如何使用 IN 修复 Hibernate Named Native Query 的 Where 子句

Posted 2023-03-23

【中文标题】如何使用 IN 修复 Hibernate Named Native Query 的 Where 子句

【英文标题】：How to fix Hibernate Named Native Query's Where clause with IN

【发布时间】：2019-08-22 01:18:45

【问题描述】：

此查询将从数据库中返回 17 个带有 IN 子句的数据。

但是，如果我为此分配变量，它会返回 0。

有人可以帮我解决问题吗？ 谢谢你。

``` @NamedNativeQuery(name = "CustomerPayeeTransaction.getCustomerPayeeTransactionsForTotalTransactionEmail", query = "" +
            "  select cpt.merchant_id, cpt.merchant_transaction_id, cpt.created_datetime, cpt.amount " +
            "  from customer_payee_transactions cpt"+
            "  inner join appl_inte_payment_gateway aipg on cpt.payment_gateway_id = aipg.integrated_payment_gateway_id"+
            "  inner join appl_cus_paye_trx_statuses acpts on cpt.cus_paye_trx_status_id = acpts.cus_paye_trx_status_id"+
            "  where (cpt.payment_gateway_id = :ipgId)"+
            "  and (acpts.name in ('CG_Pending'))")

    ```String statusList = "('CG_Pending','PG_Pending')";
query.setParameter("statusId",statusList);
 @NamedNativeQuery(name = "CustomerPayeeTransaction.getCustomerPayeeTransactionsForTotalTransactionEmail", query = "" +
                "  select cpt.merchant_id, cpt.merchant_transaction_id, cpt.created_datetime, cpt.amount " +
                "  from customer_payee_transactions cpt"+
                "  inner join appl_inte_payment_gateway aipg on cpt.payment_gateway_id = aipg.integrated_payment_gateway_id"+
                "  inner join appl_cus_paye_trx_statuses acpts on cpt.cus_paye_trx_status_id = acpts.cus_paye_trx_status_id"+
                "  where (cpt.payment_gateway_id = :ipgId)"+
                "  and (acpts.name in :statusList)")

【参考方案1】：

我在休眠而不是字符串中找到了答案

statusList = "('CG_Pending','PG_Pending')";

列出 statusIds = Arrays.asList("PG_Success","CG_Pending");

然后 Hibernate 会自动应用所需的条件。