
【参考方案1】:您不应该加入 ON fia.AUTHOR_ID = a.AUTHOR_ID;
您希望作者 ID 相同。除非我遗漏了什么,否则希望 itemID 与 authorID 匹配是没有意义的
【讨论】:
宾果游戏。谢谢,Learning2Code。以上是关于如果作者写了多篇文章,为啥这个 SQL 查询将一篇文章的作者姓名返回为 NULL?的主要内容,如果未能解决你的问题,请参考以下文章