Django 错误：“'ChoiceField' 对象没有属性 'is_hidden'”

Posted 2023-02-24

【中文标题】Django 错误：“\'ChoiceField\' 对象没有属性 \'is_hidden\'”

【英文标题】：Django error: "'ChoiceField' object has no attribute 'is_hidden'"Django 错误：“'ChoiceField' 对象没有属性 'is_hidden'”

【发布时间】：2014-08-31 23:37:11

【问题描述】：

Django 模板在渲染时抛出“AttributeError”。我想要实现的是，在模板中，resolted forn 将包含一个选择框，其中包含下面列表中的值。

这是Forms.py 文件：

class CallForm (forms.ModelForm):

class Meta():
    model = Call
    widgets = 
         'employee_id' : forms.ChoiceField(choices=FormsTools.EmployeesToTuples(Employee.objects.all()))
    

解释：

FormsTools.EmployeesToTuples(Employee.objects.all()) --> [(1, u'E1'), (2, u'E2'), (3, u'E3')]

这是 django 的错误：

Template error:
In template C:\virtualenv\#\#\templates\new_call.html, error at line 7
   'ChoiceField' object has no attribute 'is_hidden'
   1 : % extends "base.html" %


   2 : 


   3 : % block content %


   4 : 


   5 :         <form action="/NewCall/" method="post">% csrf_token %


   6 :             <ul>


   7 :                   form.as_p  


   8 :             </ul>


   9 :             <input type="submit" name="submit" value="Add New Call">


   10 : 


   11 :         </form>


   12 : 


   13 : % endblock %

Traceback:
File "C:\Python27\lib\site-packages\django\core\handlers\base.py" in get_response
  112.                     response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "C:\virtualenv\OmegaManager2\OmegaManager\ServiceManager\views.py" in new_call
  32.         html = t.render(Context(args))
File "C:\Python27\lib\site-packages\django\template\base.py" in render
  140.             return self._render(context)
File "C:\Python27\lib\site-packages\django\template\base.py" in _render
  134.         return self.nodelist.render(context)
File "C:\Python27\lib\site-packages\django\template\base.py" in render
  840.                 bit = self.render_node(node, context)
File "C:\Python27\lib\site-packages\django\template\debug.py" in render_node
  78.             return node.render(context)
File "C:\Python27\lib\site-packages\django\template\loader_tags.py" in render
  123.         return compiled_parent._render(context)
File "C:\Python27\lib\site-packages\django\template\base.py" in _render
  134.         return self.nodelist.render(context)
File "C:\Python27\lib\site-packages\django\template\base.py" in render
  840.                 bit = self.render_node(node, context)
File "C:\Python27\lib\site-packages\django\template\debug.py" in render_node
  78.             return node.render(context)
File "C:\Python27\lib\site-packages\django\template\loader_tags.py" in render
  62.             result = block.nodelist.render(context)
File "C:\Python27\lib\site-packages\django\template\base.py" in render
  840.                 bit = self.render_node(node, context)
File "C:\Python27\lib\site-packages\django\template\debug.py" in render_node
  78.             return node.render(context)
File "C:\Python27\lib\site-packages\django\template\debug.py" in render
  88.             output = self.filter_expression.resolve(context)
File "C:\Python27\lib\site-packages\django\template\base.py" in resolve
  585.                 obj = self.var.resolve(context)
File "C:\Python27\lib\site-packages\django\template\base.py" in resolve
  735.             value = self._resolve_lookup(context)
File "C:\Python27\lib\site-packages\django\template\base.py" in _resolve_lookup
  789.                             current = current()
File "C:\Python27\lib\site-packages\django\forms\forms.py" in as_p
  241.             errors_on_separate_row = True)
File "C:\Python27\lib\site-packages\django\forms\forms.py" in _html_output
  156.             if bf.is_hidden:
File "C:\Python27\lib\site-packages\django\forms\forms.py" in is_hidden
  560.         return self.field.widget.is_hidden

Exception Type: AttributeError at /NewCall/
Exception Value: 'ChoiceField' object has no attribute 'is_hidden'

'AttributeError' 的原因是什么？如何修复？ 谢谢。

【参考方案1】：

ChoiceField 不是小部件 - 它是 form field：

class CallForm (forms.ModelForm):
    employee_id = forms.ChoiceField(choices=FormsTools.EmployeesToTuples(Employee.objects.all()))

    class Meta:
        model = Call
        fields = ['employee_id']

【讨论】：

正确的做法是什么？如何将其传输到小部件？

你能简单解释一下小部件的用途是什么吗？

@user2216190 很高兴它成功了。基本上小部件控制网页上字段的表示，小部件处理 HTML 表单的呈现，docs 对它们非常详细。