当我尝试在 android 中使用 Mandrill SMTP 发送电子邮件时出错
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【中文标题】当我尝试在 android 中使用 Mandrill SMTP 发送电子邮件时出错【英文标题】:Error when I trying to send email with Mandrill SMTP in android 【发布时间】:2015-09-07 00:29:45 【问题描述】:我在运行我的应用时使用 android Studio 1.2 API Mandrill 响应并出现此错误
"status":"error","code":-1,"name":"ValidationError","message":"You must specify a message value"
当我检查我的对象 paramsArr 似乎还可以,但我认为可能是我错过了一些属性或者我的 paramsArr 没有正确的结构。
这是 paramsArr 的结构:
["key":"mykey","message":["html":"ghgh","text":"test","to":["email":"mymail@gmail.com","name":"person","type":"to"],"from_email":"mymail@gmail.com","from_name":"person","subject":"erer"],"async":false]
分级:
compileSdkVersion 21
buildToolsVersion '22.0.1'
minSdkVersion 16
targetSdkVersion 21
AndroidManifest.xml:
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
发送邮件的函数
public void SendEmail(View view)
try
JSONArray paramsArr = new JSONArray();
JSONArray paramsArr1 = new JSONArray();
JSONArray paramsArr2 = new JSONArray();
JSONObject object = new JSONObject();
object.put("key", "mykey");
JSONObject arrayElementTo = new JSONObject();
arrayElementTo.put("email","mymail@gmail.com");
arrayElementTo.put("name", "person");
arrayElementTo.put("type", "to");
paramsArr1.put(arrayElementTo);
JSONObject arrayElementMessage = new JSONObject();
arrayElementMessage.put("html", "ghgh");
arrayElementMessage.put("text", "test");
arrayElementMessage.put("to",paramsArr1);
arrayElementMessage.put("from_email", "mymail@gmail.com");
arrayElementMessage.put("from_name", "person");
arrayElementMessage.put("subject", "erer");
paramsArr2.put(arrayElementMessage);
object.put("message",paramsArr2);
object.put("async", false);
paramsArr.put(object);
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("https://mandrillapp.com/api/1.0/messages/send.json");
StringEntity params = new StringEntity(paramsArr.toString());
httppost.setHeader("Content-type", "application/json");
httppost.setEntity(params);
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
String responseString = EntityUtils.toString(entity, "UTF-8");
catch (Exception e)
Toast toast = Toast.makeText(getApplicationContext(), "error",
Toast.LENGTH_SHORT);
toast.show();
【问题讨论】:
【参考方案1】:问题出在我的参数json ["key":"mykey","message":["html":"ghgh","text":"test","to":["email":"mymail@gmail.com","name":"person","type":"to"],"from_email":"mymail@gmail.com","from_name":"person","subject":"erer"],"async":false]
的结构中
正确的结构是
"key":"mykey","message":"html":"ghgh","text":"test","to":["email":"mymail@gmail.com","name":"person","type":"to"],"from_email":"mymail@gmail.com","from_name":"person","subject":"erer","async":false
通过此功能,您可以使用此服务从 android 发送和发送电子邮件,我测试过,效果很好。
【讨论】:
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