如何通过html内容获取href和文本内容

Posted 2023-02-23

【中文标题】如何通过html内容获取href和文本内容

【英文标题】：how to get href and text content by html Content

【发布时间】：2020-11-05 20:04:03

【问题描述】：

我想获取包含所有其他 td 数据的内容和 url。

我的代码：

$context = stream_context_create(
    array(
        "http" => array(
            "header" => "User-Agent: Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (Khtml, like Gecko) Chrome/50.0.2661.102 Safari/537.36"
        )
    )
);

$htmlContent = file_get_contents("https://www.iana.org/domains/root/db", false, $context);
    
$DOM = new DOMDocument();
$DOM->loadHTML($htmlContent);

$FirstdTable = $DOM->getElementsByTagName('table')->item(0);


$Header = $FirstdTable->getElementsByTagName('th');
$Detail = $FirstdTable->getElementsByTagName('td');

//#Get header name of the table
foreach($Header as $NodeHeader) 

    $aDataTableHeaderHTML[] = trim($NodeHeader->textContent);


//#Get row data/detail table without header name as key
$i = 0;
$j = 0;
foreach($Detail as $sNodeDetail)

   
    $aDataTableDetailHTML[$j][] = trim($sNodeDetail->textContent);
    $i = $i + 1;
    $j = $i % count($aDataTableHeaderHTML) == 0 ? $j + 1 : $j;

当前输出：

Array
(
    [0] => Array
        (
            [0] => .aaa
            [1] => generic
            [2] => American Automobile Association, Inc.
        )

    [1] => Array
        (
            [0] => .aarp
            [1] => generic
            [2] => AARP
        )

    [2] => Array
        (
            [0] => .abarth
            [1] => generic
            [2] => Fiat Chrysler Automobiles N.V.
        )

我想在这里：

Array
(
    [0] => Array
        (
            [0] => .aaa
            [1] => generic
            [2] => American Automobile Association, Inc.
            [3] => https://www.iana.org/domains/root/db/aaa.html
        )

    [1] => Array
        (
            [0] => .aarp
            [1] => generic
            [2] => AARP
            [3] => https://www.iana.org/domains/root/db/aarp.html
        )

    [2] => Array
        (
            [0] => .abarth
            [1] => generic
            [2] => Fiat Chrysler Automobiles N.V.
            [3] => https://www.iana.org/domains/root/db/abarth.html
        )

【参考方案1】：

目前，您只是获取所有<td> 中的所有文本内容。它不会在锚标签内包含链接。为此，您需要深入挖掘<td>。

这是使用xpath 的一种方法：

$xpath = new DOMXpath($DOM);
$base = 'https://www.iana.org/';
foreach($Detail as $sNodeDetail)

    $aDataTableDetailHTML[$j][] = trim($sNodeDetail->textContent);
    if ($link = $xpath->evaluate("string(./span[contains(@class, 'domain')]/a/@href)", $sNodeDetail)) 
        $aDataTableDetailHTML[$j][] = "$base$link";
    
    $i = $i + 1;
    $j = $i % count($aDataTableHeaderHTML) == 0 ? $j + 1 : $j;

基本上，如果迭代中的当前<td> 具有<span class="domain tld"><a href="xxxx">xxx</a></span>，则查询只需提取href 值并获取href 值。

另一种方法是迭代每个<tr> 而不是每个<td>：

$aDataTableDetailHTML = [];
$DOM = new DOMDocument();
$DOM->loadHTML($htmlContent);
$xpath = new DOMXpath($DOM);
$base = 'https://www.iana.org/';
foreach($xpath->query('//table[@id="tld-table"]/tbody/tr') as $row) 
    $domain = trim($xpath->evaluate("string(./td[1])", $row));
    $type = $xpath->evaluate("string(./td[2])", $row);
    $tld_manager = $xpath->evaluate("string(./td[3])", $row);
    $url = $xpath->evaluate("string(./td[1]/span/a/@href)", $row);
    $aDataTableDetailHTML[] = [$domain, $type, $tld_manager, "$base$url"];

【讨论】：

谢谢，它的工作原理，但如果我需要在 td[1] ex 中获取包括 html 元素在内的内容。

test 输出应该是：test