从仓库库存中提取数据，按文章分组，但如果描述发生变化，则使用最后一个 USED

Posted 2023-03-24

【中文标题】从仓库库存中提取数据，按文章分组，但如果描述发生变化，则使用最后一个 USED

【英文标题】：Extract data from wharehouse stock, group by article but, if description change, use the last USED

【发布时间】：2020-04-13 07:09:06

【问题描述】：

我有一个文件 xls，在第一张表中我有我的货物库存记录，我每年都提取这个文件，并将结果放入同一张表的最后一行。 我尝试匹配过去 3 年，文章代码是唯一的，但描述已更改。 有一种按文章代码分组的方法，如果描述发生了变化，使用最后找到的？ 这是文件

这是我的查询，我使用 ADODB.Connection：

SELECT tab1[Codice Articolo], tab1Descrizione, Sum(IIf([anno]=2017,[qta],0)) AS Qta2017, Sum(IIf([anno]=2017,[Tot],0)) AS Val2017, Sum(IIf([anno]=2017,[€Pz],0)) AS Cad2017, Sum(IIf([anno]=2018,[Qta],0)) AS Qta2018, Sum(IIf([anno]=2018,[Tot],0)) AS Val2018, Sum(IIf([anno]=2018,[€pz],0)) AS Cad2018, Sum(IIf([anno]=2019,[Qta],0)) AS Qta2019, Sum(IIf([anno]=2019,[Tot],0)) AS Val2019, Sum(IIf([anno]=2019,[€pz],0)) AS Cad2019
FROM tab1
GROUP BY tab1.[Codice Articolo], tab1.Descrizione;

这是qry结果

这是我希望能够拥有的：

我认为我需要对同一张表使用一个连接，我尝试了这段代码的一些变体，没有权利：

SELECT t1[Codice Articolo], t2.Descrizione,(IIf(t1.[anno]=2017,t1.[qta],0)) AS Qta2017, Sum(IIf(t1.[anno]=2017,t1.[Tot],0)) AS Val2017, Sum(IIf(t1.[anno]=2017,t1.[€Pz],0)) AS Cad2017, Sum(IIf(t1.[anno]=2018,t1.[Qta],0)) AS Qta2018, Sum(IIf(t1.[anno]=2018,t1.[Tot],0)) AS Val2018, Sum(IIf(t1.[anno]=2018,t1.[€pz],0)) AS Cad2018, Sum(IIf(t1.[anno]=2019,t1.[Qta],0)) AS Qta2019, Sum(IIf(t1.[anno]=2019,t1.[Tot],0)) AS Val2019, Sum(IIf(t1.[anno]=2019,t1.[€pz],0)) AS Cad2019
FROM tab1 t1
LEFT JOIN (Select t2.Descrizione from Tab1 t2 on t2.anno = max(t1.anno)
LEFT JOIN 
GROUP BY tab1[Codice Articolo], t2.Descrizione;

是正确的方法，但错误是在代码上还是错误的方法？ 感谢您的任何建议

【参考方案1】：

问题在于描述，其值有时等于文章代码，有时不等于。这会创建新的组，这不是您想要的。

这是避免这种情况的一种方法：

SELECT 
    tab1[Codice Articolo], 
    Max(IIf(tab1[Codice Articolo] <> tab1Descrizione, tab1Descrizione, null)) AS tab1Descrizione
    Sum(IIf([anno]=2017,[qta],0)) AS Qta2017, 
    Sum(IIf([anno]=2017,[Tot],0)) AS Val2017, 
    ..., 
    Sum(IIf([anno]=2019,[€pz],0)) AS Cad2019
FROM tab1
GROUP BY tab1.[Codice Articolo], tab1.Descrizione;

【讨论】：

对于这篇文章，我只摘录了几篇文章；蝙蝠我有一个例子，在 2017 年，代码在描述中是相同的，但在 2018 年或 2019 年，描述发生了变化。如果代码产品上的描述相同与否，则相等，目标是使用上一年的描述。无论如何，你的代码给我这个错误：运行时错误'-2147467259（80004005）'我使用excel，ADODB和Provider = Microsoft.ACE.OLEDB.12.0

【参考方案2】：

我确信我的问题的解决方案是使用 JOIN QUERY，但我看不到光，因为我需要两个 JOIN。

这是我找到的解决方案：

strsql = "SELECT t1.[Codice Articolo], t2.Descrizione," & _
"Sum(IIf(t1.[Esercizio]=2017,t1.[NrPz],0)) AS Qta2017," & _
"Sum(IIf(t1.[Esercizio]=2017,t1.[€Tot],0)) AS Val2017," & _
"Sum(IIf(t1.[Esercizio]=2017,t1.[€Pz],0)) AS Cad2017," & _
"Sum(IIf(t1.[Esercizio]=2018,t1.[NrPz],0)) AS Qta2018," & _
"Sum(IIf(t1.[Esercizio]=2018,t1.[€Tot],0)) AS Val2018," & _
"Sum(IIf(t1.[Esercizio]=2018,t1.[€pz],0)) AS Cad2018," & _
"Sum(IIf(t1.[Esercizio]=2019,t1.[NrPz],0)) AS Qta2019," & _
"Sum(IIf(t1.[Esercizio]=2019,t1.[€Tot],0)) AS Val2019," & _
"Sum(IIf(t1.[Esercizio] = 2019, t1.[€pz], 0)) As Cad2019 " & _
"FROM ([temp$] t1 INNER JOIN [temp$] AS t2 ON t1.[Codice Articolo] = t2.[Codice Articolo]) INNER JOIN (SELECT Max([Esercizio]) AS maxdiEsercizio, [Codice Articolo] FROM [temp$] GROUP BY [Codice Articolo]) t3 ON (t2.[Codice Articolo] = t3.[Codice Articolo]) AND (t2.Esercizio = t3.maxdiEsercizio) " & _
"GROUP BY t1.[Codice Articolo], t2.Descrizione;"

谢谢。 法布里奇奥