在单个查询中评估特定的分组值?
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【中文标题】在单个查询中评估特定的分组值?【英文标题】:Evaluate specific grouped values in a single query? 【发布时间】:2012-03-30 05:45:29 【问题描述】:我有一个书籍数据库,其中包含与书籍相关的类别和标签。我正在尝试构建一个过滤器,让用户可以过滤多个类别或标签,并查看具有这些标签或类别的书籍。它适用于单个类别或标签,但如果由于按图书 ID 分组而存在多个标签或类别,它就会崩溃。
SELECT books.id as id,title, sub_title,medium_image_url,
amzn_url,amzn_review as review,SUBSTRING(kindle_price,2) as price,
IFNULL(ROUND(combined_ratings.love/(combined_ratings.love+combined_ratings.hate)*100), 0) AS rating ,
categories.category as category,GROUP_CONCAT(DISTINCT categories.id SEPARATOR ", ") as all_cats
FROM books
JOIN combined_ratings ON books.id = combined_ratings.book_id JOIN book_categories ON books.id = book_categories.book_id
JOIN categories ON book_categories.category_id = categories.id
WHERE (SUBSTRING(kindle_price,2) >= 0
AND SUBSTRING(kindle_price,2) <= 12
AND kindle_price <> "")
AND (IFNULL(ROUND(combined_ratings.love/(combined_ratings.love+combined_ratings.hate)*100), 0) >= 0
AND IFNULL(ROUND(combined_ratings.love/(combined_ratings.love+combined_ratings.hate)*100), 0) <= 100)
GROUP BY id
ORDER BY price ASC, rating DESC
我尝试过使用 GROUP_CONCAT 和 HAVING,我刚刚阅读了有关 IN() 的信息,但我尝试过,但它不起作用。我现在真正需要做的就是对其执行 IN() 之类的操作,有什么建议吗?
编辑:我使用它并且能够获得单个类别的结果,但它只能工作一次...... 这行得通...
AND FIND_IN_SET( categories.id, '6' ) > 0
这不是
AND FIND_IN_SET( categories.id, '6' ) > 0 AND FIND_IN_SET( categories.id, '5' ) > 0
如果我可以让它工作,它就解决了我的问题。
【问题讨论】:
【参考方案1】:不久前有 *** 帖子。请check it out。 另一种方法是每次创建临时表并将所有标签和类别放在那里,然后进行连接。
【讨论】:
我尝试按照您准确链接的帖子的答案进行操作,但它不起作用。我在 mysql 中遇到各种错误。我也不确定如何按照您的建议创建临时表。【参考方案2】:我放弃了尝试单独使用 JOIN 并使用子查询。这对我有用,可能并不理想,但我现在可以根据需要过滤尽可能多的标签或类别。
SELECT id, title, author, image, sub_title, price, SUM(count) as count, rating FROM
(
SELECT books.id as id, title, author, medium_image_url as image, sub_title, kindle_price as price, IFNULL(ROUND(combined_ratings.love/(combined_ratings.love+combined_ratings.hate)*100), 0) as rating , COUNT( DISTINCT category_id ) AS count
FROM book_categories
JOIN books ON book_categories.book_id = books.id
JOIN authors ON books.author_id = authors.id
JOIN combined_ratings ON books.id = combined_ratings.book_id
WHERE category_id = 5
OR category_id = 6
OR category_id = 12
GROUP BY book_categories.book_id
HAVING count >= 3
UNION ALL
SELECT books.id as id, title, author, medium_image_url as image, sub_title, kindle_price as price, IFNULL(ROUND(combined_ratings.love/(combined_ratings.love+combined_ratings.hate)*100), 0) as rating , COUNT( DISTINCT tag_id ) AS count
FROM book_tags JOIN books ON book_tags.book_id = books.id
JOIN authors ON books.author_id = authors.id
JOIN combined_ratings ON books.id = combined_ratings.book_id
WHERE book_tags.tag_id = 22
GROUP BY book_tags.book_id HAVING count >= 1
)
as b1
WHERE (SUBSTRING(price,2) >= 0
AND SUBSTRING(price,2) <= 20 AND price <> '')
AND (rating >= 0 AND rating <= 100)
GROUP BY id
HAVING count = 4
ORDER BY price ASC,
rating DESC
这是通过检查任何条件是否存在任何结果,然后计算条件匹配的数量来实现的。在外部查询中,我将两个联合查询相加,并确定这些计数的 SUM() 是否与参数总数匹配。
【讨论】:
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