QMenu mousePressEvent 阻碍了 QAction 切换
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【中文标题】QMenu mousePressEvent 阻碍了 QAction 切换【英文标题】:QAction toggling is hinder by QMenu mousePressEvent 【发布时间】:2019-04-03 01:00:23 【问题描述】:我有一个嵌套的菜单项,我试图在其中使所有项都可以检查。最初,切换不适用于主项目(设置为 QAction 的 QMenu),而它适用于子项目。
但是在使用mousePressEvent
时,切换现在适用于主要项目,但不适用于子项目。
试图复制我为子项目功能的主要项目所做的事情,但切换仍然不起作用。看起来,它在_callActionItem()
中被调用了两次。
但是,由于某些原因,如果子项目窗口处于撕下模式,则可以切换,但如果您在工具本身中执行右键单击菜单,则不能切换。
此外,如果我在 QCustomMenu
中禁用 mousePressEvent
,我将回到第一格,其中切换适用于子项目,但不适用于主项目
class QSubAction(QtGui.QAction):
def __init__(self, text="", parent=None):
super(QSubAction, self).__init__(text, parent)
self.setCheckable(True)
self.setChecked(True)
class QAddAction(QtGui.QAction):
def __init__(self, icon=None, text="Add Item", parent=None):
if icon:
super(QAddAction, self).__init__(icon, text, parent)
else:
super(QAddAction, self).__init__(text, parent)
class QCustomMenu(QtGui.QMenu):
"""Customized QMenu."""
def __init__(self, title, parent=None):
super(QCustomMenu, self).__init__(title=str(title), parent=parent)
self.setup_menu()
def mousePressEvent(self, event):
action = self.activeAction()
if isinstance(action, QtGui.QAction):
action.trigger()
return QtGui.QMenu.mousePressEvent(self, event)
def setup_menu(self):
self.setContextMenuPolicy(QtCore.Qt.DefaultContextMenu)
def contextMenuEvent(self, event):
no_right_click = [QAddAction]
if any([isinstance(self.actionAt(event.pos()), instance) for instance in no_right_click]):
return
pos = event.pos()
def addAction(self, action):
super(QCustomMenu, self).addAction(action)
class Example(QtGui.QMainWindow):
def __init__(self, parent=None):
super(Example, self).__init__(parent)
self.initUI()
def initUI(self):
self.setGeometry(300, 300, 300, 200)
self.setWindowTitle('Context menu')
self.qmenu = QCustomMenu(title='', parent=self)
add_item_action = QtGui.QAction('Add Main item', self,
triggered=self.add_new_item)
self.qmenu.addAction(add_item_action)
def contextMenuEvent(self, event):
action = self.qmenu.exec_(self.mapToGlobal(event.pos()))
def add_new_item(self):
main_menu_name, ok = QtGui.QInputDialog.getText(
self,
'Main Menu',
'Name of new Menu Item:'
)
if ok:
self._addMenuItemTest(main_menu_name)
def _addMenuItemTest(self, main_menu_name):
icon_path = '/user_data/add.png'
base_qmenu = QCustomMenu(title=main_menu_name, parent=self)
base_qmenu.setTearOffEnabled(True)
add_item_action = QAddAction(None, 'Add Sub Item', base_qmenu)
slot = functools.partial(self.add_sub_item, base_qmenu)
add_item_action.triggered.connect(slot)
base_qmenu.addAction(add_item_action)
test_action = QtGui.QAction(main_menu_name, self)
test_action.setMenu(base_qmenu)
test_action.setCheckable(True)
test_action.setChecked(True)
self.connect(
test_action,
QtCore.SIGNAL("triggered(bool)"),
self.main_toggling
)
self.qmenu.addAction(test_action)
def main_toggling(self, check_state):
sender_obj = self.sender()
if isinstance(sender_obj, QtGui.QAction):
sender_obj.setChecked(check_state)
def add_sub_item(self, base_menu):
sub_menu_name, ok = QtGui.QInputDialog.getText(
self,
'Sub Menu',
'Name of new Sub Item:'
)
if ok:
action = QSubAction(sub_menu_name, self)
slot = functools.partial(
self._callActionItem,
action
)
# action.toggled.connect(slot)
# from pprint import pprint
# pprint(help(action))
# action.connect(action, QtCore.SIGNAL("triggered(bool)"), self._callActionItem)
base_menu.addAction(action)
def _callActionItem(self, action):
# This is called twice, False and True again
print '>>> sub check-state : ', action.isChecked()
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
window = Example()
window.show()
sys.exit(app.exec_())
【问题讨论】:
【参考方案1】:默认情况下,QMenu 只会使没有子项的 QAction 可以检查,因此您已经做了一个技巧来启用另一个不符合上述可能影响操作的 QAction 的功能,这就是您的情况。解决方法是区分按下的是哪种类型的QAction:
def mousePressEvent(self, event):
action = self.activeAction()
if not isinstance(action, QSubAction) and action is not None:
action.trigger()
return
return QtGui.QMenu.mousePressEvent(self, event)
【讨论】:
抱歉,评论有点晚了,但我想了解为什么action
会返回两次——一次是QSubAction
和None
。尤其是None
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