UISearchBar 从 Json (SWIFT 3) 获取数据

Posted 2023-03-04

【中文标题】UISearchBar 从 Json (SWIFT 3) 获取数据

【英文标题】：UISearchBar fetching data from Json ( SWIFT 3 )

【发布时间】：2017-08-09 02:24:58

【问题描述】：

我有一个类保存来自我的 api 的数据

class Shops 
    private var _familiy_id: String?
    private var _logo : String?
    private var _shopname : String?


    var familiy_id : String
        return _familiy_id!
    

    var shopname : String
        return _shopname!
    
    var Logo : String
        return _logo!
    

    init(shopname : String , Logo : String , family_id : String)         
        self._shopname = shopname
               self._logo = Logo
        self._familiy_id = family_id        
    

我正在尝试过滤商店名称并在用户编辑搜索栏时将其展开。所以我尝试了这段代码：

var searchActive : Bool = false
var filtered:[Shops] = []
var shops = [Shops]()

func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String)        
    filtered = searchText.isEmpty ? shops : shops.filter  (item: String) -> Bool in
        // If dataItem matches the searchText, return true to include it
        return item.range(of: searchText, options: .caseInsensitive, range: nil, locale: nil) != nil
            
    tableView.reloadData()

但我收到一条错误消息，提示该项目没有成员范围！ 抱歉，这是我第一次在我的项目中实现 UISearchBar，所以我正在尝试从其他代码中学习

【参考方案1】：

查看此链接How to implement UISearchController in UITableView - SWIFT 并在此函数中添加您的代码func updateSearchResults(for searchController: UISearchController) 试试这个：

// MARK: UISearchResultsUpdating delegate function
// example for search user in userlist and change it as your requirements. 
func updateSearchResults(for searchController: UISearchController) 
    guard let searchString = searchController.searchBar.text else 
        return
    

    // Filter the data array and get only those userlist that match the search text.
    filteredArray = self.userList.filter
        let firstName = $0.first_name.lowercased()
        let middleName = $0.middle_name.lowercased()
        let lastName = $0.last_name.lowercased()
        let contactNumber = $0.mobile.lowercased()
        let fullName = $0.fullname.lowercased()

        return firstName.range(of: searchString.lowercased()) != nil
            || middleName.range(of: searchString.lowercased()) != nil
            || lastName.range(of: searchString.lowercased()) != nil
            || contactNumber.range(of: searchString.lowercased()) != nil
            || fullName.range(of: searchString.lowercased()) != nil
    
    // Reload the tableview.
    tableView.reloadData()

希望对你有所帮助

【讨论】：

感谢您的回复。问题是我不知道如何将商店的名称放在过滤器的数组中。到目前为止，它在数组中作为 Data

let filteredArray = shops.filter let shopname = $0.shopname.lowercased() return shopname.range(of: searchString.lowercased()) != nil 你试过上面的代码了吗？它会帮助你，请尝试一下。