获取联系人姓名？

Posted 2023-04-15

【中文标题】获取联系人姓名？

【英文标题】：Get contact name?

【发布时间】：2016-05-07 23:23:32

【问题描述】：

我想获取联系人姓名，但无法获取。在查看this answer 之后，我尝试使用family、given 和display 来获取名称，但没有任何效果

  @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) 
        if (requestCode == PICK_CONTACT && resultCode == RESULT_OK) 
            Uri contactUri = data.getData();
            Cursor cursor = getContentResolver().query(contactUri, null, null, null, null);
            cursor.moveToFirst(); //Move to first row...I actually dont know why this part is necessary, but I get an error without it... 
            int NumberColumn = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER); //Int column is the column of the numbers
            int NameColumn = cursor.getColumnIndex(ContactsContract.CommonDataKinds.StructuredName.GIVEN_NAME);
            String contactNumber = cursor.getString(NumberColumn);
            String contactName = cursor.getString(NameColumn);
            Toast.makeText(MainActivity.this, ""+ contactNumber +"" +contactName, Toast.LENGTH_SHORT).show();

        

/

public void addContact(View v) //OnClick listener to launch contact picker
    Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.CommonDataKinds.Phone.CONTENT_URI);
    startActivityForResult(intent, PICK_CONTACT);

【参考方案1】：

尝试以下代码以获取特定号码的联系方式

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) 
    super.onActivityResult(requestCode, resultCode, data);

    if (requestCode == REQUEST_CODE_PICK_CONTACTS && resultCode == RESULT_OK) 
        Log.d(TAG, "Response: " + data.toString());
        uriContact = data.getData();

        retrieveContactName();

    


 private void retrieveContactName() 

        String contactName = null;

        // querying contact data store
        Cursor cursor = getContentResolver().query(uriContact, null, null, null, null);

        if (cursor.moveToFirst()) 

            // DISPLAY_NAME = The display name for the contact.
            // HAS_PHONE_NUMBER =   An indicator of whether this contact has at least one phone number.

            contactName = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
        

        cursor.close();

        Log.d(TAG, "Contact Name: " + contactName);

    

更多详情请参考以下链接https://tausiq.wordpress.com/2012/08/23/android-get-contact-details-id-name-phone-photo/

【讨论】：

为什么是if (cursor.moveToFirst()) ？谢谢]

我认为我们只有一个条目，这就是我们使用光标 movetofirst 的原因。首先它会检查光标是否为空，如果不是，它将返回数据

你能得到电话号码的名字吗？

否，因为它与我在问题中提供的代码相同。

你查过号码有名字吗？