如何在我的应用程序中解析/获取 JSON [关闭]

Posted 2023-03-16

【中文标题】如何在我的应用程序中解析/获取 JSON [关闭]

【英文标题】：How to parse/GET JSON in my App [closed]

【发布时间】：2014-02-03 06:37:42

【问题描述】：

我有数据库（linkP）

如何解析上述链接中的所有数据并显示结果

【问题讨论】：

看看这里***.com/questions/5547311/…

使用 NSURLConnection 和 NSJSONSerialization。 （同时检查 NSData 类）

How to parsing JSON object in iPhone SDK (XCode) using JSON-Framework 的可能副本

@user3264750 问题确实应该表明尝试并在出现问题时寻求帮助。

【参考方案1】：

- (void)viewDidLoad

NSMutableURLRequest *request=[NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http://arproject.site90.com/jsonbuilding.php"]];

    [request setHTTPMethod:@"GET"];

    [request setValue:@"application/json;charset=UTF-8" forHTTPHeaderField:@"content-type"];

    NSError *err;
    NSURLResponse *response;
    NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&err];

    NSDictionary *jsonArray = [NSJSONSerialization JSONObjectWithData:responseData options: NSJSONReadingMutableContainers error: &err];

    NSArray *array=[jsonArray objectForKey:@"result"];

    for (int i=0; i<[array count]; i++) 
        NSLog(@"the building id==%@",[[array objectAtIndex:i]objectForKey:@"building_id"]);
        NSLog(@"the building name==%@",[[array objectAtIndex:i]objectForKey:@"building_name"]);
        NSLog(@"the latitude==%@",[[array objectAtIndex:i]objectForKey:@"latitude"]);
         NSLog(@"the longitude==%@",[[array objectAtIndex:i]objectForKey:@"longitude"]);
         NSLog(@"the picture==%@",[[array objectAtIndex:i]objectForKey:@"picture"]);

【讨论】：

在控制台中查看结果，我正在等待

感谢您的帮助！！ :)

使用字面语法； [[array objectAtIndex:i]objectForKey:@"building_id"]可以更简单的表达：array[i][@"building_id"]

gt，谢谢兄弟，我怀疑它很容易识别对象键

【参考方案2】：

dispatch_async(kBgQueue, ^

    NSURL *myURL = [NSURL URLWithString:@"http://arproject.site90.com/jsonbuilding.php"];
    NSData *data=[NSData dataWithContentsOfURL:myURL];
    [self performSelectorOnMainThread:@selector(fetchedData:) withObject:data waitUntilDone:YES];
);

-(void)fetchedData : (NSData*)responseData

      NSError *error;

//parsing json data


 NSMutableArray *dataArray;
 NSDictionary *dictionary =[NSJSONSerialization JSONObjectWithData:responseData options:kNilOptions error:&error];

if(error == nil)


    dataArray =[dictionary valueForKey:@"result"];

  for (int i=0; i<[dataArray count]; i++)
  
    NSLog(@"%@",dataArray);
    


if(error)
NSLog(@"Error is %@",[error localizedDescription]);