如何首先根据其单位（bit/s、Kbit/s 等）对特定的字典列表进行排序，然后根据它们的值对它们进行排序

Posted 2023-02-16

【中文标题】如何首先根据其单位（bit/s、Kbit/s 等）对特定的字典列表进行排序，然后根据它们的值对它们进行排序

【英文标题】：How do I sort the particular list of dictionary first on the basis of their Units (bit/s, Kbit/s, etc) and then sort them according to their value

【发布时间】：2021-10-26 05:05:12

【问题描述】：

my_lst = [
        "usage": "0.59 Kbit/s",
        "usage": "383.34 bit/s",
        "usage": "158.13 bit/s",
        "usage": "4.15 Gbit/s",
        "usage": "18.5 Mbit/s",
        "usage": "45 Kbit/s"
    ]

试图实现的输出应该是这样的，带有排序值：-

my_lst = [
    'usage': '4.15 Gbit/s', 
    'usage': '18.5 Mbit/s', 
    'usage': '45 Kbit/s', 
    'usage': '0.59 Kbit/s', 
    'usage': '383.34 bit/s', 
    'usage': '158.13 bit/s'
]

【参考方案1】：

单程使用humanfriendly.parse_size：

from humanfriendly import parse_size

sorted(my_lst, key=lambda x: parse_size(x["usage"]), reverse=True)

输出：

['usage': '4.15 Gbit/s',
 'usage': '18.5 Mbit/s',
 'usage': '45 Kbit/s',
 'usage': '0.59 Kbit/s',
 'usage': '383.34 bit/s',
 'usage': '158.13 bit/s']

【参考方案2】：

您可以使用humanfriendly 模块：

from humanfriendly import parse_size
print(sorted(my_lst, key=lambda x: parse_size(x["usage"])[::-1])

【参考方案3】：

使用humanfriendly 库的其他答案是更好的解决方案。这只是一种不使用库的替代方法。

from decimal import Decimal

UNIT_MAPPINGS = 
    "": 1,
    "K": pow(10, 3),
    "M": pow(10, 6),
    "G": pow(10, 9),


my_lst = [
    "usage": "0.59 Kbit/s",
    "usage": "383.34 bit/s",
    "usage": "158.13 bit/s",
    "usage": "4.15 Gbit/s",
    "usage": "18.5 Mbit/s",
    "usage": "45 Kbit/s"
]

def convert_rate(rate):
    num, _, unit = rate['usage'].partition(" ")
    unit = unit.replace('bit/s', '')
    return Decimal(num) * UNIT_MAPPINGS[unit]

my_lst.sort(key=convert_rate, reverse=True)
print(my_lst)

输出

['usage': '4.15 Gbit/s', 'usage': '18.5 Mbit/s', 'usage': '45 Kbit/s', 'usage': '0.59 Kbit/s', 'usage': '383.34 bit/s', 'usage': '158.13 bit/s']