使用 EclipseLink 的 H2 数据库出现问题(即使没有错误,程序也不会更改数据库)
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【中文标题】使用 EclipseLink 的 H2 数据库出现问题(即使没有错误,程序也不会更改数据库)【英文标题】:Problem with H2 Database using EcipseLink (Program doesnt change database even without a error) 【发布时间】:2018-09-25 08:36:19 【问题描述】:所以...我刚开始使用数据库,我的兄弟建议我使用带有 EclipseLink 的 H2 来开始。快速谷歌搜索并找到一个教程:
https://www.javatips.net/blog/eclipselink-jpa-with-h2-database
https://www.javatips.net/blog/java-persistence-jpa-2-0-tutorial-with-eclipselink
如果我按照教程中描述的方式对其进行编码,我在运行它时不会出错,但我检查了数据库,我的表仍然是空的。我现在搜索了大约一个星期,但我没有找到答案。
我的代码:
同学
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;
@Entity
@Table(name = "STUDENT")
public class Student implements java.io.Serializable
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "STUDENTID")
private long studentId;
@Column(name = "STUDENTNAME")
private String studentName;
public void setStudentId(long studentId)
this.studentId = studentId;
public long getStudentId()
return studentId;
public void setStudentName(String studentName)
this.studentName = studentName;
public String getStudentName()
return studentName;
JPA 示例
import java.util.Iterator;
import java.util.List;
import javax.persistence.EntityManager;
public class JPAExample
private EntityManager entityManager = EntityManagerUtil.getEntityManager();
public static void main(String[] args)
JPAExample example = new JPAExample();
System.out.println("After Sucessfully insertion ");
Student student1 = example.saveStudent("Sumith");
Student student2 = example.saveStudent("Anoop");
example.listStudent();
System.out.println("After Sucessfully modification ");
example.updateStudent(student1.getStudentId(), "Sumith Honai");
example.updateStudent(student2.getStudentId(), "Anoop Pavanai");
example.listStudent();
System.out.println("After Sucessfully deletion ");
example.deleteStudent(student2.getStudentId());
example.listStudent();
public Student saveStudent(String studentName)
Student student = new Student();
try
entityManager.getTransaction().begin();
student.setStudentName(studentName);
student = entityManager.merge(student);
entityManager.getTransaction().commit();
catch (Exception e)
entityManager.getTransaction().rollback();
return student;
public void listStudent()
try
entityManager.getTransaction().begin();
@SuppressWarnings("unchecked")
List<Student> Students = entityManager.createQuery("from Student").getResultList();
for (Iterator<Student> iterator = Students.iterator(); iterator.hasNext();)
Student student = (Student) iterator.next();
System.out.println(student.getStudentName());
entityManager.getTransaction().commit();
catch (Exception e)
entityManager.getTransaction().rollback();
public void updateStudent(Long studentId, String studentName)
try
entityManager.getTransaction().begin();
Student student = (Student) entityManager.find(Student.class, studentId);
student.setStudentName(studentName);
entityManager.getTransaction().commit();
catch (Exception e)
entityManager.getTransaction().rollback();
public void deleteStudent(Long studentId)
try
entityManager.getTransaction().begin();
Student student = (Student) entityManager.find(Student.class, studentId);
entityManager.remove(student);
entityManager.getTransaction().commit();
catch (Exception e)
entityManager.getTransaction().rollback();
EntityManagerUtil
import javax.persistence.EntityManager;
import javax.persistence.EntityManagerFactory;
import javax.persistence.Persistence;
public class EntityManagerUtil
private static final EntityManagerFactory entityManagerFactory;
static
try
entityManagerFactory = Persistence.createEntityManagerFactory("test");
catch (Throwable ex)
System.err.println("Initial SessionFactory creation failed." + ex);
throw new ExceptionInInitializerError(ex);
public static EntityManager getEntityManager()
return entityManagerFactory.createEntityManager();
Persistence.xml
<persistence xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
version="2.0" xmlns="http://java.sun.com/xml/ns/persistence">
<persistence-unit name="test" transaction-type="RESOURCE_LOCAL">
<class>Student</class>
<properties>
<property name="javax.persistence.jdbc.driver" value="org.h2.Driver" />
<property name="javax.persistence.jdbc.url" value="jdbc:h2:~/test" />
<property name="javax.persistence.jdbc.user" value="sa" />
<property name="javax.persistence.jdbc.password" value="" />
<property name="eclipselink.ddl-generation" value="create-tables"/>
<property name="eclipselink.ddl-generation.output-mode" value="database" />
</properties>
</persistence-unit>
当我运行 JPAExample 时,我得到以下输出: My Output
但预期的输出应如下所示: Expected Output
如果我查看 H2 数据库,一切都没有改变: H2 Database Interface (German Language)
希望有人可以帮助我或者可以链接我一个有用/更好的 JPA 教程 :)
【问题讨论】:
我假设您遇到了异常。请在插入、更新和删除方法中记录异常。 【参考方案1】:您正在捕获异常但没有确认或记录它们 - 您应该确保至少记录它。
在这种情况下,您的 listStudent 方法在
上遇到异常 entityManager.createQuery("from Student").getResultList()
因为这是一个无效的 JPQL 查询。你应该使用类似的东西:
entityManager.createQuery("select s from Student s").getResultList()
【讨论】:
好吧,我改变了查询,我得到了正确的输出,但是在 H2 接口中没有任何改变 检查您的连接方式,以及它是否与“~/test”相同的数据库是用户特定的。 h2database.com/html/tutorial.html#creating_new_databases以上是关于使用 EclipseLink 的 H2 数据库出现问题(即使没有错误,程序也不会更改数据库)的主要内容,如果未能解决你的问题,请参考以下文章
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