如何在 Alamofire 中请求带有正文和标头的 JSON？
Posted
技术标签:
【中文标题】如何在 Alamofire 中请求带有正文和标头的 JSON？【英文标题】：How to request JSON with body and header in Alamofire? 【发布时间】：2017-07-19 10:23:52 【问题描述】：我曾尝试使用以下代码进行请求，但结果出现 400 错误。 API 由 header 和 body 组成。标头有两个字段，即“授权”和“内容类型”。正文格式已添加到下面的参数中。
func file( sender: abc)
let baseUrl = "url”
let params: [String : Any] = [
"profile": [
“Type": [
" Real Estate",
"Estater",
"Construction",
"Entertainment"
],
"Size": [
"large",
“small”
],
"Level": [
“A”,
“B”
],
“Name” : [
“John”,
“Harry”
]
]
]
let header = [
"Authorization" : "bearer e2ff3aa3-63a3-41d1-bc5a-3e8c88adeaaa",
"Content-Type" : "application/json"
]
// var request = URLRequest(url: URL(string:baseUrl)!)
// request.httpMethod = HTTPMethod.post.rawValue
// request.setValue("application/json", forHTTPHeaderField: "Content-Type")
// request.addValue("bearer e2ff3aa3-63a3-41d1-bc5a-3e8c88adeaaa", forHTTPHeaderField: "Authorization")
// let data = try! JSONSerialization.data(withJSONObject: params as Any, options:JSONSerialization.WritingOptions.prettyPrinted)
//
// request.httpBody = data
Alamofire.request("\(baseUrl)", method: .post, parameters: params, headers:header).responseJSON response in
print(response.request ?? "no request") // original URL requ est
print(response.response ?? "no response") // HTTP URL response
print(response.data ?? "no data") // server data
print(response.result) // result of response serialization
print(response.response?.statusCode ?? "noCode")
if(response.response?.statusCode != nil)
switch response.response!.statusCode
case 200:
print("Success")
let json = JSON(data: response.data!)
print(json)
sender.onSuccessCall()
case 400:
print("Error in authentication")
case 401:
print("Error authentication object was not found")
default:
print("dEfault")
请帮忙解决这个问题。
【问题讨论】：
我们不知道你的 api 想要你做什么 我只想通过 post 请求获取 JSON 数据，但它显示 400 错误。我的代码有错误吗？ 在不知道您的 API 期望什么的情况下，我们无能为力。请在您的问题中包含一个成功的请求，即使它不是来自 swift（即 Postman 请求、curl 请求等）。 如果响应中出现错误，甚至在 seding 数据之前我们也无能为力，信息太少 请尝试使用我的代码，看看它对我来说非常适合我已经用我的 magento api 测试过 【参考方案1】：我解决了问题，下面添加了正确的方法。
func file( sender: abc)
let params: [String : Any] = [
"profile": [
“Type": [
" Real Estate",
"Estater",
"Construction",
"Entertainment"
],
"Size": [
"large",
“small”
],
"Level": [
“A”,
“B”
],
“Name” : [
“John”,
“Harry”
]
]
]
var request = URLRequest(url: URL(string:”url string”)!)
request.httpMethod = HTTPMethod.post.rawValue
request.setValue("bearer 5bac059b-eb2b-4e1b-914a-9de5b6a58577", forHTTPHeaderField: "Authorization")
request.setValue("application/json", forHTTPHeaderField: "Content-Type")
let data = try! JSONSerialization.data(withJSONObject: params as Any, options:JSONSerialization.WritingOptions.prettyPrinted)
let json = NSString(data: data, encoding: String.Encoding.utf8.rawValue)
print(json!)
request.httpBody = json!.data(using: String.Encoding.utf8.rawValue)
Alamofire.request(request).responseJSON response in
print(response.request ?? "no request") // original URL requ est
print(response.response ?? "no response") // HTTP URL response
print(response.data ?? "no data") // server data
print(response.result) // result of response serialization
print(response.response?.statusCode ?? "noCode")
if(response.response?.statusCode != nil)
switch response.response!.statusCode
case 200:
print("Success")
let json = JSON(data: response.data!)
print(json)
sender.onSuccessCall()
case 400:
print("Error in authentication")
case 401:
print("Error authentication object was not found")
default:
print("dEfault")
【讨论】：
【参考方案2】：请试试这个代码
let urlString = String(format : "Your URL" )
let params: [String : Any] = [
"profile": [
"Type": [
" Real Estate",
"Estater",
"Construction",
"Entertainment"
],
"Size": [
"large",
"small"
],
"Level": [
"A",
"B"
],
"Name" : [
"John",
"Harry"
]
]
]
print(params)
let url = URL(string: urlString)!
let data = try! JSONSerialization.data(withJSONObject: params, options: JSONSerialization.WritingOptions.prettyPrinted)
let json = NSString(data: data, encoding: String.Encoding.utf8.rawValue)
if let json = json
print(json)
let jsonData = json!.data(using: String.Encoding.utf8.rawValue);
var request = URLRequest(url: url)
request.httpMethod = HTTPMethod.post.rawValue
request.setValue("application/json; charset=UTF-8", forHTTPHeaderField: "Content-Type")
request.setValue("bearer e2ff3aa3-63a3-41d1-bc5a3e8c88adeaaa",forHTTPHeaderField: "Authorization")
request.httpBody = jsonData
Alamofire.request(request).responseJSON
(response) in
switch response.result
case .success(let JSON):
print("Success with JSON: \(JSON)")
break
case .failure(let error):
print("Request failed with error: \(error)")
//callback(response.result.value as? NSMutableDictionary,error as NSError?)
break
.responseString response in
print("Response String: \(response.result.value)")
【讨论】：
【参考方案3】：有时我们需要 URLEncoding.httpBody 类型作为 post 方法希望它可以帮助你和
let headers = [
// "Content-Type": "application/x-www-form-urlencoded" // try this if its ok then use this otherwise use "application/json"
// "Content-Type" : "application/json"
]
let parameters = [
]
Alamofire.request("urlString", method: .post, parameters: parameters, encoding: URLEncoding.httpBody, headers: headers).responseJSON (response:DataResponse<Any>) in
switch(response.result)
case.success(let data):
print("success",data)
case.failure(let error):
print("Not Success",error)
self.view.makeToast(message: "Server Error!!")
【讨论】：
你把“Authorization”：“bearer e2ff3aa3-63a3-41d1-bc5a-3e8c88adeaaa”放在带有内容类型的标题中并尝试了这个 是的，我试过了，但是不行。我也试过这个代码 request.setValue("application/json", forHTTPHeaderField: "Content-Type" request.addValue("bearer e2ff3aa3-63a3-41d1-bc5a-3e8c88adeaaa", forHTTPHeaderField: "Authorization" 去 alamofire github 并尝试从他们更改 urlEncoding 类型，它们是关于 urlEncoding 的参考，有时我们的 urlEncoding 似乎不适用于 post 方法类型 让 params :Parameters = [ ] 在参数中尝试一次：[String : Any] 我认为它的问题在标头请求中。【参考方案4】：使用URLConvertible在baseUrl中输入url
解决方法如下：
func file( sender: abc)
let baseU = URL(string:"url")
let baseUrl = baseU as! URLConvertible
let params: [String : Any] = [
"profile": [
"Type": [
" Real Estate",
"Estater",
"Construction",
"Entertainment"
],
"Size": [
"large",
"small"
],
"Level": [
"A",
"B"
],
"Name" : [
"John",
"Harry"
]
]
]
let header = [
"Authorization" : "bearer e2ff3aa3-63a3-41d1-bc5a-3e8c88adeaaa",
"Content-Type" : "application/json"
]
// var request = URLRequest(url: URL(string:baseUrl)!)
// request.httpMethod = HTTPMethod.post.rawValue
// request.setValue("application/json", forHTTPHeaderField: "Content-Type")
// request.addValue("bearer e2ff3aa3-63a3-41d1-bc5a-3e8c88adeaaa", forHTTPHeaderField: "Authorization")
// let data = try! JSONSerialization.data(withJSONObject: params as Any, options:JSONSerialization.WritingOptions.prettyPrinted)
//
// request.httpBody = data
Alamofire.request(baseUrl, method: .post, parameters: params, headers:header).responseJSON response in
print(response.request ?? "no request") // original URL requ est
print(response.response ?? "no response") // HTTP URL response
print(response.data ?? "no data") // server data
print(response.result) // result of response serialization
print(response.response?.statusCode ?? "noCode")
if(response.response?.statusCode != nil)
switch response.response!.statusCode
case 200:
print("Success")
let json = JSON(data: response.data!)
print(json)
sender.onSuccessCall()
case 400:
print("Error in authentication")
case 401:
print("Error authentication object was not found")
default:
print("dEfault")
【讨论】：
谢谢，@Sakir Sherasiya。我试过了，但没用。 API 调用后。 我知道。我的意思是如果传递错误的 json 那么你就对了？ 让我们continue this discussion in chat.以上是关于如何在 Alamofire 中请求带有正文和标头的 JSON？的主要内容，如果未能解决你的问题，请参考以下文章
Alamofire POST 请求，正文中有一个简单的字符串作为参数，标头仍然显示缺少的参数值