当答案== true时如何使void不返回[关闭]
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【中文标题】当答案== true时如何使void不返回[关闭]【英文标题】:How to make void not return when answer == true [closed] 【发布时间】:2021-04-04 01:21:15 【问题描述】:我制作了这个程序,当我输入“yes”时,它应该结束我的程序,而不是等待我说更多内容,然后它带有我的 void nottrue();我应该怎么做才能避免这种情况?这是我的代码
#include <iostream>
using namespace std;
void CharacterWorld();
void nottrue();
int main()
CharacterWorld();
nottrue();
return 0;
void CharacterWorld()
string CharacterName;
int CharacterAge;
string yesorno;
cout << " Hi, welcome to the Vanish World! " << endl;
cout << " What's your name champion? " << endl;
cin >> CharacterName;
cout << " ...And what's your age? " << endl;
cin >> CharacterAge;
cout << " ... So your name is " << CharacterName << " and your age is " << CharacterAge << " Is that right?" << endl;
cin >> yesorno;
if (yesorno == "yes")
cout << " Okey! so let's start your journey champion!" << endl;
else
cout << " SO what's your name then ??" << endl;
return nottrue();
void nottrue()
string CharacterName;
int CharacterAge;
string yesorno;
cin >> CharacterName;
cout << " and what's your age?" << endl;
cin >> CharacterAge;
cout << " ...Okey, already. Your name is " << CharacterName << " and your age is " << CharacterAge << endl;
【问题讨论】:
return nottrue();
调用 nottrue()
并退出,void
不是一个值,不是任何类型的结果。当然,接下来您会再次致电nottrue()
。
【参考方案1】:
虽然return nottrue()
有效,但它只是一个函数调用,因为调用者和被调用函数都没有返回值。你不会以任何方式改变流量。
您必须将函数返回的结果用于控制流。例如
bool CharacterWorld()
//...
if (yesorno == "yes")
cout << " Okey! so let's start your journey champion!" << endl;
return true;
else
cout << " SO what's your name then ??" << endl;
return false;
int main()
if(!CharacterWorld())
nottrue();
return 0;
还有预定义的exit()
函数退出程序。
【讨论】:
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