php中数据加载中的数组到字符串转换

Posted 2023-05-09

【中文标题】php中数据加载中的数组到字符串转换

【英文标题】：Array to string conversion in php in data loading

【发布时间】：2018-04-17 09:50:16

【问题描述】：

    <?php

$serverName = "RAHULTCO-PC\MANTRA2005";
$url1=$_SERVER['REQUEST_URI'];
header("Refresh: 1; URL=$url1");
$connectionInfo = array("Database"=>"PayTime", "UID"=>"sa", "PWD"=>"Mantra123");

$conn = sqlsrv_connect($serverName, $connectionInfo);
$con1 = $con1=mysqli_connect('localhost','root','','gps_db');
$date = date('Y-m-d H:i:sa');
$sql = "SELECT TOP 10 CardNO FROM dbo.tmpDmpTerminalData order by In_Out_Time desc ";
/*$sql = "SELECT [CardNO]
  FROM [PayTime].[dbo].[tmpDmpTerminalData] WHERE (IPaddress = '172.23.42.141' AND In_Out_Time >= '$date')";*/

$stmt = sqlsrv_query( $conn, $sql);
if( $stmt === false ) 
     die( print_r( sqlsrv_errors(), true));


// Make the first (and in this case, only) row of the result set available for reading.
if( sqlsrv_fetch( $stmt ) === false) 
     die( print_r( sqlsrv_errors(), true));


// Get the row fields. Field indeces start at 0 and must be retrieved in order.
// Retrieving row fields by name is not supported by sqlsrv_get_field.

if ($conn)
  $items = array();
  while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC) ) 
      $items[] = $row;


   print_r($items);
 

else
  echo "connection failed.<br />";
  die (print_r(sqlsrv_errors(), true));


$host = "localhost";
$user = "root";
$pass = "";
$db = "gps_db";


$con = mysqli_connect($host, $user, $pass, $db);


if ($con) 
    echo "Connected";

    $query = "SELECT `user_id` FROM `gps_gatepassmaster` WHERE `punch_id` IN (".implode(',',$items).")";
    $run = mysqli_query($con, $query);
    if ($run == TRUE)
      ?>
      <table border="1"  align="center">
        <tr>
          <td>user_id</td>
        </tr>
        <?php
        while($data= mysqli_fetch_assoc($run))
          ?>
          <tr>
            <td><?php echo $data['user_id'];?></td>
          </tr>
          <?php
        
         ?></table><?php

数组的输出 = Array ( [0] => Array ( [CardNO] => 115293 ) [1] => 数组 ( [CardNO] => 100087 ) [2] => 数组 ( [CardNO] => 115293 ) [3] => 数组 ( [CardNO] => 100087 ) [4] => 数组 ( [CardNO] => 115293 ) [5] => 数组 ( [CardNO] => 115163 ) [6] => 数组 ( [CardNO] = > 115201 ) [7] => 数组 ( [CardNO] => 115293 ) [8] => 数组 ( [CardNO] => 115163))

数据未加载出现错误

"数组到字符串的转换 D:\wamp\www\reports_vinay\connect_to_multiple.php 第 54 行"。

【问题讨论】：

您使用的是 MySQL 还是 MS SQL Server？

@jarlh sqlsrv_connect() 建议他在sql server上

我不知道第 54 行包含什么...

请以后只选择与您的问题相关的标签，不要向其他标签发送垃圾邮件

【参考方案1】：

implode 仅适用于单维数组，您传递的是多维数组。您应该可以通过只需将卡号放入$items 数组而不是整行来解决它。

while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC) ) 
  $items[] = $row['CardNO'];

【参考方案2】：

if ($conn)
  $items = array();
  while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC) ) 
  $items[] = $row;


print_r($items);
 

这意味着您的 $items 是一个关联数组，位于第 54 行。 那是WHEREpunch_idIN (".implode(',',$items).")";，在这里你将它用作简单的数组。

这就是问题所在。

将$items[] = $row; 更改为$items[] = $row['CardNO'];