PHP/MySQL/PDO - 结果错误但没有数据库错误消息？

Posted 2023-02-24

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【中文标题】PHP/MySQL/PDO - 结果错误但没有数据库错误消息？【英文标题】：PHP/MySQL/PDO - results false but no DB error message? 【发布时间】：2011-09-17 11:28:15 【问题描述】：

我有一大段代码执行得很奇怪。有时它起作用，有时它不起作用。服务器有一个绝对古老的 php 副本（5.1.6，五年前，但带有由 Red Hat 手动向后移植的安全补丁）。

这是代码，包括我目前在其中的调试行：

<?php
// Includes json_print, which does a json_encode, an 
// appropriate content-type header, prints it, and exits the script.
include_once('json-functions.php');

$uid = $_POST['uid'];

$salted = false;

if(isset($_POST['salted'])) $salted = true; 

// No uid given.
if(is_null($uid) || $uid === '')
        $details = array(
            'error' => 1,
            'errorMessage' => 'No unique ID entered.  Please try again.',
        );
        json_print($details);


// Validate uid.  Must be 64 digit hexadecimal value.
$pattern = '/^[a-f0-9]64$/i';
if(preg_match($pattern, $uid) === 0)
        $details = array(
            'error' => 2,
            'errorMessage' => 'Invalid unique ID.',
        );
        json_print($details);



include_once('../db.php');

header('Content-Type: text/plain');

// Is this salted already?
var_dump($salted);

// What's the UID?
var_dump($uid);

if(!$salted) $uid = hash('sha256', $salt.$uid); 

// Was the UID salted?  (shouldn't be double-salted)
var_dump($uid);

// The query
$SQL = 'SELECT ';

    $SQL .= 'p.patronID AS patronID, ';
    $SQL .= 'uniqueID, ';
    $SQL .= 'status, ';
    $SQL .= 'active, ';
    $SQL .= 'd.name AS department, ';
    $SQL .= 'docdelivery, ';
    $SQL .= 'terms, ';
    $SQL .= 'copyright, ';
    $SQL .= 'lastLogin, ';
    $SQL .= 'updated, ';
    $SQL .= 'TIMESTAMPDIFF(MINUTE, lastLogin, NOW()) AS recency, ';
    $SQL .= 'DATEDIFF(NOW(), updated) AS stale, ';

    $SQL .= 'AES_DECRYPT(first, ?) AS first, ';
    $SQL .= 'AES_DECRYPT(last, ?) AS last, ';
    $SQL .= 'AES_DECRYPT(barcode, ?) AS barcode, ';
    $SQL .= 'INET_NTOA(AES_DECRYPT(ip, ?)) AS ip, ';
    $SQL .= 'AES_DECRYPT(email, ?) AS email, ';
    $SQL .= 'AES_DECRYPT(phone, ?) AS phone, ';
    $SQL .= 'AES_DECRYPT(address1, ?) AS address1, ';
    $SQL .= 'AES_DECRYPT(address2, ?) AS address2, ';
    $SQL .= 'AES_DECRYPT(city, ?) AS city, ';
    $SQL .= 'AES_DECRYPT(state, ?) AS state, ';
    $SQL .= 'AES_DECRYPT(zip, ?) AS zip ';

$SQL .= 'FROM patrons p, departments d ';
$SQL .= 'WHERE department = d.deptID ';
$SQL .= 'AND uniqueID = ?';

$query = $DB->prepare($SQL);

$p = array(
    $key,
    $key,
    $key,
    $key,
    $key,
    $key,
    $key,
    $key,
    $key,
    $key,
    $key,
    $uid,
);

$query->execute($p);

$result = $query->fetch();

// dump the results
var_dump($result);
print "\n\n";

// And any error info
var_dump($DB->errorInfo());
exit;

这是正常工作时的示例输出：

// Salted is true
bool(true)

// UID is:
string(64) "52223d99e1db275716028cf6fd4f58895b1df7eb8e061cefab346b8ce3cf4ff4"

// It was not double-salted:
string(64) "52223d99e1db275716028cf6fd4f58895b1df7eb8e061cefab346b8ce3cf4ff4"

// Results were:
array(46) 
  ["patronID"]=>
  string(1) "126"
  [0]=>
  string(1) "126"
  ["uniqueID"]=>
  string(64) "52223d99e1db275716028cf6fd4f58895b1df7eb8e061cefab346b8ce3cf4ff4"
  [1]=>
  string(64) "52223d99e1db275716028cf6fd4f58895b1df7eb8e061cefab346b8ce3cf4ff4"
  ["status"]=>
  string(1) "4"
  [2]=>
  string(1) "4"
  ["active"]=>
  string(1) "1"
  [3]=>
  string(1) "1"

  *** snip! ***

  [21]=>
  string(2) "TX"
  ["zip"]=>
  string(5) "78623"
  [22]=>
  string(5) "78623"


// Errors reported?
array(1) 
  [0]=>
  string(5) "00000"

这是失败时的示例输出：

 // Salted is true
bool(true)

// UID is:
string(64) "1d6fa3b897b07301a836f5441d23f60e7cb4b52a00ee6d20648fe51b01c769bf"

// It was not double salted
string(64) "1d6fa3b897b07301a836f5441d23f60e7cb4b52a00ee6d20648fe51b01c769bf"

// Results were:
bool(false)

// Error code was:
array(1) 
  [0]=>
  string(5) "00000"

我不明白为什么它适用于某些 uid，但不适用于其他 uid。此外，在第二个示例中，结果集出现 FALSE，但数据库报告错误 00000，这意味着“没有错误”。我已经检查了查询是否准备妥当，在这两种情况下都是。

我在这里错过了什么？

【问题讨论】：

var_dump($query->error) 在发生故障的地方显示什么？ var_dump($query->error) 为空。也许你在想 $query->errorInfo()，它写着array(1) [0]=> string(5) "00000" 。 【参考方案1】：

尝试直接在数据库上运行查询并检查是否正常。

【讨论】：

我将此标记为答案，因为运行几个测试查询最终让我弄清楚了。我运行的第一个确实有效，因此我的最后一条评论 - 直到后来我用另一个 UID 尝试它时我才发现它。尽管如此，这还是成功了。（...对于那些正在寻找的人，解决方案在下面）。【参考方案2】：

*手掌*

好的，我想通了。查询因此失败：