我是 graphql 的新手，我发现在 django-graphql 中使用来自两个不同应用程序的模式有困难？

Posted 2023-03-08

【中文标题】我是 graphql 的新手，我发现在 django-graphql 中使用来自两个不同应用程序的模式有困难？

【英文标题】：I am new to graphql and I am finding difficulty in using schema from two different apps in django-graphql?

【发布时间】：2020-10-08 11:42:02

【问题描述】：

我是 graphql 的新手，我发现在 django-graphql 中使用来自两个不同应用程序的架构有困难？

app1 hero schema.py

import graphene
from graphene_django import DjangoObjectType
from .models import Hero

class HeroType(DjangoObjectType):
    class Meta:
        model = Hero

class Query(graphene.ObjectType):
    heroes = graphene.List(HeroType)    

    def resolve_heroes(self, info, **kwargs):
        return Hero.objects.all()

app2 产品架构.py

class ProductType(DjangoObjectType):
  class Meta:
    model = Product

class Query(object):
    allproducts = graphene.List(ProductType, search=graphene.String(),limit=graphene.Int(),skip=graphene.Int(), offset=graphene.Int())

    def resolve_allproducts(self, info, search=None, limit=None, skip=None, offset=None,  **kwargs):
        # Querying a list of products
        qs = Product.objects.all()
        data = []
        if search:
          filter = (
                Q(name__icontains=search)|
                Q(price__icontains=search)
            )
          qs = qs.filter(filter)

        if skip:
            qs = qs[skip:]

        if limit:
          # qs = qs[:limit]
            qs = qs[int(offset):(int(offset) + int(limit))]
        return qs

我的问题： 在主项目schema.py中，如何从app1-hero和app2-product调用schema？

【参考方案1】：

您可以将两个查询导入为不同的名称。您的主 schema.py 看起来像这样：

import graphene
from app1.schema import Query as app1_query
from app2.schema import Query as app2_query

class Query(app1_query, app2_query):
    # This class will inherit from multiple Queries
    pass


schema = graphene.Schema(query=Query)

【参考方案2】：

只需在您的应用中定义类型（比如说在 query.py 文件中）及其解析器。

import graphene
from graphene_django import DjangoObjectType
from .models import Hero

class HeroType(DjangoObjectType):
    class Meta:
        model = Hero

def resolve_hero_type(info):
    # your resolver

然后在schema.py

from app1.query import ProductType, resolve_product_type
from app2.query import HeroType, resolve_hero_type

class Query(object):
    all_products = graphene.List(ProductType, search=graphene.String(), limit=graphene.Int(),skip=graphene.Int(), offset=graphene.Int())
    heroes = graphene.List(HeroType)

    def resolve_all_products(self, info):
        return resolve_product_type(info)

    def resolve_heroes(self, info):
        return resolve_hero_type(info)

【讨论】：

谢谢车切。这对我有用..我被困了很长时间......你帮我解决了这个问题。再次感谢您。