在 sqlite 数据库中创建表时出现语法错误

Posted 2023-04-15

【中文标题】在 sqlite 数据库中创建表时出现语法错误

【英文标题】：syntax error in creat table in sqlite database

【发布时间】：2018-07-25 13:12:07

【问题描述】：

我不知何故无法创建表。我检查了我的语法并搜索了其他有相同错误的人，但我找不到错误是什么。我使用相同的语法来创建所有表，但只是 stuff 表有问题。即使我将数据库版本更改为 2 和几次卸载我的应用程序。我在这里放了一部分代码。

public class Stuff 
//*****DataBase query*****/
public static final String TABLE_NAME = "stuff";
public static final String CLM_ID = "id";
public static final String CLM_NAME = "name";
public static final String CLM_PRICE = "price";
public static final String CLM_DESCRIPTION = "description";
public static final String CLM_BRAND = "brand";
public static final String CLM_MODEL = "model";
public static final String CLM_COUNT = "count";
public static final String CLM_COLOR = "color";
public static final String CLM_CATGID = "catgid";

public static final String SQL_DROP_TABLE = String.format("DROP TABLE %s", TABLE_NAME);
public static final String SQL_CREATE_TABLE = String.format("CREATE TABLE IF NOT EXISTS %s (" +
        "%s INTEGER PRIMARY KEY," +
        "%s TEXT," +
        "%s REAL," +
        "%s TEXT NOT NULL," +
        "%s TEXT NOT NULL," +
        "%s TEXT," +
        "%s INTEGER," +
        "%s TEXT NOT NULL," +
        "FOREIGN KEY (%s) REFERENCES(%s)" +
        ");", TABLE_NAME, CLM_ID, CLM_NAME,CLM_PRICE,CLM_DESCRIPTION,CLM_BRAND,CLM_MODEL,CLM_COUNT,CLM_COLOR,CLM_CATGID,Category.TABLE_NAME);

public class DBHelper extends SQLiteOpenHelper 
  private static DBHelper helper;
private static SQLiteDatabase database;

public static final String DATA_BASE_NAME = "dbDigikala";
public static final int DATA_BASE_VERSION = 1;

public static SQLiteDatabase getDatabase(Context context) 
    return getInstance(context).getWritableDatabase();


public static DBHelper getInstance(Context context) 
    if (helper == null) 
        helper = new DBHelper(context, DATA_BASE_NAME, null, DATA_BASE_VERSION);
    
    return helper;


public DBHelper(Context context, String name, SQLiteDatabase.CursorFactory factory, int version) 
    super(context, name, factory, version);

@Override
public void onCreate(SQLiteDatabase db) 
    db.execSQL(Category.SQL_CREATE_TABLE);
    db.execSQL(Stuff.SQL_CREATE_TABLE);
    db.execSQL(Rate.SQL_CREATE_TABLE);
    db.execSQL(Favorit.SQL_CREATE_TABLE);
    db.execSQL(Image.SQL_CREATE_TABLE);
    db.execSQL(Video.SQL_CREATE_TABLE);
    db.execSQL(Address.SQL_CREATE_TABLE);
    db.execSQL(User.SQL_CREATE_TABLE);
    db.execSQL(Comment.SQL_CREATE_TABLE);
    db.execSQL(Factor.SQL_CREATE_TABLE);
    db.execSQL(SoldStuff.SQL_CREATE_TABLE);
    db.execSQL(Slake.SQL_CREATE_TABLE);
    db.execSQL(SlakeStuff.SQL_CREATE_TABLE);
    db.execSQL(SlakeUser.SQL_CREATE_TABLE);

@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion)    
    db.execSQL(Category.SQL_DROP_TABLE);
    db.execSQL(Stuff.SQL_DROP_TABLE);
    db.execSQL(Rate.SQL_DROP_TABLE);
    db.execSQL(Favorit.SQL_DROP_TABLE);
    db.execSQL(Image.SQL_DROP_TABLE);
    db.execSQL(Video.SQL_DROP_TABLE);
    db.execSQL(Address.SQL_DROP_TABLE);
    db.execSQL(User.SQL_DROP_TABLE);
    db.execSQL(Comment.SQL_DROP_TABLE);
    db.execSQL(Factor.SQL_DROP_TABLE);
    db.execSQL(SoldStuff.SQL_DROP_TABLE);
    db.execSQL(Slake.SQL_DROP_TABLE);
    db.execSQL(SlakeStuff.SQL_DROP_TABLE);
    db.execSQL(SlakeUser.SQL_DROP_TABLE);
    onCreate(db);
  


public class Config extends Application 
public static Context context;
public static Activity currentActivity;
public static final long SPLASH_DELAY = 2000;
public static SQLiteDatabase database;
@Override
public void onCreate() 
    super.onCreate();
    context = getApplicationContext();
    database = DBHelper.getDatabase(getApplicationContext());

【问题讨论】：

这会是问题吗？看起来外键还没有定义？ You have to define your column first and then set foreign key on it.

请不要发布代码、XML 或 logcat 输出的屏幕截图。请将所有文本作为文本发布。

【参考方案1】：

问题在于您设置 ForeignKey "FOREIGN KEY (%s) REFERENCES(%s)"。 更新您的代码如下：

public static final String SQL_CREATE_TABLE = String.format("CREATE TABLE IF NOT EXISTS %s (" +
        "%s INTEGER PRIMARY KEY," +
        "%s TEXT," +
        "%s REAL," +
        "%s TEXT NOT NULL," +
        "%s TEXT NOT NULL," +
        "%s TEXT," +
        "%s INTEGER," +
        "%s TEXT NOT NULL," +
        "FOREIGN KEY (%s) REFERENCES %s(%s)" +
        ");", TABLE_NAME, CLM_ID, CLM_NAME,CLM_PRICE,CLM_DESCRIPTION,CLM_BRAND,CLM_MODEL,CLM_COUNT,CLM_COLOR,CLM_CATGID,Category.TABLE_NAME,Category.CLM_ID);

您仅传递表名并将其设置在错误的位置。

"FOREIGN KEY (%s) REFERENCES %s(%s)"

REFERENCES 之后的第一个 %s 是表名，第二个 (%s) 是您在类别表中的列 id。

【讨论】：

我这样做了，但我的应用程序给了我同样的错误。我认为问题来自其他地方。例如dBHelper 类。

类别表中的 id（主键）是什么？您最后必须传递该列名而不是 Category.CLM_ID。并尝试清除数据并安装一次最新版本。

Category 表的主键是 That's what you write (Category.CLM_ID)。我也清除数据。

试试这个"FOREIGN KEY (%s) REFERENCES %s(%s)"删除%s后的空格

很高兴为您提供帮助！！

【参考方案2】：

子句REFERENCES必须使用语法：REFERENCES table_name(column_id):

public static final String SQL_CREATE_TABLE = String.format("CREATE TABLE IF NOT EXISTS %s (" +
        "%s INTEGER PRIMARY KEY," +
        "%s TEXT," +
        "%s REAL," +
        "%s TEXT NOT NULL," +
        "%s TEXT NOT NULL," +
        "%s TEXT," +
        "%s INTEGER," +
        "%s TEXT NOT NULL," +
        "FOREIGN KEY (%s) REFERENCES %s(%s)" +
        ");", TABLE_NAME, CLM_ID, CLM_NAME,CLM_PRICE,CLM_DESCRIPTION,CLM_BRAND,CLM_MODEL,CLM_COUNT,CLM_COLOR,CLM_CATGID,Category.TABLE_NAME,Category.CLM_ID);