考虑在你的配置中定义一个“javax.persistence.EntityManager”类型的bean
Posted
技术标签:
【中文标题】考虑在你的配置中定义一个“javax.persistence.EntityManager”类型的bean【英文标题】:Consider defining a bean of type 'javax.persistence.EntityManager' in your configuration 【发布时间】:2020-08-01 16:59:20 【问题描述】:我是春天的初学者。所以现在我开始学习spring boot并构建这个简单的项目,但是当我运行它时,我得到了这个错误“ sagala.rest.boot.remade.dao.EmployeeDaoImpl 中的字段 entityManager 需要一个找不到的 'javax.persistence.EntityManager' 类型的 bean。”。
这是我的控制器类
package sagala.rest.boot.remade.controller;
import java.util.List;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.web.bind.annotation.GetMapping;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RestController;
import sagala.rest.boot.remade.entity.Employee;
import sagala.rest.boot.remade.service.EmployeeService;
@RestController
@RequestMapping("/api")
public class MainController
@Autowired
private EmployeeService employeeService;
@GetMapping("/employees")
public List<Employee> findAll()
return employeeService.findAll();
这里是服务类
package sagala.rest.boot.remade.service;
import java.util.List;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Service;
import org.springframework.transaction.annotation.Transactional;
import sagala.rest.boot.remade.dao.EmployeeDao;
import sagala.rest.boot.remade.entity.Employee;
@Service
public class EmployeeServiceImpl implements EmployeeService
@Autowired
private EmployeeDao employeeDao;
@Override
@Transactional
public List<Employee> findAll()
return employeeDao.findAll();
这是 DAO 类
package sagala.rest.boot.remade.dao;
import java.util.List;
import javax.persistence.EntityManager;
import org.hibernate.Session;
import org.hibernate.query.Query;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Repository;
import sagala.rest.boot.remade.entity.Employee;
@Repository
public class EmployeeDaoImpl implements EmployeeDao
@Autowired
private EntityManager entityManager;
@Override
public List<Employee> findAll()
Session session =entityManager.unwrap(Session.class);
Query<Employee> query =session.createQuery("from Employee", Employee.class);
List<Employee> employees =query.getResultList();
return employees;
这里是实体类
package sagala.rest.boot.remade.entity;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;
@Entity
@Table(name="employee")
public class Employee
@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
@Column(name="id")
private int id;
@Column(name="first_name")
private String firstName;
@Column(name="last_name")
private String lastName;
@Column(name="email")
private String email;
public Employee()
public Employee(String firstName, String lastName, String email)
this.firstName = firstName;
this.lastName = lastName;
this.email = email;
public int getId()
return id;
public void setId(int id)
this.id = id;
public String getFirstName()
return firstName;
public void setFirstName(String firstName)
this.firstName = firstName;
public String getLastName()
return lastName;
public void setLastName(String lastName)
this.lastName = lastName;
public String getEmail()
return email;
public void setEmail(String email)
this.email = email;
这是 POM 文件
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0
https://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<parent>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-parent</artifactId>
<version>2.2.6.RELEASE</version>
<relativePath/> <!-- lookup parent from repository -->
</parent>
<groupId>sagala</groupId>
<artifactId>rest.boot.remade</artifactId>
<version>0.0.1-SNAPSHOT</version>
<name>rest.boot.remade</name>
<description>Demo project for Spring Boot</description>
<properties>
<java.version>1.8</java.version>
<maven-jar-plugin.version>3.1.1</maven-jar-plugin.version>
</properties>
<dependencies>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-data-jpa</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-web</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-devtools</artifactId>
<scope>runtime</scope>
<optional>true</optional>
</dependency>
<dependency>
<groupId>mysql</groupId>
<artifactId>mysql-connector-java</artifactId>
<scope>runtime</scope>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-test</artifactId>
<scope>test</scope>
<exclusions>
<exclusion>
<groupId>org.junit.vintage</groupId>
<artifactId>junit-vintage-engine</artifactId>
</exclusion>
</exclusions>
</dependency>
</dependencies>
<build>
<plugins>
<plugin>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-maven-plugin</artifactId>
</plugin>
</plugins>
</build>
</project>
这是应用程序属性
spring.datasource.url=jdbc:mysql://localhost:3306/employee_directory?useSSL=false&serverTimezone=UTC spring.datasource.username=spring******* spring.datasource.password=spring*******
如果有人可以帮助我。谢谢
【问题讨论】:
您应该使用@PersistenceContext
而不是@Autowired
。请通过这个问题***.com/q/31335211/7458887。
已经试过了,但还是不行。
【参考方案1】:
我将 Spring Boot 版本从 2.2.6 更改为 2.1.13,一切正常。似乎 javax.persistence.EntityManager 在较新的 Spring Boot 版本中已损坏。即使多次删除 repo,当我尝试将其扩展为另一种替代 dao 实现时,我仍然找不到 JpaRepository 接口。
【讨论】:
以上是关于考虑在你的配置中定义一个“javax.persistence.EntityManager”类型的bean的主要内容,如果未能解决你的问题,请参考以下文章
考虑在你的配置中定义一个“javax.persistence.EntityManager”类型的bean