json_decode 从 iOS 应用程序返回空值

Posted 2023-03-16

【中文标题】json_decode 从 iOS 应用程序返回空值

【英文标题】：json_decode returns null value from iOS application

【发布时间】：2012-12-19 01:16:09

【问题描述】：

我在解析发送到 php 网络服务的数据时遇到问题。我正在使用以下代码来获取 json：

$decoded = json_decode(file_get_contents('php://input'));
if(is_null($decoded) == NULL)
    
        $body = "Data was not successfully received";
        $body = $body . "      " . $jsonInput;
    

json 是从 ios 应用程序发送的，如下所示：

  "water" : "YES",
  "int_clean" : "YES",
  "ceiling_stains" : "YES",
  "additional_comments" : "not entered",
  "roof_cond" : "YES",
  "e_clean" : "YES",
  "interior_cond" : "not entered",
  "no_exp" : "not entered",
  "addr" : "YES",
  "roof_leak" : "YES",
  "doors_sec" : "YES",
  "elec" : "YES",
  "ceiling_exp" : "not entered",
  "repaired" : "YES",
  "o_desc" : "not entered",
  "w_sign" : "YES",
  "o_cond" : "not entered",
  "int_cond" : "YES",
  "gas" : "YES",
  "for_sale_sign" : "YES",
  "sold_as_is" : "YES",
  "mb_sign" : "YES",
  "graffiti" : "YES",
  "date" : "18-12-2012 18:58",
  "dewinterized" : "YES",
  "HVAC" : "YES",
  "why_no_mat" : "not entered",
  "is_lockbox" : "YES",
  "financing_mat" : "YES",
  "yard_cond" : "YES",
  "marketing_mat" : "YES",
  "HVAC_missing" : "not entered",
  "agent_info" : "YES",
  "e_cond" : "YES",
  "e_key" : "YES",
  "pool_sec" : "YES",
  "pool_clean" : "YES"

并使用此代码发送：

 NSDictionary * info = [NSDictionary dictionaryWithObjects:values forKeys:keys];
NSData* jsonData = [NSJSONSerialization dataWithJSONObject:info options:NSJSONWritingPrettyPrinted error:&error];

NSMutableURLRequest *req = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http://uofi-bars.com/sendEmail.php"]];
[req addValue:@"Content-Type: application/json" forHTTPHeaderField: @"Content-Type"];
[req setHTTPMethod:@"POST"];
[req setHTTPBody:jsonData];


[NSURLConnection sendSynchronousRequest:req returningResponse:&response error:&error];

我对 php 完全陌生，这让我头疼了很长一段时间。任何帮助将不胜感激！

【问题讨论】：

if(is_null($decoded) == NULL)?为什么不if(is_null($decoded))

【参考方案1】：

这是不正确的if(is_null($decoded) == NULL)。 PHP is_null 返回一个 boolean 值。所以你需要使用if(is_null($decoded) === FALSE) 或if(is_null($decoded) === TRUE)。