在 Android 网络服务方面需要帮助
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【中文标题】在 Android 网络服务方面需要帮助【英文标题】：Need help in Android web services 【发布时间】：2017-10-25 13:54:09 【问题描述】：我正在制作一个需要登录和注册的 android 应用程序，我是编程初学者，我已经完成了一些没有显示任何结果或错误的工作。 `
package com.example.user.appliication;
import android.content.Intent;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;
import com.android.volley.Request;
import com.android.volley.RequestQueue;
import com.android.volley.Response;
import com.android.volley.VolleyError;
import com.android.volley.toolbox.StringRequest;
import com.android.volley.toolbox.Volley;
import org.json.JSONException;
import org.json.JSONObject;
import java.util.HashMap;
public class RegisterActivity extends AppCompatActivity
EditText ETname, ETusername, ETpassword, ETconfpas, ETrollnumber, ETemail;
Button RegisterButton;
StringRequest request;
RequestQueue queue;
String URL = "http://user.000webhostapp.com/folder/script.php";
@Override
protected void onCreate(Bundle savedInstanceState)
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_register);
ETname = (EditText) findViewById(R.id.etName);
ETusername = (EditText) findViewById(R.id.etUsername);
ETpassword = (EditText) findViewById(R.id.etPassword);
ETconfpas = (EditText) findViewById(R.id.etConPass);
ETrollnumber = (EditText) findViewById(R.id.etRollnumber);
ETemail = (EditText) findViewById(R.id.etEmail);
queue = Volley.newRequestQueue(this);
RegisterButton = (Button) findViewById(R.id.regButton);
RegisterButton.setOnClickListener(new View.OnClickListener()
@Override
public void onClick(View v)
if(ETname.getText().toString().matches("")||ETusername.getText().toString().matches("")||ETpassword.getText().toString().matches("")||ETconfpas.getText().toString().matches("")||ETrollnumber.getText().toString().matches("")||ETemail.getText().toString().matches(""))
Toast.makeText(RegisterActivity.this, "All fields required", Toast.LENGTH_SHORT).show();
else
request = new StringRequest(Request.Method.POST, URL, new Response.Listener<String>()
@Override
public void onResponse(String s)
try
JSONObject jsonObject = new JSONObject(s);
boolean success = jsonObject.getBoolean("success");
if(success)
String message = jsonObject.getString("message");
Intent i = new Intent(RegisterActivity.this, HomeActivity.class);
startActivity(i);
Toast.makeText(RegisterActivity.this, message, Toast.LENGTH_SHORT).show();
else
String message = jsonObject.getString("message");
Toast.makeText(RegisterActivity.this, message, Toast.LENGTH_SHORT).show();
catch (JSONException e)
e.printStackTrace();
, new Response.ErrorListener()
@Override
public void onErrorResponse(VolleyError volleyError)
Toast.makeText(RegisterActivity.this, volleyError.toString(), Toast.LENGTH_SHORT).show();
)
@Override
protected HashMap<String, String> getParams()
HashMap<String,String> params = new HashMap<String, String>();
params.put("name",ETname.getText().toString());
params.put("username",ETusername.getText().toString());
params.put("password",ETpassword.getText().toString());
params.put("rollnumber",ETrollnumber.getText().toString());
params.put("email",ETemail.getText().toString());
return params;
;
queue.add(request);
);
`
用于注册的PHP脚本是
<?php
$response = array();
if (isset($_POST['user_name']) && isset($_POST['user_password']) &&
isset($_POST['user_fullname']))
// include db connect
require_once __DIR__ . '/connection.php';
$name = $_POST['name'];
$username = $_POST['username'];
$password = $_POST['password'];
$rollnumber = $_POST['rollnumber'];
$email = $_POST['email'];
$query = "INSERT INTO appusers(name ,username, password, rollnumber, email)
VALUES ('$name','$username','$password','$rollnumber','$email')";
// insert into db
$result = mysqli_query($con,$query);
//check if registration completed
if ($result)
$response["success"] = true;
$response["message"] = "Registration completed";
// echo JSON response
echo json_encode($response);
else
$response["success"] = false;
$response["message"] = "Rollnumber alreaday exist";
// echo JSON response
echo json_encode($response);
else
$response["success"] = false;
$response["message"] = "Something went wrong";
// echo JSON response
echo json_encode($response);
?>
当我运行这个应用程序时，ADB 停止但没有显示任何错误响应，也没有向我的数据库发送数据。
【问题讨论】：
强烈建议您查看准备好的语句，因为您目前对 sql 注入开放。 【参考方案1】：我从未使用过 StringRequest 你试过不使用 AsyncTask 将它放在主线程上吗？ 它看起来像这样：
在您的按钮中单击：
//Trust me you need a progress bar
pb = (ProgressBar) this.findViewById(R.id.regProgressBar);
RegisterButton = (Button) findViewById(R.id.regButton);
RegisterButton.setOnClickListener(new View.OnClickListener()
@Override
public void onClick(View v)
LoginLoader ll = new LoginLoader(pb, RegisterActivity.this);
String[] args = new String[6];
args[0] = URL;
args[1] = ETname.getText().toString();
args[2] = ETusername.getText().toString();
args[3] = ETemail.getText().toString();
args[4] = ETpassword.getText().toString();
args[5] = ETrollnumber.getText().toString();
ll.execute(args);
);
public class LoginLoader extends AsyncTask<String, Void, String>
private final ProgressBar _pb;
private final Activity _act;
public LoginLoader(ProgressBar pb, Activity act)
_pb = pb;
_act = act;
@Override
protected String doInBackground(String... params)
try
String url = params[0];
HttpURLConnection con = (HttpURLConnection) new URL(url).openConnection();
con.setDoInput(true);
con.setRequestMethod("POST");
if(params.length > 1)
con.setDoOutput(true);
OutputStreamWriter writer = new OutputStreamWriter(con.getOutputStream());
writer.write("name=" + URLEncoder.encode(params[1], "UTF-8") + "&");
writer.write("username=" + URLEncoder.encode(params[2], "UTF-8") + "&");
writer.write("email=" + URLEncoder.encode(params[3], "UTF-8") + "&");
writer.write("password=" + URLEncoder.encode(params[4], "UTF-8") + "&");
writer.write("rollnumber=" + URLEncoder.encode(params[5], "UTF-8") + "&");
writer.close();
InputStreamReader reader = new InputStreamReader(con.getInputStream());
char[] buf = new char[1024];
StringBuilder sb = new StringBuilder();
int len = 0;
while((len = reader.read(buf)) >0)
sb.append(buf, 0, len);
reader.close();
return sb.toString();
catch (Exception ex)
return null;
@Override
protected void onPostExecute(String result)
try
JSONObject jsonObject = new JSONObject(result);
boolean success = jsonObject.getBoolean("success");
if(success)
String message = jsonObject.getString("message");
Intent i = new Intent(_act, HomeActivity.class);
_act.startActivity(i);
Toast.makeText(_act, message, Toast.LENGTH_SHORT).show();
else
String message = jsonObject.getString("message");
Toast.makeText(_act, message, Toast.LENGTH_SHORT).show();
catch (JSONException e)
e.printStackTrace();
_pb.setVisibility(ProgressBar.INVISIBLE);
@Override
protected void onPreExecute()
_pb.setVisibility(ProgressBar.VISIBLE);
@Override
protected void onProgressUpdate(Void... values)
【讨论】：
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