Spring Security 登录错误：HTTP 状态 404 - /j_spring_security_check

Posted 2023-02-26

【中文标题】Spring Security 登录错误：HTTP 状态 404 - /j_spring_security_check

【英文标题】：Spring Security Login Error : HTTP Status 404 - /j_spring_security_check

【发布时间】：2013-10-14 03:53:21

【问题描述】：

您好，我正在尝试在我的应用程序上配置 spring 安全性。但是一旦我输入用户名和密码并提交表单，我就会收到错误

HTTP Status 404 - /j_spring_security_check The requested resource is not available.

以下是我的配置文件：

web.xml

<filter-mapping>
    <filter-name>CharacterEncodingFilter</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

<filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>

<filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>   

<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/applicationContext.xml,/WEB-INF/taskTracker-app.xml,/WEB-INF/taskTracker-servlet.xml,/WEB-INF/taskTracker-security.xml</param-value>
</context-param>

<servlet>
    <servlet-name>taskTracker</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>2</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>taskTracker</servlet-name>
    <url-pattern>*.html</url-pattern>
</servlet-mapping>

taskTracker-servlet.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:tx="http://www.springframework.org/schema/tx"
    xmlns:aop="http://www.springframework.org/schema/aop" xmlns:dwr="http://www.directwebremoting.org/schema/spring-dwr"
    xsi:schemaLocation="http://www.springframework.org/schema/beans 
 http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
 http://www.springframework.org/schema/aop 
 http://www.springframework.org/schema/aop/spring-aop-3.0.xsd 
 http://www.springframework.org/schema/tx
 http://www.springframework.org/schema/tx/spring-tx-3.0.xsd 
 http://www.directwebremoting.org/schema/spring-dwr
 http://www.directwebremoting.org/schema/spring-dwr-2.0.xsd">

    <bean id="TaskTrackerLoginController"
        class="org.springframework.web.servlet.mvc.ParameterizableViewController">
        <property name="viewName">
            <value>/taskTracker/sign-in</value>
        </property>
    </bean>

    <bean id="TaskTrackerErrorController"
        class="org.springframework.web.servlet.mvc.ParameterizableViewController">
        <property name="viewName">
            <value>/taskTracker/error</value>
        </property>
    </bean>

    <bean id="WelcomeController" class="com.tracker.web.controllers.WelcomeController">
        <property name="BusinessLogic">
            <ref bean="BusinessLogic" />
        </property>
        <property name="viewName">
            <value>/taskTracker/welcome</value>
        </property>
    </bean>

    <bean id="nonSecurePageMappings"
        class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
        <property name="mappings">
            <props>
                <prop key="/taskTracker/sign-in.html">TaskTrackerLoginController</prop>
                <prop key="/taskTracker/error.html">TaskTrackerErrorController</prop>
            </props>
        </property>
    </bean>
    <bean id="PageMappings"
        class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
        <property name="mappings">
            <props>

                <prop key="/taskTracker/welcome.html">WelcomeController</prop>

            </props>
        </property>
    </bean>

    <bean id="viewResolver"
        class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="viewClass">
            <value>org.springframework.web.servlet.view.JstlView</value>
        </property>
        <property name="prefix">
            <value>/WEB-INF/jsp/</value>
        </property>
        <property name="suffix">
            <value>.jsp</value>
        </property>
    </bean>
</beans>

taskTracker-security.xml

<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:security="http://www.springframework.org/schema/security"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
                        http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
                        http://www.springframework.org/schema/security
                        http://www.springframework.org/schema/security/spring-security-3.0.xsd">

    <bean id="SecurityService" class="com.tracker.web.security.SecurityService">
        <property name="BusinessLogic">
            <ref bean="BusinessLogic" />
        </property>
    </bean>

    <security:http access-denied-page="/taskTracker/tracker/error.html" auto-config="false">
        <security:session-management invalid-session-url="/taskTracker/sign-in.html">
        </security:session-management>
        <security:form-login login-page="/taskTracker/sign-in.html" default-target-url="/taskTracker/welcome.html"
            always-use-default-target="false" authentication-failure-url="/taskTracker/sign-in.html?error=1" />
        <security:logout invalidate-session="true" logout-success-url="/taskTracker/sign-in.html" />
        <security:intercept-url pattern="/taskTracker/sign-in.html*" filters="none" />
        <security:intercept-url pattern="/taskTracker/welcome.html*" />
    </security:http>

    <security:authentication-manager>
        <security:authentication-provider user-service-ref="SecurityService" />
    </security:authentication-manager>

</beans> 

taskTracker-app.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:tx="http://www.springframework.org/schema/tx"
    xmlns:aop="http://www.springframework.org/schema/aop" xmlns:dwr="http://www.directwebremoting.org/schema/spring-dwr"
    xsi:schemaLocation="http://www.springframework.org/schema/beans 
 http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
 http://www.springframework.org/schema/aop 
 http://www.springframework.org/schema/aop/spring-aop-3.0.xsd 
 http://www.springframework.org/schema/tx
 http://www.springframework.org/schema/tx/spring-tx-3.0.xsd 
 http://www.directwebremoting.org/schema/spring-dwr
 http://www.directwebremoting.org/schema/spring-dwr-2.0.xsd">

    <bean id="userDao" class="com.tracker.data.dao.jdbc.UserJdbcDao">
        <property name="dataSource">
            <ref bean="dataSource" />
        </property>
    </bean>

    <bean id="BusinessLogic" class="com.tracker.business.logic.TrackerBusinessLogicImpl">
        <property name="userLogic">
            <ref bean="userLogic" />
        </property>
    </bean>

    <bean id="userLogic" class="com.tracker.business.logic.user.UserLogic">
        <property name="userDao">
            <ref bean="userDao" />
        </property>
    </bean>
</beans>

SecurityService.java

package com.tracker.web.security;

import org.apache.log4j.Logger;
import org.springframework.dao.DataAccessException;
import org.springframework.security.core.userdetails.UserDetails;
import org.springframework.security.core.userdetails.UserDetailsService;
import org.springframework.security.core.userdetails.UsernameNotFoundException;

import com.tracker.business.logic.TrackerBusinessLogic;
import com.tracker.business.model.User;

public class SecurityService implements UserDetailsService 
    private final static Logger log = Logger.getLogger(SecurityService.class);
    private TrackerBusinessLogic trackerBusinessLogic;

    public UserDetails loadUserByUsername(String username)
            throws UsernameNotFoundException, DataAccessException 

        String errMsg = "User with username: " + username;

        User user = trackerBusinessLogic.loadUser(username);
        if(user!=null) 
            // user has been loaded
         else 
            log.error("User with username: " + username + " not found");
        
        return user;
    

    public TrackerBusinessLogic getBusinessLogic() 
        return trackerBusinessLogic;
    

    public void setBusinessLogic(TrackerBusinessLogic trackerBusinessLogic) 
        this.trackerBusinessLogic = trackerBusinessLogic;
    

sign-in.jsp

<html lang="en-US">
<head>
    <title>Login</title>
</head>
<body>
<div class="login">
    <h1>Task Tracker Login</h1>
    <form action="/j_spring_security_check" method="post">
        <input type="text" name="j_username" value="" placeholder="Username" required="required" />
        <input type="password" name="j_password" placeholder="Password" required="required" />
        <input type="hidden" name="referrer" value="$param.referrer" />
        <input type="submit" value="Let me in." class="btn btn-primary btn-block btn-large">
    </form>
</div>
</body> 
</html>

请帮我解决我在这里缺少的东西。谢谢。

【参考方案1】：

与此特定问题无关（但与“j_spring_security_check 404”问题有关）。认为它可能会帮助任何试图用 spring 4 解决相同问题的人，即使所有设置都是正确的。

从 Spring 4 开始，spring 默认启用 csrf，所以首先检查 csrf 是否禁用，如果这解决了“j_spring_security_check 404”问题。

<http>
    <!-- ... -->
    <csrf disabled="true"/>
</http>

这只是为了测试，如果它确实有效，那么再次启用它，因为现在禁用 csrf 对于 web-app 来说不是一个好主意。所以删除那个

<csrf disabled="true" />

行（'coz crsf 默认启用），并在您的身份验证输入表单中添加一个 csrf 令牌字段：

<form action="$loginUrl" method="post">
    <input ... />
    <input type="hidden" name="$_csrf.parameterName" value="$_csrf.token"/>
</form>   

或

<form action="$loginUrl?$_csrf.parameterName=$_csrf.token" method="post"> .... </form>

【参考方案2】：

我在 /j_spring_security_check 之前添加 $request.contextPath 时修复了该错误

【参考方案3】：

在您的sign-in.jsp中，您需要更改您提交登录请求的URL，您可以实现如下：

<c:url value="/j_spring_security_check" var="loginUrl" />

并在您的表单操作中使用它：

<form action="$loginUrl" method="post">

login-processing-url 属性默认为 /j_spring_security_check，并指定登录表单（应包括 username 和 password）应使用 HTTP 帖子提交到的 URL。

【讨论】：

你有这个<%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c"%>添加到你的jsp吗？

非常感谢...现在提交时，我得到localhost:8080/TaskTracker/taskTracker/sign-in.html?error=1，这意味着正在调用该操作并返回此 URL 以表示登录尝试失败...但问题是我尝试登录使用确实存在的用户名和密码..那么为什么登录失败？

是不是因为数据库连接失败。但如果是这种情况，我会在控制台日志中出现 JDBC 异常，但我没有收到任何错误。

从trackerBusinessLogic 加载UserDetails 时可能会出现一些问题。

不.. 他们不是。在我的回答中，我使用 'c:url' 将相对 URL 转换为应用程序上下文的 url。