org.json.JSONArray 类型的值无法转换为 JSONObject
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【中文标题】org.json.JSONArray 类型的值无法转换为 JSONObject【英文标题】:Value of type org.json.JSONArray cannot be converted to JSONObject 【发布时间】:2013-12-13 07:13:09 【问题描述】:遇到这个错误:
3169-3190/com.meisolsson.app E/JSON Parser﹕解析数据时出错 org.json.JSONException: Value ["type":0,"can_see_custom_stories":true,"display":"","name ":"jenniaim","type":0,"can_see_custom_stories":true,"display":"","name":"lucasgardebrand","type":0,"can_see_custom_stories":true," display":"","name":"herr_anderzzon","type":0,"can_see_custom_stories":true,"display":"","name":"chrillebile","type":0 ,"can_see_custom_stories":true,"display":"","name":"meisolsson","type":0,"can_see_custom_stories":true,"display":"","name":"sakanapanda" ,"type":0,"can_see_custom_stories":true,"display":"Team Snapchat","name":"teamsnapchat","type":0,"can_see_custom_stories":true,"display": "","name":"f***lindfors","type":0,"can_see_custom_stories":true,"display":"Katja","name":"katjaawesome","type":0," can_see_custom_stories":true,"display":"","name":"swimkey","type":1,"can_see_custom_stories":true,"display":"","name":"agnesholmberg"] org.json.JSONArray 类型的无法转换为 JSO对象
代码如下:
public class JSONParser extends AsyncTask<Void, Void, Boolean>
static InputStream is = null;
static JSONObject jObj = null;
static String json = "";
// constructor
public JSONParser()
public JSONObject getJSONFromUrl(String url)
// Making HTTP request
try
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("username", LoginActivity.Suser));
nameValuePairs.add(new BasicNameValuePair("password", LoginActivity.Spass));
httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
catch (UnsupportedEncodingException e)
e.printStackTrace();
catch (ClientProtocolException e)
e.printStackTrace();
catch (IOException e)
e.printStackTrace();
try
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null)
sb.append(line + "\n");
is.close();
json = sb.toString();
catch (Exception e)
Log.e("Buffer Error", "Error converting result " + e.toString());
// try parse the string to a JSON object
try
jObj = new JSONObject(json);
catch (JSONException e)
Log.e("JSON Parser", "Error parsing data " + e.toString());
// return JSON String
return jObj;
@Override
protected Boolean doInBackground(Void... params)
getJSONFromUrl("http://flapplabs.se/development/snapchat/friends.php");
return null;
【问题讨论】:
您对异常有什么不明白的地方? 这是一个json数组,里面没有对象所以不能转换 JSON 的东西我很不擅长,谢谢你的帮助 【参考方案1】:[..]
表示应该是JSONArray
,..
表示应该是JSONObject
。
因此:
try
JSONArray jObj = new JSONArray(json);
catch (JSONException e)
Log.e("JSON Parser", "Error parsing data " + e.toString());
【讨论】:
你刚刚救了我的命❤❤ ummuah【参考方案2】:即使我有一个 JSON 对象,它也被存储在一个数组中 Hariharan 用方括号 [ items:items, ... ]
指出我的解决方案是简单地解析出唯一的对象,像这样位于数组位置 [0] 中
JSONArray jsonArray = new JSONArray(stringIn);
JSONObject obj = jsonArray.getJSONObject(0);
【讨论】:
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