与 AngularJS 一起使用时,Django 模板不呈现 JSON 响应

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【中文标题】与 AngularJS 一起使用时,Django 模板不呈现 JSON 响应【英文标题】:Django template not rendering JSON response when used with AngularJS 【发布时间】:2016-10-14 14:50:02 【问题描述】:

编辑:已解决

views.py

def post_list(request):
queryset = Post.objects.all()
json_data = serializers.serialize('json', queryset)

context = 
    "jsondata" : json_data,


return render(request,"index.html", context)

index.html

<script src="https://cdnjs.cloudflare.com/ajax/libs/semantic-ui/1.11.8/semantic.min.js"></script>
<script src="http://ajax.googleapis.com/ajax/libs/angularjs/1.4.8/angular.min.js"></script>

<body ng-app="myapp" ng-controller="myctrl">

     jsondata 

    <div class="ui icon input">
        <input type="text" ng-model="search" placeholder="Search skills...">
        <i class="search link icon"></i>
    </div>


    <div class="ui link cards" style="padding:40px">

        <div class="card">

            <div class="image">
                <img class="ui avatar centered image" src="http://1.semantic-ui.com/images/avatar/large/elliot.jpg">
            </div>

            <div class="content">

                <div class="ui small header" ng-repeat="skill in skills | filter:search">
                     skill.fields.post_title
                </div>

                <div class="description">
                     skill.fields.post_content 
                </div>

            </div>
        </div>
    </div>

    <script type="text/javascript">
        var skills_list = " jsondata ";

        var nice_data = JSON.parse(skills_list.replace(/&quot;/g, '"'))

        var very_nice_data = JSON.stringify(nice_data);

        console.log(very_nice_data)
    </script>
    <script>
        angular.module('skillboard', []).controller('searchskills', function ($scope) 
            $scope.skills = very_nice_data;
        );
    </script>
</body>

**very_nice_data** 在控制台的输出是:

[
  
    "model": "posts.post",
    "pk": 1,
    "fields": 
      "post_title": "Algorithms",
      "post_content": "Calling it.",
      "updated_on": "2016-06-12T09:09:45.198Z",
      "timestamp": "2016-04-20T09:44:21.887Z",
      "test_type": "Coding",
      "number_of_questions": 0,
      "test_url": "http://example.com"
    
  ,
  
    "model": "posts.post",
    "pk": 4,
    "fields": 
      "post_title": "Data Structures",
      "post_content": "new content here",
      "updated_on": "2016-06-12T09:09:26.359Z",
      "timestamp": "2016-04-26T06:28:32.569Z",
      "test_type": "Coding",
      "number_of_questions": 0,
      "test_url": "http://example.com"
    
  ,
  
    "model": "posts.post",
    "pk": 11,
    "fields": 
      "post_title": "Dynamic Programming",
      "post_content": "This level of DP is well suited for 2+ yr experience programmers/researchers.",
      "updated_on": "2016-06-12T09:09:16.542Z",
      "timestamp": "2016-06-12T08:44:25.705Z",
      "test_type": "Coding",
      "number_of_questions": 0,
      "test_url": "#"
    
  
]

我正在尝试使用 Angular 将我的 django 视图中的 JSON 响应呈现到我的模板中。我为每个项目使用语义卡。 JSON 响应非常好。 ng-repeat 也在循环 JSON 中的项目数,但 post_titlepost_content 没有显示。

<div class="ui small header" ng-repeat="skill in skills | filter:search">
     skill.fields.post_title 
</div>

<div class="description">
     skill.fields.post_content 
</div>

错误在哪里?请帮忙。

【问题讨论】:

【参考方案1】:

不要字符串化very-nice_data

$scope.skills = very_nice_data; 需要是 javscript 数组而不是 json 字符串

【讨论】:

nice_data 的输出是一个对象数组: Array[3]0: Object1: Object2: Objectlength: 3__proto__: Array[0] 如何使用 ng-repeat有了这个数组。保持$scope.skills = nice_data 也不起作用。【参考方案2】:

Charlieftl 的回答是完美的。而不是var very_nice_data = JSON.stringify(nice_data); 只是做var very_nice_data = nice_data;

var app = angular.module("skillboard", []);

app.controller("searchskills", function($scope) 
  $scope.skills = very_nice_data;
);
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>


<div ng-app="skillboard" ng-controller="searchskills">
  <div class="ui small header" ng-repeat="skill in skills | filter:search">
     skill.fields.post_title 
  </div>
</div>

<script type="text/javascript">
  var skills_list = '["model":"posts.post","pk":1,"fields":"post_title":"Algorithms","post_content":"Calling it.","updated_on":"2016-06-12T09:09:45.198Z","timestamp":"2016-04-20T09:44:21.887Z","test_type":"Coding","number_of_questions":0,"test_url":"http://example.com","model":"posts.post","pk":4,"fields":"post_title":"Data Structures","post_content":"new content here","updated_on":"2016-06-12T09:09:26.359Z","timestamp":"2016-04-26T06:28:32.569Z","test_type":"Coding","number_of_questions":0,"test_url":"http://example.com","model":"posts.post","pk":11,"fields":"post_title":"Dynamic Programming","post_content":"This level of DP is well suited for 2+ yr experience programmers/researchers.","updated_on":"2016-06-12T09:09:16.542Z","timestamp":"2016-06-12T08:44:25.705Z","test_type":"Coding","number_of_questions":0,"test_url":"#"]'

  var nice_data = JSON.parse(skills_list.replace(/&quot;/g, '"'))

  var very_nice_data = nice_data;
</script>

【讨论】:

我试过了。输出为空白。我不认为它会完全解决问题。似乎 django 处理了花括号 。 IMO angularjs 大括号和 django 大括号之间存在冲突。对此有何建议?【参考方案3】:

最终解决问题。我遇到以下问题:

django 的花括号和角度视图绑定存在冲突。所以我在下面创建了自定义绑定。

    var app=angular.module('appName', []);
    app.config(function($interpolateProvider) 
    $interpolateProvider.startSymbol('[[');
    $interpolateProvider.endSymbol(']]');
    ); 

【讨论】:

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