对于以下场景，如何在 oracle sql 中执行类似 unpivot 的操作？

Posted 2023-04-12

【中文标题】对于以下场景，如何在 oracle sql 中执行类似 unpivot 的操作？

【英文标题】：How to do something like unpivot like in oracle sql for the following scenario?

【发布时间】：2020-10-05 14:56:29

【问题描述】：

这是表格语句，我想将数据转换为非透视数据，比如只使用 sql。

create table galy(
pro_Date date,
profit number
);
insert into galy values(sysdate-1,30);
insert into galy values(sysdate,20);
insert into galy values(sysdate+1,40);
insert into galy values(sysdate+2,50);
insert into galy values(sysdate+3,70);
commit;

在单个查询中需要输出（不应考虑包含周六和周日的日期）

      Date                  d-1                    d                d+1
    01-02-2018(sysdate)      30                    20                40
     ....
     ....

【参考方案1】：

无需数据透视/取消透视即可以您想要的格式显示数据。只要每天只有1个PRO_DATE，就可以使用LEAD和LAG解析函数。

查询

SELECT pro_date,
       LAG (profit) OVER (ORDER BY pro_date)     AS prior_day_profit,
       profit                                    AS current_day_profit,
       LEAD (profit) OVER (ORDER BY pro_date)     AS next_day_profit
  FROM galy;

结果

    PRO_DATE    PRIOR_DAY_PROFIT    CURRENT_DAY_PROFIT    NEXT_DAY_PROFIT
____________ ___________________ _____________________ __________________
04-OCT-20                                           30                 20
05-OCT-20                     30                    20                 40
06-OCT-20                     20                    40                 50
07-OCT-20                     40                    50                 70
08-OCT-20                     50                    70

更新

要排除周末，您只需在查询中添加 where 子句

SELECT pro_date,
       LAG (profit) OVER (ORDER BY pro_date)      AS prior_day_profit,
       profit                                     AS current_day_profit,
       LEAD (profit) OVER (ORDER BY pro_date)     AS next_day_profit
  FROM galy
 WHERE TO_CHAR (pro_date, 'DY') NOT IN ('SAT', 'SUN');