仅针对 XSL 1.0 中的特定条件列出组内属性的唯一值
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【中文标题】仅针对 XSL 1.0 中的特定条件列出组内属性的唯一值【英文标题】:List unique values of an attribute within a group only for specific criteria in XSL 1.0 【发布时间】:2015-09-06 01:45:46 【问题描述】:当另一个属性具有特定值时,我需要列出组中某个属性的唯一值。在 XSL 1.0 中进行这项工作很难理解。
感谢另一篇文章,我现在定义了分组,以便在属性匹配特定条件时执行计数。但是,我很难仅列出一个特定属性的唯一值,其中另一个属性等于特定值,但仅在当前组的成员中。
与往常一样,这对于示例源数据和代码会更有意义。
这里是示例 XML
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Group1>
<Group2>
<LocationIdentification LocationID="0610390" />
<LocationIdentification1 LocationQualifier="12" LocationID="USLGB"/>
</Group2>
<Group2>
<LocationIdentification LocationID="0610612" />
<LocationIdentification1 LocationQualifier="12" LocationID="USLAX"/>
</Group2>
<Group2>
<LocationIdentification LocationID="0650004"/>
<LocationIdentification1 LocationQualifier="12" LocationID="USLGB"/>
</Group2>
<Group2>
<LocationIdentification LocationID="0650306"/>
<LocationIdentification1 LocationQualifier="6" LocationID="USLAX"/>
</Group2>
<Group2>
<LocationIdentification LocationID="0650220"/>
<LocationIdentification1 LocationQualifier="12" LocationID="USLGB"/>
</Group2>
</Group1>
我已将 XSL 设置为基于 LocationIdentification 节点中 LocationID 属性的前 3 个字符创建组。
XSL 1.0
<xsl:stylesheet version="1.0"
<xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html"/>
<xsl:key name="grp" match="Group2" use="substring(LocationIdentification/@LocationID, 1, 3)"/>
<xsl:template match="/Group1">
<table align="center" border="1">
<thead>
<tr>
<th>Bay</th>
<th>Units</th>
<th>Locations</th>
</tr>
</thead>
<tbody>
<xsl:for-each select="Group2[generate-id()=generate-id(key('grp', substring(LocationIdentification/@LocationID, 1, 3))[1])]">
<xsl:sort select="LocationIdentification/@LocationID"/>
<xsl:variable name="curr-key" select="substring(LocationIdentification/@LocationID, 1, 3)" />
<xsl:variable name="curr-group" select="key('grp', $curr-key)" />
<tr>
<td>
<xsl:value-of select="$curr-key"/>
</td>
<td>
<xsl:value-of select="count($curr-group)"/>
</td>
<td>
<!-- NEW CODE NEEDS TO GO HERE -->
</td>
</tr>
</xsl:for-each>
</tbody>
</table>
</xsl:template>
</xsl:stylesheet>
我需要弄清楚的是如何在 LocationQualifier='12' 的 LocationIdentification1 中列出 LocationID 的唯一值
期望的输出
<table align="center" border="1">
<thead>
<tr>
<th>Bay</th>
<th>Count</th>
<th>Location(s)</th>
</tr>
</thead>
<tbody>
<tr>
<td>061</td>
<td>2</td>
<td>USLGB USLAX</td>
</tr>
<tr>
<td>065</td>
<td>3</td>
<td>USLGB</td>
</tr>
</table>
请注意,Bay 65 的计数为 3,但只有 2 个成员的 LocationQualifier 为 12,并且它们都具有相同的 LocationID 值,因此输出应仅列出位置的 USLGB。
【问题讨论】:
【参考方案1】:你需要再做一轮Muenchian分组:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html"/>
<xsl:key name="grp" match="Group2" use="substring(LocationIdentification/@LocationID, 1, 3)"/>
<xsl:key name="loc12" match="LocationIdentification1[@LocationQualifier='12']" use="concat(substring(../LocationIdentification/@LocationID, 1, 3), '|', @LocationID)"/>
<xsl:template match="/Group1">
<table align="center" border="1">
<thead>
<tr>
<th>Bay</th>
<th>Units</th>
<th>Locations</th>
</tr>
</thead>
<tbody>
<xsl:for-each select="Group2[generate-id()=generate-id(key('grp', substring(LocationIdentification/@LocationID, 1, 3))[1])]">
<xsl:sort select="LocationIdentification/@LocationID"/>
<xsl:variable name="curr-key" select="substring(LocationIdentification/@LocationID, 1, 3)" />
<xsl:variable name="curr-group" select="key('grp', $curr-key)" />
<tr>
<td>
<xsl:value-of select="$curr-key"/>
</td>
<td>
<xsl:value-of select="count($curr-group)"/>
</td>
<td>
<xsl:for-each select="$curr-group/LocationIdentification1[@LocationQualifier='12'][generate-id()=generate-id(key('loc12', concat($curr-key, '|', @LocationID))[1])]">
<xsl:value-of select="@LocationID"/>
<xsl:text> </xsl:text>
</xsl:for-each>
</td>
</tr>
</xsl:for-each>
</tbody>
</table>
</xsl:template>
</xsl:stylesheet>
【讨论】:
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