如何检查输入的电子邮件是不是为电子邮件格式[重复]

Posted 2023-03-15

【中文标题】如何检查输入的电子邮件是不是为电子邮件格式[重复]

【英文标题】：how to check the entered email is in email format [duplicate]如何检查输入的电子邮件是否为电子邮件格式[重复]

【发布时间】：2016-07-23 21:14:58

【问题描述】：

如何检查输入的电子邮件是否正确。喜欢 [e-mail] 或任何。

这是我的代码。我试过了，但我的 if 语句出错了

import UIKit

extension String 
    func matchPattern(patStr:String)->Bool 
        var isMatch:Bool = false
        do 
            let regex = try NSRegularExpression(pattern: patStr, options: [.CaseInsensitive])
            let result = regex.firstMatchInString(self, options: NSMatchingOptions(rawValue: 0), range: NSMakeRange(0, characters.count))

            if (result != nil)
            
                isMatch = true
            
        
        catch 
            isMatch = false
        
        return isMatch
    


class RegisterVC: UIViewController 



    @IBOutlet weak var EmailField: UITextField!


    @IBOutlet weak var LocationField: UITextField!

    @IBOutlet weak var userNameField: UITextField!



    @IBOutlet weak var passWordField: UITextField!



    @IBOutlet weak var confirmPasswordField: UITextField!
override func viewDidLoad() 
        super.viewDidLoad()

        // Do any additional setup after loading the view.
    
@IBAction func SignUpBtnPress(sender: AnyObject) 
        let Email:NSString = EmailField.text!
        let Location:NSString = LocationField.text!
        let username:NSString = userNameField.text!
        let password:NSString = passWordField.text!
        let confirm_password:NSString = confirmPasswordField.text!

        if (Email.matchPattern("^[A-Z0-9._%+-]+@[A-Z0-9.-]+\\.[A-Z]2,4$")==true)
        
            print("this is e-mail!")
        

        else if ( Email.isEqualToString("") || Location.isEqualToString("") || username.isEqualToString("") || password.isEqualToString("") || confirm_password.isEqualToString("") ) 


            let alertController = UIAlertController(title: "Alert", message: "All Field Are Mnditory.", preferredStyle: UIAlertControllerStyle.Alert)
            let DestructiveAction = UIAlertAction(title: "Ok", style: UIAlertActionStyle.Default)  (result : UIAlertAction) -> Void in
                print("Settings")
            

            alertController.addAction(DestructiveAction)

            self.presentViewController(alertController, animated: true, completion: nil)



         else if ( !password.isEqual(confirm_password) ) 

            let alertController = UIAlertController(title: "Alert", message: "Password Din't Match.", preferredStyle: UIAlertControllerStyle.Alert)
            let DestructiveAction = UIAlertAction(title: "Ok", style: UIAlertActionStyle.Default)  (result : UIAlertAction) -> Void in
                print("Password Din't Match")
            

            alertController.addAction(DestructiveAction)

            self.presentViewController(alertController, animated: true, completion: nil)

        




        print("login sucess")

我需要的是，如果任何用户开始绑定电子邮件 ID 格式错误，我需要显示警报。

谢谢

【问题讨论】：

" 我的 if 语句出错了" 是一个无用的问题描述。哪个 if 语句和什么错误？

***.com/questions/27998409/…

除了实际联系主机并查看它是否会接受电子邮件之外，确实没有验证电子邮件地址的好方法。见这篇文章：I Knew How To Validate An Email Address Until I Read The RFC

【参考方案1】：

希望对你有帮助：

func isValidEmail(testStr:String) -> Bool 

    print("validate emilId: \(testStr)")
    let emailRegEx = "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]2,4"
    let emailTest = NSPredicate(format:"SELF MATCHES %@", emailRegEx)
    let result = emailTest.evaluateWithObject(testStr)
    return result

在您的代码中：

import UIKit

extension String 
    func matchPattern(patStr:String)->Bool 
        var isMatch:Bool = false
        do 
            let regex = try NSRegularExpression(pattern: patStr, options: [.CaseInsensitive])
            let result = regex.firstMatchInString(self, options: NSMatchingOptions(rawValue: 0), range: NSMakeRange(0, characters.count))

            if (result != nil)
            
                isMatch = true
            
        
        catch 
            isMatch = false
        
        return isMatch
    


class RegisterVC: UIViewController 



    @IBOutlet weak var EmailField: UITextField!


    @IBOutlet weak var LocationField: UITextField!

    @IBOutlet weak var userNameField: UITextField!



    @IBOutlet weak var passWordField: UITextField!



    @IBOutlet weak var confirmPasswordField: UITextField!
override func viewDidLoad() 
        super.viewDidLoad()

        // Do any additional setup after loading the view.
    


func isValidEmail(testStr:String) -> Bool 

    print("validate emilId: \(testStr)")
    let emailRegEx = "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]2,4"
    let emailTest = NSPredicate(format:"SELF MATCHES %@", emailRegEx)
    let result = emailTest.evaluateWithObject(testStr)
    return result



@IBAction func SignUpBtnPress(sender: AnyObject) 
        let Email:NSString = EmailField.text!
        let Location:NSString = LocationField.text!
        let username:NSString = userNameField.text!
        let password:NSString = passWordField.text!
        let confirm_password:NSString = confirmPasswordField.text!

        if isValidEmail(Email) == true
        
            print("this is e-mail!")
        

        else if ( Email.isEqualToString("") || Location.isEqualToString("") || username.isEqualToString("") || password.isEqualToString("") || confirm_password.isEqualToString("") ) 


            let alertController = UIAlertController(title: "Alert", message: "All Field Are Mnditory.", preferredStyle: UIAlertControllerStyle.Alert)
            let DestructiveAction = UIAlertAction(title: "Ok", style: UIAlertActionStyle.Default)  (result : UIAlertAction) -> Void in
                print("Settings")
            

            alertController.addAction(DestructiveAction)

            self.presentViewController(alertController, animated: true, completion: nil)



         else if ( !password.isEqual(confirm_password) ) 

            let alertController = UIAlertController(title: "Alert", message: "Password Din't Match.", preferredStyle: UIAlertControllerStyle.Alert)
            let DestructiveAction = UIAlertAction(title: "Ok", style: UIAlertActionStyle.Default)  (result : UIAlertAction) -> Void in
                print("Password Din't Match")
            

            alertController.addAction(DestructiveAction)

            self.presentViewController(alertController, animated: true, completion: nil)

        




        print("login sucess")

【讨论】：

我只是复制你的 func 方法，但是当我输入一个未格式化的电子邮件时它没有显示？？

没问题，但我怎么能在我的 signupbutton pressd 方法中调用这个方法

您需要稍微扩展正则表达式 emailRegEx = "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]2,15" - 现在很多域结尾都以超过 4 个字符结尾。

【参考方案2】：

你可以试试这个

-(BOOL)isValidEmailAddress:(NSString *)email

    BOOL stricterFilter = YES; 
    NSString *stricterFilterString = @"[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]2,4";
    NSString *laxString = @".+@.+\\.[A-Za-z]2[A-Za-z]*";
    NSString *emailRegex = stricterFilter ? stricterFilterString:laxString;
    NSPredicate *emailTest = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", emailRegex];
    return [emailTest evaluateWithObject:email];

斯威夫特版本

func isValidEmail(testStr:String) -> Bool 

println("validate emilId: \(testStr)")

let emailRegEx = "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]2,"

var emailTest = NSPredicate(format:"SELF MATCHES %@", emailRegEx)

var result = emailTest?.evaluateWithObject(testStr)

return result!

使用电子邮件验证：

   if isValidEmail(textField.text)
  
      println("Validate EmailID")
  
  else
  
      println("invalide EmailID")
  

更多来自Email & Phone Validation in Swift

【讨论】：

我是 ios 新手，从 swift 开始。如果可能的话 swift.It will be help full

关于 Swift 的问题

如何使用上述解决方案代码显示警报？？

那是什么rdfsdsfsdfsd??

@user5513630 是字符串！！！

【参考方案3】：

这应该可以正常工作

   func isValidEmail(testStr:String) -> Bool 
            let emailRegEx = "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]2,"
            let emailTest = NSPredicate(format:"SELF MATCHES %@", emailRegEx)
            let result = emailTest.evaluateWithObject(testStr)
            return result
        

用法：

if isValidEmail("[e-mail]")
//email is valid

【讨论】：

错误。以下电子邮件是有效的，此测试表明它是无效的 [e-mail]9、js#[e-mail]、j_9@[129.126.118.1]、`[e-mail]9` 和以下相反：[e-mail]、[e-mail]、js@proseware..com , js@proseware..com