if 循环中的语句不起作用

Posted 2023-03-15

【中文标题】if 循环中的语句不起作用

【英文标题】：If statements in while loop not working

【发布时间】：2016-01-08 16:51:52

【问题描述】：

import random
#create a sequence of words to choose from
WORDS = ("python", "jumble", "easy", "difficult", "answer", "xylophone")

#pick one word randomly from the sequence
word = random.choice(WORDS)
#create a variable to use later to see if the guess is correct
correct = word
#create a jumbled version of the word
jumble = ""

count = 1
score = 100
hint = ""

while word:
  position = random.randrange(len(word))
  jumble += word[position]
  word = word[:position] + word[(position+1):]

 #start the game
 print ("""

      Welcome to Word Jumble!

Unscramble the letters to make a word.
(Press the enter key at the prompt to quit.)
""")
print("The jumble is: ", jumble)

guess = input("Your guess: ").lower()
while(guess != correct) and (guess != ""):
  print("Sorry, that's not it.")
  guess = input("Your guess: ").lower()
  count += 1
  if count == 3:
    option = input("Would you like a hint? (yes/no)" + '\n').lower()
      if option == "yes":
        hint = "yes"
        if word == "python":
            print("HINT: This was used to make this game.")
        elif word == "jumble":
            print("HINT: The name of the game.")
        elif word == "easy":
            print("HINT: Part of the Staples slogan.")
        elif word == "difficult":
            print("HINT: A synonym for hard.")
        elif word == "answer":
            print("HINT: Opposite of question.")
        elif word == "xylophone":
            print("HINT: An instrument.")



if guess == correct:
  print("That's it! You guess it!\n")
  score = score - 5*count
  if hint == "yes":
    score = score - 20



print("Thanks for playing. The word was", correct, ".")
print("You score is: " + str(score))
input("\n\nPress the enter key to exit.")

所以我在 python 中制作了这个小游戏，基本上要求用户解读单词，我在执行所有 if 语句时遇到问题。当我运行我的程序时，它可以正常工作到它向用户询问提示的部分。在回答是提示时，它会循环回到 while 循环，而不是显示提示，它只是说“对不起，不是这样”并继续循环直到用户得到正确的答案。因此，代码中的以下 if 语句没有被执行，有人可以解释为什么会这样以及如何解决它吗？

if option == "yes":
        hint = "yes"
        if word == "python":
            print("HINT: This was used to make this game.")
        elif word == "jumble":
            print("HINT: The name of the game.")
        elif word == "easy":
            print("HINT: Part of the Staples slogan.")
        elif word == "difficult":
            print("HINT: A synonym for hard.")
        elif word == "answer":
            print("HINT: Opposite of question.")
        elif word == "xylophone":
            print("HINT: An instrument.")

【参考方案1】：

问题出在这里：

option = input("Would you like a hint? (yes/no)" + '\n').lower

option 被设置为lower，一个字符串方法。你需要调用它：

option = input("Would you like a hint? (yes/no)" + '\n').lower()
                                                              ^^

现在option 将是一个字符串。

【讨论】：

我刚刚注意到，当我发布问题时，它对问题没有影响，问题仍然存在

如果程序之前缺少()，那将使其无法运行。添加() 应该会有所作为。您是否保存了源代码然后重新运行它？

【参考方案2】：

您正在检查word 是什么，但我认为这不是答案（它已被更改）。改为检查correct：

if option == "yes":
    hint = "yes"
    if correct == "python":
        print("HINT: This was used to make this game.")
    elif correct == "jumble":
        print("HINT: The name of the game.")
    elif correct == "easy":
        print("HINT: Part of the Staples slogan.")
    elif correct == "difficult":
        print("HINT: A synonym for hard.")
    elif correct == "answer":
        print("HINT: Opposite of question.")
    elif correct == "xylophone":
        print("HINT: An instrument.")

【讨论】：

以前试过这个，没有运气

等等，它确实起作用了，在修复了 Tigerhawk 提到的错误并将其更改为更正之后，它起作用了，我的问题是，为什么它是正确的还是单词有关系？两者都包含我想要的实际单词

@W.Ahmed - 在while word: 循环中，word 最终会变成一个空字符串，jumble 将包含混乱的单词，而correct 包含原始单词。