Swift 2 - 用户的当前位置在 MKPolygon 内
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【中文标题】Swift 2 - 用户的当前位置在 MKPolygon 内【英文标题】:Swift 2 - User's Current Location is inside MKPolygon 【发布时间】:2016-02-06 08:31:14 【问题描述】:我正在尝试检查用户的当前位置是否在 MKPolygon 内。我创建了以下函数,但它对我的所有测试用例都返回 false。是不是我做错了什么?
func isCorrectRegion(coordinates: Array<JSON>, userLocation: CLLocationCoordinate2D) -> Bool
var newCoordinates: [CLLocationCoordinate2D] = []
var mapPoints: [MKMapPoint] = []
for(a):(JSON) in coordinates
let lat = a.arrayValue[1].double
let long = a.arrayValue[0].double
let location = CLLocationCoordinate2D(latitude: lat!, longitude: long!)
newCoordinates.append(location)
for b in newCoordinates
let c: MKMapPoint = MKMapPointForCoordinate(b)
mapPoints.append(c)
let polygon: MKPolygon = MKPolygon(points: &mapPoints, count: mapPoints.count)
let polyRender: MKPolygonRenderer = MKPolygonRenderer(polygon: polygon)
polyRender.invalidatePath()
let target: MKMapPoint = MKMapPointForCoordinate(userLocation)
let cgTarget: CGPoint = CGPoint(x: target.x, y: target.y)
let isWithin = CGPathContainsPoint(polyRender.path, nil, cgTarget, false)
return isWithin
【问题讨论】:
【参考方案1】:在尝试了一些不同的事情后终于弄明白了。希望这对其他人有帮助:
func isCorrectRegion(coordinates: Array<JSON>, userLocation: CLLocationCoordinate2D) -> Bool
var newCoordinates: [CLLocationCoordinate2D] = []
var mapPoints: [MKMapPoint] = []
let mpr: CGMutablePathRef = CGPathCreateMutable()
for(a):(JSON) in coordinates
let lat = a.arrayValue[1].double
let long = a.arrayValue[0].double
let location = CLLocationCoordinate2D(latitude: lat!, longitude: long!)
newCoordinates.append(location)
for b in newCoordinates
let c: MKMapPoint = MKMapPointForCoordinate(b)
mapPoints.append(c)
for var p = 0; p<mapPoints.count; p++
if p == 0
CGPathMoveToPoint(mpr, nil, CGFloat(mapPoints[p].x), CGFloat(mapPoints[p].y))
else
CGPathAddLineToPoint(mpr, nil, CGFloat(mapPoints[p].x), CGFloat(mapPoints[p].y))
let target: MKMapPoint = MKMapPointForCoordinate(userLocation)
let cgTarget: CGPoint = CGPoint(x: target.x, y: target.y)
let isWithin = CGPathContainsPoint(mpr, nil, cgTarget, false)
return isWithin
【讨论】:
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