Android 使用 xmpp 接受群聊邀请

Posted 2023-02-24

【中文标题】Android 使用 xmpp 接受群聊邀请

【英文标题】：Android accept invitation of group chat by using xmpp

【发布时间】：2014-08-19 13:25:35

【问题描述】：

我正在使用下面在 xmpp 中获得邀请进行群聊，并且也成功获得了邀请，但在接受邀请的地方无法接受邀请。

这是我邀请和接受群聊的代码：

     public static void addMUC() 
                MultiUserChat.addInvitationListener(connection, new InvitationListener() 
                    @Override
                    public void invitationReceived(Connection conn, final String room, String invitor,
                            String reason, String password, Message message) 

                        Constant.showGroupChatInvitationAlert(Constant.MESSAGE_GROUP_CHAT, reason, 
                                room,conn,invitor, _sPrefs.getString("USERNAME", ""), _sPrefs.getString("PASSWORD", ""));


                    
                );
            


    public static void showGroupChatInvitationAlert(final String title, final String message,
                final String roomname,final Connection conn,final String inviter, final String user,final String password) 

            new Thread(new Runnable() 
        public void run() 

joinMultiUserChat(Constant.userName, Constant.password, roomname.split("@")[0]);
        
    ).start();

        

public static MultiUserChat joinMultiUserChat(String user, String password, String roomsName)   
        try   

            XMPPSmackConnection.getInstance();
            StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
            StrictMode.setThreadPolicy(policy); 
            // Create a MultiUserChat window using XMPPConnection  
            MultiUserChat muc = new MultiUserChat(XMPPSmackConnection.connection, roomsName  
                    + "@conference." + XMPPSmackConnection.connection.getServiceName());  



            // The number of chat room services will decide to accept the historical record  
            DiscussionHistory history = new DiscussionHistory();  
            history.setMaxStanzas(0);  
            //history.setSince(new Date());  
            // Users to join in the chat room  
            muc.join(user, password, history, SmackConfiguration.getPacketReplyTimeout());  
            System.out.println("The conference room success....");  
            return muc;  
         catch (XMPPException e)   
            e.printStackTrace();  
            System.out.println("The conference room to fail....");  
            return null;  
          
    

【问题讨论】：

xmpp 支持群聊，但它不是持久性，您必须在本地存储所有邀请和数据，因为如果连接中断，它会清除所有组相关数据

对不起.. 没明白你想说什么..

有没有办法自动接受邀请？

***.com/questions/22626930/…

igniterealtime.org/builds/smack/docs/latest/documentation/…

【参考方案1】：

在连接到服务器之前将此扩展管理器添加到ProviderManager

ProviderManager.getInstance().addExtensionProvider("x", "http://jabber.org/protocol/muc#user",  new MUCUserProvider());

希望对你有帮助……