线程处理 c++ linux OS
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【中文标题】线程处理 c++ linux OS【英文标题】:thread handling c++ linux OS 【发布时间】:2014-06-26 08:08:33 【问题描述】:我的项目中有三个用 c++ 编写的函数。它们在同一个 .cpp 文件中,我有两个头文件。
现在,我有三个相应的线程,因此,第二个线程从第一个线程获取输出,最后一个线程等待直到第二个线程结束其操作。请注意,线程处于“永远循环”中,即while(1)....
source.cpp 看起来像这样:
#include <iostream>
#include "source.h"
#include "glob_variables.h"
#include "armadillo"
#include <vector>
using namespace arma;
using namespace std;
void source::first_function(int size)
for(int i=0;i<size;i++)
container.push_back(i);//container is global variable vector of type int declared in glob_variables.h
//~~~~~~~~~~~~~~~~~~~~~~
void source::second_function()
//sleep until the first function fills the the vector to set set its size to matrix.n_rows
matrix.set_size(container.size(),33);
for(int i=0;i<container.size();i++)
for(int j=0;j<50;j++)
matrix(i,j)=i+j;//matrix is also a global variable in glob_variables.h
//~~~~~~~~~~~~~~~~~~~~~~
void source::third_function()
//sleep untill the second function fills the matrix, then print
cout<<matrix;//print out the matrix
source.h:
#include "glob_variables.h"
#include "armadillo"
#include <vector>
using namespace arma;
using namespace std;
class source
public:
void first_function(int size);
void second_function();
void third_function();
;
glob_variables.h:
#include "armadillo"
#include <vector>
using namespace arma;
using namespace std;
extern mat matrix;
extern vector<int> container;
Main.cpp:
#include <iostream>
#include <stdio.h>
#include <pthread.h>
#include "source.h"
#include "glob_variables.h"
#include "armadillo"
#include <vector>
using namespace arma;
using namespace std;
//thread functions
void* first_reader(void* id1)
source mysource;
while(1)
mysource.first_function(80);
void* second_reader(void* id2)
source mysource;
while(1)
mysource.second_function();
void* third_reader(void* id3)
source mysource;
while(1)
mysource.third_function();
int main()
pthread_t first;
pthread_t second;
pthread_t third;
int hndl_first;
int hndl_second;
int hndl_third;
hndl_first = pthread_create(&first, NULL, first_reader, NULL);
hndl_second= pthread_create(&second, NULL, second_thread, NULL);
hndl_third;= pthread_create(&third, NULL,third_thread, NULL);
pthread_exit(NULL);
return 0;
我可以有任何技术来做到这一点,或者任何简单的例子。谢谢。
【问题讨论】:
您为什么使用 pthreads 而不是 boost? 【参考方案1】:尝试使用以下链接。 AutoResetEvent 满足您的要求。链接中的代码正是您所期望的。
What is the C++ equivalent for AutoResetEvent under Linux?
【讨论】:
【参考方案2】:我认为您想按顺序播放线程。 在第一个线程中做某事 -> 在第二个线程中做某事 -> 在第三个线程中做某事。
对吗? 在这种情况下,您可以使用信号。
示例:
pthread_cond_t cond;
pthread_mutex_t mtx;
typedef enum
ready1,
ready2,
ready3
thread_ready;
thread_ready t_ready;
void* first_reader(void* id1)
//source mysource;
while(1)
pthread_mutex_lock(&mtx);
while(t_ready != ready1)
pthread_cond_wait(&cond, &mtx);
pthread_mutex_unlock(&mtx);
std::cout << "first" << std::endl;
//mysource.first_function(80);
pthread_mutex_lock(&mtx);
t_ready = ready2;
pthread_cond_signal(&cond);
pthread_mutex_unlock(&mtx);
sleep(1);
void* second_reader(void* id2)
//source mysource;
while(1)
pthread_mutex_lock(&mtx);
while(t_ready != ready2)
pthread_cond_wait(&cond, &mtx);
pthread_mutex_unlock(&mtx);
std::cout << "second" << std::endl;
//mysource.second_function();
pthread_mutex_lock(&mtx);
t_ready = ready3;
pthread_cond_signal(&cond);
pthread_mutex_unlock(&mtx);
sleep(1);
void* third_reader(void* id3)
//source mysource;
while(1)
pthread_mutex_lock(&mtx);
while(t_ready != ready3)
pthread_cond_wait(&cond, &mtx);
pthread_mutex_unlock(&mtx);
std::cout << "third" << std::endl;
//mysource.third_function();
pthread_mutex_lock(&mtx);
t_ready = ready1;
pthread_cond_signal(&cond);
pthread_mutex_unlock(&mtx);
sleep(1);
int main()
pthread_t first;
pthread_t second;
pthread_t third;
int hndl_first;
int hndl_second;
int hndl_third;
pthread_cond_init(&cond,NULL);
pthread_mutex_init(&mtx,NULL);
t_ready = ready1;
hndl_first = pthread_create(&first, NULL, first_reader, NULL);
hndl_second = pthread_create(&second, NULL, second_reader, NULL);
hndl_third = pthread_create(&third, NULL,third_reader, NULL);
pthread_join(first, NULL);
pthread_join(second, NULL);
pthread_join(third, NULL);
return 0;
其实这个case不需要做3个线程。如果你想喜欢我的代码,你最好只做 1 个线程。
【讨论】:
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