如何将二进制流插入varbinary? [复制]
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【中文标题】如何将二进制流插入varbinary? [复制]【英文标题】:How to insert binary stream into varbinary? [duplicate] 【发布时间】:2020-03-06 19:56:04 【问题描述】:我一直在阅读here 和here 关于如何将二进制数组插入varbinary
,但是如果我没有准备好字节数组怎么办?如果我要序列化一个对象怎么办?所以如果我有
var Formatter = new BinaryFormatter();
Formatter.Serialize(SerializeStream, NewEmployeeTree);
当我想序列化成文件时,我将SerializeStream
传递为
var SerializeStream = new FileStream(SelectedPath, FileMode.Create, FileAccess.ReadWrite, FileShare.ReadWrite);
但是这次我想序列化到数据库中。我该怎么做?
【问题讨论】:
Creating a Byte Array from a Stream @RobertHarvey 但是我怎样才能在我的代码中实现它呢? 您的问题是“如果我没有准备好字节数组怎么办?”链接的帖子解释了如何将流转换为字节数组。一旦你这样做了,你将准备好一个字节数组。 @RobertHarvey 但是我从哪里得到流?什么类型的流? 【参考方案1】:你可以使用
批量插入
像这样:
using System;
using System.Collections.Generic;
using System.Data.SqlClient;
using System.IO;
using System.Linq;
using System.Runtime.Serialization;
using System.Runtime.Serialization.Formatters.Binary;
using System.Text;
using System.Threading.Tasks;
namespace ConsoleApp1
class Program
static void Main(string[] args)
//toturial obj = new toturial();
//obj.ID = 1;
//obj.name = "MrLotfi";
//IFormatter formatter = new BinaryFormatter();
//Stream stream = new FileStream("E:\\example.txt", FileMode.Create, FileAccess.ReadWrite);
//formatter.Serialize(stream,obj);
//stream.Close();
Tutorial obj = new Tutorial();
obj.ID = 1;
obj.Name = ".Net";
IFormatter formatter = new BinaryFormatter();
Stream stream = new FileStream(@"E:\ExampleNew.txt", FileMode.Create, FileAccess.Write);
formatter.Serialize(stream, obj);
stream.Close();
SqlConnection conn = new SqlConnection("Your SQL Connection String");
conn.Open();
StringBuilder str = new StringBuilder();
str.AppendLine("DECLARE @tImage AS VARBINARY(MAX)");
str.AppendLine(@"SELECT @tImage = CAST(bulkcolumn AS VARBINARY(MAX)) FROM OPENROWSET( BULK 'E:\ExampleNew.txt', SINGLE_BLOB ) AS x");
str.AppendLine(@"INSERT INTO TblPhotos (ID, Name, Images) SELECT NEWID(), 'E:\ExampleNew.txt',@tImage");
SqlCommand cmd = new SqlCommand(str.ToString(), conn);
cmd.ExecuteNonQuery();
Console.WriteLine("Image Saved Successfully...");
stream = new FileStream(@"E:\ExampleNew.txt", FileMode.Open, FileAccess.Read);
Tutorial objnew = (Tutorial)formatter.Deserialize(stream);
Console.WriteLine(objnew.ID);
Console.WriteLine(objnew.Name);
Console.ReadKey();
[Serializable]
public class Tutorial
public int ID;
public string Name;
【讨论】:
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