在 xcode 8 中登录的 UI 测试
Posted
技术标签:
【中文标题】在 xcode 8 中登录的 UI 测试【英文标题】:UITesting for login in xcode8 【发布时间】:2016-12-20 10:48:46 【问题描述】:我正在使用 UITesting,因为我必须使用保存的 NSUserDefaults 值来测试电子邮件字段和密码。请给我一些代码。
注意:1.检查电子邮件和密码字段是否有效或无效或为空。
【问题讨论】:
你有电子邮件和密码字段验证码吗?? 是的,但是验证是在 uitesting 中完成的。 【参考方案1】:使用以下代码从文本字段中获取文本并验证它们。
let app = XCUIApplication()
let nameTextField = app.textFields.element(boundBy: 0)
// based on index you can get text field.
nameTextField.typeText("userName")
let passwordTextField = app.textFields.element(boundBy: 1)
// it returns the password field.
passwordTextField.typeText("password")
let userName : String = nameTextField.value
// returns the text in text field.
let password : String = passwordTextField.value
if userName.isEmpty || password.isEmpty
print("Text fields are empty");
else
let validateButton = app.buttons.element(boundsBy: 0)
validateButton.tap()
如果存在任何警报,请稍后检查条件。如果存在您的信用卡错误。否则等待下一个 XCUIElement。使用此代码等待
let existsPredicate = NSPredicate(format: "exists == true")
expectation(for: existsPredicate,
evaluatedWith: element, handler: nil)
waitForExpectations(timeout: 20, handler: nil)
【讨论】:
Reddy,你的答案是我的答案,但我试过了,它有问题,你能指导我吗.....【参考方案2】:@interface NSString (emailValidation)
- (BOOL)isValidEmail;
@end
实现
@implementation NSString (emailValidation)
-(BOOL)isValidEmail
BOOL stricterFilter = NO; // Discussion http://blog.logichigh.com/2010/09/02/validating-an-e-mail-address/
NSString *stricterFilterString = @"^[A-Z0-9a-z\\._%+-]+@([A-Za-z0-9-]+\\.)+[A-Za-z]2,4$";
NSString *laxString = @"^.+@([A-Za-z0-9-]+\\.)+[A-Za-z]2[A-Za-z]*$";
NSString *emailRegex = stricterFilter ? stricterFilterString : laxString;
NSPredicate *emailTest = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", emailRegex];
return [emailTest evaluateWithObject:self];
@end
密码验证
-(void)textFieldDidEndEditing:(UITextField *)textField
int numberofCharacters = 0;
BOOL lowerCaseLetter,upperCaseLetter,digit,specialCharacter = 0;
if([textField.text length] >= 10)
for (int i = 0; i < [textfield.text length]; i++)
unichar c = [textfield.text characterAtIndex:i];
if(!lowerCaseLetter)
lowerCaseLetter = [[NSCharacterSet lowercaseLetterCharacterSet] characterIsMember:c];
if(!upperCaseLetter)
upperCaseLetter = [[NSCharacterSet uppercaseLetterCharacterSet] characterIsMember:c];
if(!digit)
digit = [[NSCharacterSet decimalDigitCharacterSet] characterIsMember:c];
if(!specialCharacter)
specialCharacter = [[NSCharacterSet symbolCharacterSet] characterIsMember:c];
if(specialCharacter && digit && lowerCaseLetter && upperCaseLetter)
//do what u want
else
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Error"
message:@"Please Ensure that you have at least one lower case letter, one upper case letter, one digit and one special character"
delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alert show];
else
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Error"
message:@"Please Enter at least 10 password"
delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alert show];
【讨论】:
,感谢您的出色回答,但我的要求不是这个。【参考方案3】:在 NSUserDefaults 中存储电子邮件和密码:
[[NSUserDefaults standardUserDefaults] setObject:@"sam.martin105@gmail.com" forKey:@"Email"];
[[NSUserDefaults standardUserDefaults] setObject:@"123456Sam@" forKey:@"Password"];
电子邮件验证:
-(BOOL)NSStringIsValidEmail:(NSString *)checkString
BOOL stricterFilter = NO;
NSString *stricterFilterString = @"^[A-Z0-9a-z\\._%+-]+@([A-Za-z0-9-]+\\.)+[A-Za-z]2,4$";
NSString *laxString = @"^.+@([A-Za-z0-9-]+\\.)+[A-Za-z]2[A-Za-z]*$";
NSString *emailRegex = stricterFilter ? stricterFilterString : laxString;
NSPredicate *emailTest = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", emailRegex];
return [emailTest evaluateWithObject:checkString];
强密码验证:
- (BOOL)strongPassword:(NSString *)yourText
BOOL strongPwd = YES;
//Checking length
if([yourText length] < 8)
strongPwd = NO;
//Checking uppercase characters
NSCharacterSet *charSet = [NSCharacterSet uppercaseLetterCharacterSet];
NSRange range = [yourText rangeOfCharacterFromSet:charSet];
if(range.location == NSNotFound)
strongPwd = NO;
//Checking lowercase characters
charSet = [NSCharacterSet lowercaseLetterCharacterSet];
range = [yourText rangeOfCharacterFromSet:charSet];
if(range.location == NSNotFound)
strongPwd = NO;
//Checking special characters
charSet = [[NSCharacterSet alphanumericCharacterSet] invertedSet];
range = [yourText rangeOfCharacterFromSet:charSet];
if(range.location == NSNotFound)
strongPwd = NO;
return strongPwd;
检查验证电子邮件或密码,如果成功则登录,否则您可以显示警报:
-(IBAction)Login:(id)sender
NSString *Email = [[NSUserDefaults standardUserDefaults]objectForKey:@"Email"];
NSString *Password = [[NSUserDefaults standardUserDefaults]objectForKey:@"Password"];
BOOL flagEmail,flagPassword = false;
if(![Email isEqualToString:@""])
flagEmail = [self NSStringIsValidEmail:Email];
if(flagEmail)
NSLog(@"Email is accepted");
else
NSLog(@"Email is not valid");
else
NSLog(@"Email is empty");
if(![Password isEqualToString:@""])
flagPassword = [self strongPassword:Password];
if(flagPassword)
NSLog(@"Password is accepted");
else
NSLog(@"Password is not valid");
else
NSLog(@"Password is empty");
if(flagEmail && flagPassword)
NSLog(@"Email and password both are valid and not empty");
【讨论】:
请阅读我的问题并回答这不是我的要求,我必须验证 UITesting 中的电子邮件和密码文本字段。 在我的项目中,我必须编写一个测试用例来验证文本字段 我认为这个链接会对你有所帮助:***.com/questions/23613698/… 感谢@amit_donga 我检查了那个链接,这很有用,如果我得到一段代码来处理这个操作就足够了,非常感谢。以上是关于在 xcode 8 中登录的 UI 测试的主要内容,如果未能解决你的问题,请参考以下文章
Xcode 11.1 尝试在 Safari 浏览器的登录屏幕中记录以编写 UI 测试时崩溃
使用 arc4random 生成随机数以添加到字符串以进行 UI 测试登录 xcode UI 测试