列索引超出范围：1，列数：0

Posted 2023-03-31

【中文标题】列索引超出范围：1，列数：0

【英文标题】：The column index is out of range: 1, number of columns: 0

【发布时间】：2016-08-02 12:40:20

【问题描述】：

我更新了 UPSERT_DELETE_JOB_COUNTERS。 现在我认为“upsert”适用于新的查询 =) 或者你怎么看？

问候， 彼得

`private static final String UPSERT_DELETE_JOB_COUNTERS =
        "UPDATE rating.delete_job_counters SET delete_count = delete_count + ? WHERE fee_group_id = ? AND delete_job_id = ?; "+
        "INSERT INTO  rating.delete_job_counters(delete_job_id, fee_group_id, delete_count ) "+
        "SELECT ?, ? , ? " +
        "WHERE NOT EXISTS (SELECT 1 FROM rating.delete_job_counters  WHERE fee_group_id = ? AND delete_job_id = ?); ";

@Override
public Boolean insertIntoDeleteStatistic(final CachedRowSet deletedEntries,
                                      Long deleteJobId,
                                      Transaction transaction) throws SQLException 
    boolean finish = true;
    if (deletedEntries.size() == 0) 
        return finish;
    
    final Connection connection = transaction.getConnection();
    final Timer executeTimer = Timer.start("Insert took ");
    try 
        PreparedStatement pstmt = connection.prepareStatement(UPSERT_DELETE_JOB_COUNTERS);
        while (deletedEntries.next()) 
            pstmt.setInt(1, deletedEntries.getInt(2));
            pstmt.setInt(2, deletedEntries.getInt(1));
            pstmt.setLong(3, deleteJobId);
            pstmt.setLong(4, deleteJobId);
            pstmt.setInt(5, deletedEntries.getInt(1));
            pstmt.setInt(6, deletedEntries.getInt(2));
            pstmt.setInt(7, deletedEntries.getInt(1));
            pstmt.setInt(8, deletedEntries.getInt(2));
            pstmt.execute();
        ...

`

【问题讨论】：

我相信deleteCdr.getInt(2)是问题的原因。你确定这个缓存的结果集实际上有两列可用吗？

与您的问题没有直接关系，但您需要关闭Statement 和Connection。考虑try-with-resources。

` 更新 rating.delete_job_counters SET delete_count = delete_count + ?在哪里 fee_group_id = ？和 delete_job_id = ?;插入到 rating.delete_job_counters(delete_job_id, fee_group_id, delete_count) SELECT ?, ? , ?不存在的地方（从 rating.delete_job_counters 中选择 1，其中 fee_group_id = ？和 delete_job_id = ？）； ` 这个查询好吗？我的第一次测试是阳性的。

【参考方案1】：

您不能将参数化的java.sql.PreparedStatement 与DO 语句一起使用。

为什么不使用INSERT ... ON CONFLICT DO UPDATE（从 PostgreSQL 9.5 开始可用）？

对于旧版本的 PostgreSQL，您可能必须编写一个“无限循环”，如以下伪代码示例：

while (1) 
   INSERT ...
   if (insert went ok) break;
   UPDATE ...
   if (update changed one row) break;

【讨论】：

我们有 PostgresSql 9.4 =( 你有别的想法吗？

我已经编辑了答案；我想这是你唯一的选择。