React 函数式组件继承

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【中文标题】React 函数式组件继承【英文标题】:React Functional Component Inheritance 【发布时间】:2017-11-01 10:05:50 【问题描述】:

我创建了一个 React 功能组件,它是 react-data-grid 组件的包装器。现在我需要第二个组件,除了一个函数(如果你熟悉 react-data-grid 的话,就是 rowGetter)。

我在 Intranet 上工作,所以我将输入一个简单的示例...

function UsersInfoDataTable(props) 

  const userInfoCols = [
    key: "a", name: "A", ...,
    key: "b", name" "B", ...,
    key: "c", name" "C", ...,
    ...
  ];

  const aCellCreation = (aData, description, index) => (
    <span title=...>...</span>
  )

  const bCellCreation = (bData, index) => (
    <div className=...>...</div>
  

  ...

  
  const formattedTableData = props.myData.map(function (obj, index) 
    //do some stuff
    return "a": aCellCreation(obj.a, obj.desc,index), "b": bCellCreation(obj.b, index), ...
  );

  const rowGetter = rowNumber => formattedTableData[rowNumber];

  return (
    <div>
      <ReactDataGrid
        columns=userInfoCols
        rowGetter=rowGetter
        rowCount=formattedTableData.length
        minHeight=props.minHeight
       />
     </div>
   )


export default UsersInfoDataTable;

现在我也需要这样的东西......

function UsersInfoDataTableSlightlyDifferent(props) 

  //i need the same columns
  const userInfoCols = [
    key: "a", name: "A", ...,
    key: "b", name: "B", ...
  ];

  //i need same cell format    
  const aCellCreation = (aData, description, index) => (
    <span title=...>...</span>
  )

  //i need same cell format
  const bCellCreation = (bData, index) => (
    <div className=...>...</div>
  

  ...

  //the internals of this function will be pretty much the only difference
  const formattedTableData = props.myData.map(function (obj, index) 

    //do some different stuff than previous component as myData will be
    //in a different format when passed here versus the other component

    //the return will be essentially the same - maybe slightly different with
    //what is passed to the "creation" functions
    return "a": aCellCreation(obj.a, obj.desc,index), "b": bCellCreation(obj.b, index), ...
  );

  const rowGetter = rowNumber => formattedTableData[rowNumber];

  return (
    <div>
      <ReactDataGrid
        columns=userInfoCols
        rowGetter=rowGetter
        rowCount=formattedTableData.length
        minHeight=500
       />
     </div>
   )


export default UsersInfoDataTable;

我认为做我想做的事的几种方法......

    复制和粘贴不重复使用 - 不好 重用完全相同的组件,但检查一个道具中的数据,如果存在循环并以一种方式执行其他操作,则循环通过另一个道具并执行不同的操作 更改为使用 React 类而不是功能组件并使用继承(我以前不需要这样做,所以我必须做一些阅读) 更改为使用 React 类并让所有函数都是静态的,并在两个组件中使用来自一个组件的静态函数。 IE。 aCellCreation() 和 bCellCreation() 将是静态的。

我有点倾向于#2,但如果我想拥有基本相同的表格并显示来自 4 个不同来源的用户信息怎么办 - 它可能会变得丑陋。例如dataToMapThrough = props.allUsersData? props.allUserData : (props.usersFromUSAData? props.usersFromUSAData : ...)

对完成此任务的最佳方法有什么建议吗?


更新

如果有人感兴趣,我会在这里阅读 Andy_D 提供的文档。希望没有错别字,因为自从我在 Intranet 网站上工作以来,我不得不手动输入所有内容...

function UsersInfoDataTableDisplayer(props) 

  const userInfoCols = [
    key: "a", name: "A", ...,
    key: "b", name: "B", ...
  ];

  const aCellCreation = (aData, description, index) => (
    <span title=...>...</span>
  )

  const bCellCreation = (bData, index) => (
    <div className=...>...</div>
  

  ...

  //data will already be processed exactly how this Component needs it every time
  //in the specialized version of this Component
  const formattedTableData = props.userInfoData.map(function (obj, index) 

    //Probably nothing to do here since data is processed in the specialized 
    //version of this component

    return "a": aCellCreation(obj.a, obj.b,index), "b": bCellCreation(obj.b, index),"c": obj.c
  );

  const rowGetter = rowNumber => formattedTableData[rowNumber];

  return (
    <div>
      <ReactDataGrid
        columns=userInfoCols
        rowGetter=rowGetter
        rowCount=formattedTableData.length
        minHeight=500
       />
     </div>
   )


export default UsersInfoDataTableDisplayer;

现在这里是一个专门的版本 #1...

function UsersInfoFromService1DataTable(props) 

  //The format of the JSON passed in is one way here 
  const formattedTableData = props.abcData.map(function (obj, index) 

    //"combine" and "clean" or whatever you need here
    let aLikeData = obj.firstName + ' ' + obj.lastName

    return "a": aLikeData, "b": obj.description, "c": obj.whatever,...
  );



  return (
    <div>
      <UsersInfoDataTableDisplayer
        userInfoData = formattedTableData
        minHeight=500
       />
     </div>
   )


export default UsersInfoFromService1DataTable;

这里是专门的版本 #2...

function UsersInfoFromService1DataTable(props) 

  //The format of the JSON passed in is one way here 
  const formattedTableData = props.xyzData.map(function (obj, index) 

    //"combine" and "clean" or whatever you need here
    let aLikeData = obj.fullName

    return "a": aLikeData, "b": obj.desc, "c": obj.something,...
  );



  return (
    <div>
      <UsersInfoDataTableDisplayer
        userInfoData = formattedTableData
        minHeight=900
       />
     </div>
   )


export default UsersInfoFromService2DataTable;

【问题讨论】:

【参考方案1】:

React 文档在这里解决了这个问题:https://facebook.github.io/react/docs/composition-vs-inheritance.html

我已经阅读了该内容,并在这些指导方针的范围内,做任何看起来最好的事情。

TL;DR - 不要使用继承。但请务必阅读。

【讨论】:

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