tkinter 询问目录（）

Posted 2023-03-14

【中文标题】tkinter 询问目录（）

【英文标题】：tkinter askdirectory()

【发布时间】：2017-02-11 19:35:22

【问题描述】：

基于上次更新的文件移动。仅使用按钮 3，我在目录末尾缺少一个斜杠。这会导致路径与我要移动的文本文件合并：

Exception in Tkinter callback
Traceback (most recent call last):
  File "C:\Python34\lib\tkinter\__init__.py", line 1482, in __call__
    return self.func(*args)
  File "C:/Python34/check2.py", line 30, in fileMove
    if os.stat(src).st_mtime > now - 1 * 86400:
FileNotFoundError: [WinError 2] The system cannot find the file specified: 'C:/Somewhere/filenametextfile'

import shutil, sys, time, os
import tkinter as tk
from tkinter import *
import tkinter.filedialog
root = Tk()

def fileMove():
        sourcePath = filedialog.askdirectory()
        receivePath = filedialog.askdirectory()
        source = sourcePath
        dest = receivePath
        files = os.listdir(source) 

        now = time.time()
        for f in files:
            src = (source) +f
            dst = (dest) +f
            if os.stat(src).st_mtime > now - 1 * 86400:
                if os.path.isfile(src):
                    shutil.move(src, dst)
                    print("File move is Alright, Alright, Alright")

所有显示按钮

    def button_press():
        if one:
            x = 1
            display.configure(text=x)
        if two:
            x = 2
            display.configure(text=x)
        if three:
            x = 3
            display.configure(text=x)

    display = LabelFrame(root, bg="red", , )
    display.pack()

    one = Button(root, text="1", , ,command=fromSource)
    one.pack(side="left")

    two = Button(root, text="2", , , command=toReceive)
    two.pack(side="left")

    three = Button(root, text="3", , ,command=fileMove)
    three.pack(side="left")

    root.mainloop()

【问题讨论】：

您是否尝试过简单地添加斜线？还是使用os.path.join？

【参考方案1】：

您应该使用os.path.join 方法来连接路径，而不是简单的+ 字符串连接。这样代码可以在多个平台（Windows/Mac/Linux）上运行

例如

from tkinter import Tk
from tkinter import filedialog
import os

root = Tk()
root.withdraw()

current_directory = filedialog.askdirectory()
file_name = "test.txt"

file_path = os.path.join(current_directory,file_name)
print(file_path)