如何使 Http 获取请求 URL 由 swift 3 中的管道组成？

Posted 2023-03-15

【中文标题】如何使 Http 获取请求 URL 由 swift 3 中的管道组成？

【英文标题】：How to make Http get request URL consist of pipelines in swift 3?

【发布时间】：2017-08-04 08:46:24

【问题描述】：

我从 swift 3 发出了一个获取请求。该 url 有管道。如果没有管道，它可以正常工作，但是当我添加管道时，代码中断说在展开可选值错误时发现 nil。

这是我的网址 让 url = URL(string:"https://maps.googleapis.com/maps/api/directions/json?origin=colombo&destination=kandy&waypoints=optimize:true|&key=AIzaSyCNBcQLIVvNwqjkYiLawnYK_AM")

这是我的代码：

func synchronusGetRequstForExternalAPI(api_url:String, headers:[ String: String]) -> ResultModel 

        let resultModel = ResultModel()

        //create the url with URL
        let url = URL(string:"https://maps.googleapis.com/maps/api/directions/json?origin=colombo&destination=kandy&waypoints=optimize:true|&key=AIzaSyCNBcQLIVvNwqjkYiLawnYK_OK4EQbRM5M")
        //create the URLRequest object using the url object
        var request = URLRequest(url: url!)

        //set headers
        for item in headers 
            request.addValue(item.value, forHTTPHeaderField: item.key)
        

        let semaphore = DispatchSemaphore(value: 0)
        let task = URLSession.shared.dataTask(with: request as URLRequest) 
            (data, response, error) in


            if(error != nil)
                resultModel.ErrorType = .NO_INT
                resultModel.JsonReslut = JSON.null

            else

                if let resp = response as? HTTPURLResponse
                    if(resp.statusCode == 200)
                        if let jsonResult = JSON(data) as? JSON 

                            resultModel.ErrorType = .NO_ERROR
                            resultModel.JsonReslut = jsonResult
                        
                    else
                        if let jsonResult = JSON(data) as? JSON 

                            resultModel.ErrorType = .SEREVR_ERROR
                            resultModel.JsonReslut = jsonResult
                        else
                            resultModel.ErrorType = .SEREVR_ERROR
                            resultModel.JsonReslut = JSON.null
                        
                    
                
            

            semaphore.signal()
        
        task.resume()
        _ = semaphore.wait(timeout: DispatchTime.distantFuture)

        return resultModel
    

谁能告诉我为什么会这样？

【参考方案1】：

| 不是 URL 中允许的字符。尝试百分比转义 URL 字符串

let url = URL(string:"https://maps.googleapis.com/maps/api/directions/json?origin=colombo&destination=kandy&waypoints=optimize:true|&key=AIzaSyCNBcQLIVvNwqjkYiLawnYK_OK4EQbRM5M".stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLFragmentAllowedCharacterSet()))