如何根据嵌套在json中的条件过滤复杂的json？

Posted 2023-02-14

【中文标题】如何根据嵌套在json中的条件过滤复杂的json？

【英文标题】：How filter complex json on condition nested in json?

【发布时间】：2022-01-19 18:21:09

【问题描述】：

我有一个复杂对象数组，需要根据多个条件进行过滤

var myList= [
  
    "UserId": 1,
    "UserDetails": 
      "Department": [
        
          "Name": "dept1"
        
      ],
      "Projects": [
        
          "Name": "Project1"
        ,
        
          "Name": "Project2"
        
      ]
    
  ,
  
    "UserId": 2,
    "UserDetails": 
      "Department": [
        
          "Name": "dept2"
        
      ],
      "Projects": [
        
          "Name": "Project3"
        ,
        
          "Name": "Project4"
        
      ]
    
  ,
  
    "UserId": 3,
    "UserDetails": 
      "Department": [
        
          "Name": "dept3"
        
      ],
      "Projects": [
        
          "Name": "Project5"
        ,
        
          "Name": "Project6"
        
      ]
    
  
]

我想根据两个条件过滤部门-->名称为“dept3”或存在名称为“Project3”的项目

var filteredElements=this.myList.filter((x)=>x.UserDetails.filter((y)=>y.Department... ??

如何编写代码来过滤这两个条件？

【问题讨论】：

你有一个数据集，你必须过滤它。问题是什么？以及它与打字稿有什么关系？

【参考方案1】：

您不能在UserDetails 上使用过滤器，因为它不是数组而是对象。

在 Department 和 Projects 上应用 find，并在它们之间使用 OR 条件和所需条件。

var myList= [
    
      "UserId": 1,
      "UserDetails": 
        "Department": [
          
            "Name": "dept1"
          
        ],
        "Projects": [
          
            "Name": "Project1"
          ,
          
            "Name": "Project2"
          
        ]
      
    ,
    
      "UserId": 2,
      "UserDetails": 
        "Department": [
          
            "Name": "dept2"
          
        ],
        "Projects": [
          
            "Name": "Project3"
          ,
          
            "Name": "Project4"
          
        ]
      
    ,
    
      "UserId": 3,
      "UserDetails": 
        "Department": [
          
            "Name": "dept3"
          
        ],
        "Projects": [
          
            "Name": "Project5"
          ,
          
            "Name": "Project6"
          
        ]
      
    
  ]
  
var filteredElements = myList.filter(x =>x.UserDetails.Department.find(d => d.Name == "dept3") || x.UserDetails.Projects.find(p => p.Name == "Project3"))
console.log(filteredElements)

【参考方案2】：

满足条件

用户属于部门“dept3”

user.UserDetails.Department.some(department => department.Name == "dept3")

有一个名为“Project3”的项目

user.UserDetails.Projects.some(project => project.Name == "Project3")

现在将它们链接在一起，

var filteredElements = this.myList.filter(user => 
    user.UserDetails.Department.some(department => department.Name == "dept3") || 
    user.UserDetails.Projects.some(project => project.Name == "Project3"))

【讨论】：

您的代码不起作用。 Department 不是对象而是数组。看我的回答。

编辑处理数组，谢谢。

【参考方案3】：

myList.filter(i => i.UserDetails.Department.some(d => d.Name === 'dept3') || i.UserDetails.Projects.some(p => p.Name === 'Project3'))