在 iOS 5 中使用 AFNetworking 解析 JSON

Posted 2023-03-16

【中文标题】在 iOS 5 中使用 AFNetworking 解析 JSON

【英文标题】：Parsing JSON in iOS 5 with AFNetworking

【发布时间】：2013-02-27 08:47:16

【问题描述】：

我想用 ios 5 中的 AFNetworking 框架解析从服务器接收到的 JSON 数据：

AFJSONRequestOperation *operation = [AFJSONRequestOperation JSONRequestOperationWithRequest:request success:^(NSURLRequest *request, NSHTTPURLResponse *response, id JSON) 
 failure:nil];

我要解析的 JSON 数据如下所示：

[ 
    addressReal = "\U6912\U6c5f\U89e3\U653e\U5357\U8def295\U53f7";
    areaTotal = 774;
    balance = 0;
    businessIncome = "556.49";
    equNoString = "";
    equStatusSting = "";
    id = 208;
    staff = 10;

,
    
    addressReal = "\U53f0\U5dde\U5e02\U5e9c\U5927\U9053668\U53f7";
    areaTotal = 156;
    balance = 6463;
    businessIncome = "174.93";
    equStatusSting = "";
    id = 209;
    staff = 8;

]

我现在如何访问 JSON？

【问题讨论】：

我试图清理您的问题并使其真正可以回答，但我建议您尝试确保您始终清楚地说明您需要帮助解决的问题。另请参阅How To s The Smart Way（特别是：准确并提供有关您的问题的信息）

【参考方案1】：

这是我使用的，请随意满足您的需求：

-(void) loginWithUserID:(NSString*)usrID User:(NSString*)usr Password:(NSString *)psw Sender:(id)sender

    if ([sender respondsToSelector:@selector(startLoading)])
        [sender performSelector:@selector(startLoading)];
    

    baseURL = [NSString stringWithFormat:
                  @"http://xxx.xxx.xxx.xxx/test/service.svc/weblogin"];
    NSString* serviceURL = [NSString stringWithFormat:
                           @"%@?userID=%@&user=%@&password=%@",baseURL,usrID,usr,psw;

    NSURL *url = [NSURL URLWithString:[serviceURL stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding]];

    NSURLRequest *request = [NSURLRequest requestWithURL:url];

    AFJSONRequestOperation *operation = [AFJSONRequestOperation JSONRequestOperationWithRequest:request success:^(NSURLRequest *request, NSHTTPURLResponse *response, id JSON) 
        self.LoginOK = [JSON valueForKeyPath:@"LoginOK"];
        if (LoginOK.intValue == 1) 
            NSDictionary *usrData = [JSON valueForKeyPath:@"userData"];
            userData = [[UserData alloc]init];
            [userData readFromJSONDictionary:usrData];
            NSLog(@"Userdata: %@",userData);
            if ([sender respondsToSelector:@selector(loginSuccessful:)])
            
                [sender performSelector:@selector(loginSuccessful:)];
            
        else
            UIAlertView *alertView = [[UIAlertView alloc]initWithTitle:@"Error" message:@"No Correct Login Credentials" delegate:self cancelButtonTitle:@"OK" otherButtonTitles: nil];
            [alertView show];
            ;

     failure:^(NSURLRequest *request, NSHTTPURLResponse *response, NSError *error, id JSON) 
        if ([sender respondsToSelector:@selector(stopLoading)])
            [sender performSelector:@selector(stopLoading)];
        
        [[[UIAlertView alloc] initWithTitle:@"Error"
                                    message:@"Loginservice not available! Check your connection!"
                                   delegate:nil
                          cancelButtonTitle:@"OK"
                          otherButtonTitles: nil] show];
        NSLog(@"Error: %@", error);

    ];

    [operation start];
    ;

并使用一个

-(void)readFromJSONDictionary:(NSDictionary *)d


    [self setProperty1:[d objectForKey:@"property1"]];

将该字典中的所有属性获取到自定义类中的方法。

所以在你的情况下它会使用

NSDictionary *data = [JSON valueForKeyPath:@"data"];

【讨论】：

嗯，是的，这是一个示例，以防 JSON 出现在名为 data 的容器中。如果此答案对您有所帮助，并且您认为这是您问题的答案，请您按一下旁边的复选标记好吗？如果它没有回答您的问题，或者您需要更多说明，请不要犹豫！