通过 Firebase 函数发送电子邮件时出现 Firebase SendGrid 错误 - 错误：错误请求

Posted 2023-02-22

【中文标题】通过 Firebase 函数发送电子邮件时出现 Firebase SendGrid 错误 - 错误：错误请求

【英文标题】：Firebase SendGrid error on sending email via Firebase functions - Error: Bad Request

【发布时间】：2020-01-12 00:33:13

【问题描述】：

我正在使用 Firebase 和 SendGrid，我正在使用 Firebase 函数。我正在尝试在创建新用户时发送电子邮件。当我触发该功能时，我收到以下错误：

 firestoreEmail: Function execution started
2019-09-10T08:13:49.245Z I firestoreEmail:  Error: Bad Request
    at Request.http [as _callback] (node_modules/@sendgrid/client/src/classes/client.js:124:25)
    at Request.self.callback (node_modules/request/request.js:185:22)
    at emitTwo (events.js:126:13)
    at Request.emit (events.js:214:7)
    at Request.<anonymous> (node_modules/request/request.js:1161:10)
    at emitOne (events.js:116:13)
    at Request.emit (events.js:211:7)
    at IncomingMessage.<anonymous> (node_modules/request/request.js:1083:12)
    at Object.onceWrapper (events.js:313:30)
    at emitNone (events.js:111:20)
  code: 400,
  message: 'Bad Request',
  response: 
    headers: 
       server: 'nginx',
        date: 'Tue, 10 Sep 2019 08:13:49 GMT',
        'content-type': 'application/json',
        'content-length': '365',
        connection: 'close',
        'access-control-allow-origin': 'https://sendgrid.api-docs.io',
        'access-control-allow-methods': 'POST',
        'access-control-allow-headers': 'Authorization, Content-Type, On-behalf-of, x-sg-elas-acl',
        'access-control-max-age': '600',
        'x-no-cors-reason': 'https://sendgrid.com/docs/Clas-s-room/Basics/API/cors.html' ,
     body:  errors: [Array]    

这是我的 Index.js：

 const functions = require('firebase-functions');

const admin = require('firebase-admin');
admin.initializeApp(functions.config().firebase);


const SENDGRID_API_KEY = 'exact API key here because functions.config().sendgrid.key doesn't work, says sendgrid is undefined';

const sgMail = require('@sendgrid/mail');
sgMail.setApiKey(SENDGRID_API_KEY);

exports.firestoreEmail = functions.firestore
.document('Users/userId/Followers/followerId')
.onCreate(event => 

    const userId = "for now exact id";

    const db = admin.firestore()

    return db.collection('Users').doc(userId)
            .get()
            .then(doc => 
                const user = doc.data()

                const msg = 
                    to: "[e-mail]",
                    from: '[e-mail]',
                    subject: 'New Follower',
                ;

                return sgMail.send(msg)
            )
            .then( () => console.log('email sent!') )
            .catch( (err) => console.log(err) )
) 

附：我正在关注 Fireship 的教程https://www.youtube.com/watch?v=JVy0JpCOuNI&t=333s

编辑： 这些是数据库 SC first image second image

【问题讨论】：

你能提供你的firetsore db的截图吗

@ConstantinBeer 我编辑了帖子，并包含了 SC

您的Index.js 缺少行。你把它们排除在外了吗？另外，您是否尝试使用userId = "for now exact id" 获取文档，还是仅针对您的帖子进行更改？

@ConstantinBeer 我编辑了这些行，对不起，我的错误。它们从一开始就在文件中，忘记粘贴它们。我为帖子更改了“现在确切的 ID”，那里需要 SendGrid api 密钥。

【参考方案1】：

问题是 const msg 缺少一个 templateId 字段，如果使用 SendGrid，这显然是强制性的。 这是工作的 sn-p：

const msg = 
                    to: "[e-mail]",
                    from: '[e-mail]',
                    subject: 'New Follower',

                    templateId: 'd-03ff1102c6e647c08207f293fce1701f', <--- this was missing
                ;