我可以获取flask_ngrok或py-ngrok生成的ip地址或域名并返回到127.0.0.1/

Posted 2023-04-18

【中文标题】我可以获取flask_ngrok或py-ngrok生成的ip地址或域名并返回到127.0.0.1/

【英文标题】：Can i get the generated ip-address or domain name of flask_ngrok or py-ngrok and return it to 127.0.0.1/

【发布时间】：2021-02-05 06:17:45

【问题描述】：

我正在尝试在部署后获取 flask_ngrok 或 py-ngrok 生成的域名或 IP 地址。我想将 flask_app 部署到 localhost 并在主页上获取新的 IP 地址或域名。

IE：如果我访问 127.0.0.1/ 我希望它返回类似 您现在可以通过https://aaf8447ee878.ngrok.io/登录

我已尝试检查目录并阅读了一些帮助，但我仍然无法获得它。提前谢谢❤

【问题讨论】：

看看Flask的Request context，然后看看request.host。那是你要找的吗？如果请求来自localhost 或127，则呈现不同的页面。

【参考方案1】：

添加

import atexit
import json
import os
import platform
import shutil
import subprocess
import tempfile
import time
import zipfile
from pathlib import Path
from threading import Timer

import requests


def _run_ngrok():
    ngrok_path = str(Path(tempfile.gettempdir(), "ngrok"))
    _download_ngrok(ngrok_path)
    system = platform.system()
    if system == "Darwin":
        command = "ngrok"
    elif system == "Windows":
        command = "ngrok.exe"
    elif system == "Linux":
        command = "ngrok"
    else:
        raise Exception(f"system is not supported")
    executable = str(Path(ngrok_path, command))
    os.chmod(executable, 777)

    ngrok = subprocess.Popen([executable, 'http', '5000'])
    atexit.register(ngrok.terminate)
    localhost_url = "http://localhost:4040/api/tunnels"  # Url with tunnel details
    time.sleep(1)
    tunnel_url = requests.get(localhost_url).text  # Get the tunnel information
    j = json.loads(tunnel_url)

    tunnel_url = j['tunnels'][0]['public_url']  # Do the parsing of the get
    tunnel_url = tunnel_url.replace("https", "http")
    return tunnel_url


def _download_ngrok(ngrok_path):
    if Path(ngrok_path).exists():
        return
    system = platform.system()
    if system == "Darwin":
        url = "https://bin.equinox.io/c/4VmDzA7iaHb/ngrok-stable-darwin-amd64.zip"
    elif system == "Windows":
        url = "https://bin.equinox.io/c/4VmDzA7iaHb/ngrok-stable-windows-amd64.zip"
    elif system == "Linux":
        url = "https://bin.equinox.io/c/4VmDzA7iaHb/ngrok-stable-linux-amd64.zip"
    else:
        raise Exception(f"system is not supported")
    download_path = _download_file(url)
    with zipfile.ZipFile(download_path, "r") as zip_ref:
        zip_ref.extractall(ngrok_path)


def _download_file(url):
    local_filename = url.split('/')[-1]
    r = requests.get(url, stream=True)
    download_path = str(Path(tempfile.gettempdir(), local_filename))
    with open(download_path, 'wb') as f:
        shutil.copyfileobj(r.raw, f)
    return download_path

def start_ngrok():
    global ngrok_address
    ngrok_address = _run_ngrok()
    print(f" * Running on ngrok_address")
    print(f" * Traffic stats available on http://127.0.0.1:4040")


def run_with_ngrok(app):
    """
    The provided Flask app will be securely exposed to the public internet via ngrok when run,
    and the its ngrok address will be printed to stdout
    :param app: a Flask application object
    :return: None
    """
    old_run = app.run

    def new_run():
        thread = Timer(1, start_ngrok)
        thread.setDaemon(True)
        thread.start()
        old_run()
    app.run = new_run

####################

不要导入 flask_ngrok 最后在 name == 'ma​​in' 之前添加这个函数

def ngrok_url():
    global tunnel_url
    while True:
        try:
            print(ngrok_address)
        except Exception as e:
            print(e)

app.run() 之前和之后

thread = Timer(1, ngrok_url)
thread.setDaemon(True)
thread.start()

并运行警告：如果您不希望在 ngrok url 函数中使用您想要对 url 执行的任何操作替换 print，这将使您的代码编辑器/或终端崩溃

【讨论】：

谢谢，我试试看。

【参考方案2】：

你不需要那个

global tunnel_url
def ngrok_url():
    while True:
        try:
            print(ngrok_address)
        except Exception as e:
                print(e)

您也可以在导入集之后删除 name == 'ma​​in' 之前的线程部分 ngrok_address = '' 然后您可以在代码中的任何位置访问 ngrok_address

【参考方案3】：

我发现最简单的方法是在用户访问网站时复制 url。你可以这样做...

@app.before_request
def before_request():
    global url
    url = request.url
    # url = url.replace('http://', 'https://', 1)
    url = url.split('.ngrok.io')[0]
    url += '.ngrok.io'