在 iOS PayPal SDK 中使用信用卡选项时如何获取交易 ID

Posted 2023-02-22

【中文标题】在 iOS PayPal SDK 中使用信用卡选项时如何获取交易 ID

【英文标题】：How to get Transaction id when using Credit Card option in iOS PayPal SDK

【发布时间】：2014-01-02 01:41:51

【问题描述】：

我在 PayPal 中使用信用卡时收到以下回复：

    
    client =     
        environment = sandbox;
        "paypal_sdk_version" = "1.4.3";
        platform = ios;
        "product_name" = "PayPal iOS SDK";
    ;
    payment =     
        amount = "1.00";
        "currency_code" = USD;
        "short_description" = Order;
    ;
    "proof_of_payment" =     
        "rest_api" =         
            "payment_id" = "PAY-0HB84369BG507770XKKV7ZYI";
            state = approved;
        ;
    ;

)

如何使用payment_id获取transactionID？

使用 PayPal REST API 获取 transactionID 有两个步骤， 1.获取AccessToken 2.使用AccessToken和payment_id获取transactionID。

为了获得 AccessToken，他们给出了一些参考代码，如下所示，我需要帮助将最后两行的代码转换为 Objective-C，我知道标题 (-H)，但不知道 -u ,-d

    curl -v https://api.sandbox.paypal.com/v1/oauth2/token \
  -H "Accept: application/json" \
  -H "Accept-Language: en_US" \
  -u "EOJ2S-Z6OoN_le_KS1d75wsZ6y0SFdVsY9183IvxFyZp:EClusMEUk8e9ihI7ZdVLF5cZ6y0SFdVsY9183IvxFyZp" \
  -d "grant_type=client_credentials"

我使用了下面的代码，但它给出了一个错误：

NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"https://api.sandbox.paypal.com/v1/oauth2/token"]];
    NSMutableURLRequest *theRequest=[NSMutableURLRequest requestWithURL:url];
    [theRequest addValue:@"application/json" forHTTPHeaderField:@"Accept"];
    [theRequest addValue:@"Accept-Language" forHTTPHeaderField:@"en_US"];
    [theRequest setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];

    NSString *strClientIdAndSecretKey=[NSString stringWithFormat:@"%@:%@",kPayPalClientId,kPayPalSecret];

 [theRequest setValue:strClientIdAndSecretKey forHTTPHeaderField:@"client_id:secret"];

    NSString *parameterString = [NSString stringWithFormat:@"grant_type=client_credentials"];

    NSString *msgLength = [NSString stringWithFormat:@"%d", [parameterString length]];

    [theRequest addValue: msgLength forHTTPHeaderField:@"Content-Length"];

    //do post request for parameter passing
    [theRequest setHTTPMethod:@"POST"];

    [theRequest setHTTPBody:[parameterString dataUsingEncoding:NSUTF8StringEncoding]];

    NSLog(@"Headers %@",[theRequest allHTTPHeaderFields]);

    [NSURLConnection sendAsynchronousRequest:theRequest
                                       queue:[NSOperationQueue mainQueue]
                           completionHandler:^(NSURLResponse *response, NSData *dataOrder, NSError *error)
     


         if(error == nil)
         
             NSString *jsonString = [[[NSString alloc] initWithData:dataOrder encoding:NSUTF8StringEncoding] autorelease];
             NSLog(@"Result is %@",jsonString);
         
         else
         

         
     
     ];

Error Domain=NSURLErrorDomain Code=-1012 "操作无法完成。(NSURLErrorDomain error -1012.)" UserInfo=0xabd2bf0 NSErrorFailingURLKey=https://api.sandbox.paypal.com/v1/oauth2/token, NSErrorFailingURLStringKey=https://api.sandbox.paypal.com/v1/oauth2/token, NSUnderlyingError=0xabcf950 "操作无法完成。（kCFErrorDomainCFNetwork 错误 -1012。）"

我在传递 clientid 和 secret 时遇到问题，有什么想法可以解决这个问题吗？

【问题讨论】：

参考链接：developer.paypal.com/webapps/developer/docs/integration/direct/…

您好，我也遇到了同样的问题，能否请您发布代码如何使用该 URL？

【参考方案1】：

你能看看下面的代码吗，希望对你有帮助..

Objective-c 源码：

NSString *clientID = @"YOUR_CLIENT_ID";
NSString *secret = @"YOUR_SECRET";

NSString *authString = [NSString stringWithFormat:@"%@:%@", clientID, secret];
NSData * authData = [authString dataUsingEncoding:NSUTF8StringEncoding];
NSString *credentials = [NSString stringWithFormat:@"Basic %@", [authData base64EncodedStringWithOptions:0]];

NSURLSessionConfiguration *configuration = [NSURLSessionConfiguration defaultSessionConfiguration];
[configuration setHTTPAdditionalHeaders:@ @"Accept": @"application/json", @"Accept-Language": @"en_US", @"Content-Type": @"application/x-www-form-urlencoded", @"Authorization": credentials ];
NSURLSession *session = [NSURLSession sessionWithConfiguration:configuration];

NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:[NSURL URLWithString:@"https://api.sandbox.paypal.com/v1/oauth2/token"]];
request.HTTPMethod = @"POST";

NSString *dataString = @"grant_type=client_credentials";
NSData *theData = [dataString dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];

NSURLSessionUploadTask *task = [session uploadTaskWithRequest:request fromData:theData completionHandler:^(NSData *data, NSURLResponse *response,   NSError *error) 
if (!error) 
    NSLog(@"data = %@", [NSJSONSerialization JSONObjectWithData:data options:0 error:&error]);

 ];

 [task resume];

回应::

data = 
"access_token" = "YOUR_NEW_ACCESS_TOKEN";
"app_id" = "APP-YOUR_APP_ID";
"expires_in" = 34400;
scope = "https://uri.paypal.com/services/subscriptions   https://api.paypal.com/v1/payments/.* https://api.paypal.com/v1/vault/credit-card https://uri.paypal.com/services/applications/webhooks openid https://uri.paypal.com/services/invoicing https://api.paypal.com/v1/vault/credit-card/.*";
"token_type" = "YOUR_Token_Type";

【参考方案2】：

你不小心把这些值翻转了：

[theRequest addValue:@"Accept-Language" forHTTPHeaderField:@"en_US"];

应该是：

[theRequest addValue:@"en_US" forHTTPHeaderField:@"Accept-Language"];

【参考方案3】：

要设置凭据替换此代码

NSData * credential = [strClientIdAndSecretKey  dataUsingEncoding:NSUTF8StringEncoding];
NSString *credentialString = [credential base64EncodedStringWithOptions:NSDataBase64EncodingEndLineWithCarriageReturn];
[theRequest setValue:[NSString stringWithFormat:@"Basic %@",credentialString] forHTTPHeaderField:@"Authorization"];        

与

[theRequest setValue:strClientIdAndSecretKey forHTTPHeaderField:@"client_id:secret"]          

【讨论】：

试试这个，它对我有用并返回一个有效的响应