PHP-解码 JSON
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【中文标题】PHP-解码 JSON【英文标题】：PHP- Decode JSON 【发布时间】：2013-11-05 17:21:53 【问题描述】：我有以下脚本从 API 获取搜索结果，然后对数组进行切片并转储它，我无法将 JSON 解码为数组，它返回 Array(0)
这是一个wordpress简码
这是从 api 获取的 Json 示例：
[
"barcode": "000015426950",
"name": "Karen's cowboy",
"author": "Ann",
"author_last": "Martin",
"publisher": "New York : Scholastic, c2000.",
"year_pub": "",
"edition": "",
"genre": "",
"checkout": "out",
"series": "",
"callnum": "MAR",
"fiction": "true",
"in_house": "false",
"timestamp": "1355835387",
"outto": "000008388615",
"duedate": "1372005722",
"ISBN": "059052528X",
"media_type": "",
"print": "false",
"BOXID": "2147483647",
"uid": "10",
"printed": ""
,
"barcode": "000015426949",
"name": "Karen's yo-yo",
"author": "Ann M",
"author_last": "Martin",
"publisher": "New York : Scholastic, c2000.",
"year_pub": "",
"edition": "",
"genre": "",
"checkout": "out",
"series": "",
"callnum": "MAR",
"fiction": "true",
"in_house": "false",
"timestamp": "1355835343",
"outto": "000008388615",
"duedate": "1373216918",
"ISBN": "0590525115",
"media_type": "",
"print": "false",
"BOXID": "",
"uid": "10",
"printed": ""
,
...
]
这是用于获取 JSON 并对其进行分页的代码：
function book_search_form()
?>
<form method='get'><input type='text' name='searchvalue' value='<? if (isset($_GET['searchvalue'])) echo $_GET['searchvalue'];?>' /> <input type='submit' value='Search' /><input type='hidden' name='pagenum' value='1' /></form>
<br>
<?php
if(isset($_GET['pagenum']) && isset($_GET['searchvalue']))
$page=$_GET['pagenum'];
$searchvalue = $_GET['searchvalue']; // get the value of the page from your url
$recordsPerPage=10; // number of records you want on your page
$api_url = get_option('api_url');
$api_key = get_option('api_key');
$data = file_get_contents("$api_url/book/index.php/name/$searchvalue?key=2513619352");
$array = (array)json_decode($data);
$index=($page*$recordsPerPage)-1;
$recordsToBeDisplayed = array_slice($array,$index,$recordsPerPage);// this array contains all the records you would want to display on a page;
$total_pages=ceil(count($array)/$recordsPerPage);
else
//use default values
?>
<html>...<body><div id="records">
<?
echo '<pre>';
echo $recordsToBeDisplayed;
echo '</pre>';?><!-- use the array created above to display records -->
</div>
<div id="pagination">
<?
for($j=1;$j<=$total_pages;$j++)
if($j==$page)
?>
<li style="display: inline;"><a href="?searchvalue=&pagenum=<?=$j?>"><u><?=$j?></u></a></li>
<?else?>
<li style="display: inline;"><a href="?searchvalue=&pagenum=<?=$j?>"><?=$j?></a></li>
<??>
</div>
<?php
【问题讨论】：
Parsing JSON file with PHP的可能重复 【参考方案1】：如果输入是数组格式，那么你也可以使用相同的函数json_decode。您只需要为结果应用循环。
json = '
"a1": "field1":"name1", "field2":age1, "field3":"country1" ,
"a2": "field1":"name2", "field2":age2, "field3":"country2" ,
"a3": "field1":"name3", "field2":age3, "field3":"country3" ';
$Array = json_decode($json, true);
foreach ($Array as $key => $value)
echo " $key "; foreach ($value as $k => $val) echo "$k | $val <br />";
【讨论】：
【参考方案2】：试试json_decode
$array = json_decode($data, true);
然后你会得到一个数组而不是一个对象。
示例 #1 json_decode() 示例
<?php
$json = '"a":1,"b":2,"c":3,"d":4,"e":5';
var_dump(json_decode($json));
var_dump(json_decode($json, true));
?>
上面的例子会输出：
object(stdClass)#1 (5)
["a"] => int(1)
["b"] => int(2)
["c"] => int(3)
["d"] => int(4)
["e"] => int(5)
array(5)
["a"] => int(1)
["b"] => int(2)
["c"] => int(3)
["d"] => int(4)
["e"] => int(5)
【讨论】：
【参考方案3】：请把你的 php 和 html 分开，使用缩进和：
$array = json_decode($data, TRUE); //second param used for associative array return
Example #1 json_decode() examples
<?php
$json = '"a":1,"b":2,"c":3,"d":4,"e":5';
var_dump(json_decode($json));
var_dump(json_decode($json, true));
?>
The above example will output:
object(stdClass)#1 (5)
["a"] => int(1)
["b"] => int(2)
["c"] => int(3)
["d"] => int(4)
["e"] => int(5)
array(5)
["a"] => int(1)
["b"] => int(2)
["c"] => int(3)
["d"] => int(4)
["e"] => int(5)
P.S：来自圣经 (http://php.net/manual/en/function.json-decode.php)
【讨论】：
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